I am trying to convert the bigint value to date in PostgreSQL
I am using the below code
SELECT TO_CHAR(TO_TIMESTAMP(1564983632051/ 1000),
'YYYY-MM-DD HH24:MI:SS')
then its returning 2019-08-05 07:40:32, which is correct.
However i want to add few hours to it to get local time. Tried with the following query but its throwing an error :
SELECT TO_CHAR(TO_CHAR(TO_TIMESTAMP(1564983632051/ 1000),
'YYYY-MM-DD HH24:MI:SS') + INTERVAL '4 hour')
I do not want to use a separate query, if that's the case i can use
select (to_timestamp('2019-08-05 07:40:32', 'YYYY-MM-DD HH24:MI:SS.US') + interval '4 hour')::timestamp;
this will return the desired output.
I need both conversion and hours addition in a single query.
You should add to TIMESTAMP portion, not to portion casted to CHAR :
SELECT TO_CHAR(
TO_TIMESTAMP(1564983632051/ 1000)+ INTERVAL '4 hour',
'YYYY-MM-DD HH24:MI:SS'
)
The problem is here:
select pg_typeof(TO_CHAR(TO_TIMESTAMP(1564983632051/ 1000), 'YYYY-MM-DD HH24:MI:SS'));
pg_typeof
-----------
text
Adding an interval to a text value is not going to work.
So something like:
select TO_CHAR(TO_TIMESTAMP(1564983632051/1000) + interval '4 hour', 'YYYY-MM-DD HH24:MI:SS') ;
to_char
---------------------
2019-08-05 02:40:32
It is best to stay in a type for operations until the very end. Then apply formatting.
Related
I would like to add, for example, 8 hours to the enddate in a 24 hour format.
I tried adding + 8/24, 'DD-MM-YYYY HH24:MI:SS' on the first line but this gives an error.
This is my query thus far.
SELECT to_char(IN_ENDDATE, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL;
Your first line converts a date to a string. You cannot then add 8/24 to it. Do the addition before the conversion:
SELECT to_char(IN_ENDDATE + 8/24.0, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL;
IN_ENDDATE really does need to be a date type to allow +8/24 to work. If it's a timestamp, add it as an interval:
IN_ENDDATE + INTERVAL '8' HOUR
This form might be safer to use for a couple of reasons:
it works on both date and timestamps
it's more readable
If IN_ENDDATE is a non-date type (eg varchar) then your query works without the +8/24 because it is being successfully implicitly converted from varchar to date, before being passed to to_char. In this case either be explicit about your conversion:
SELECT to_char(to_date(IN_ENDDATE, 'YYMMDD WHATEVER') + 8/24.0, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL
SELECT to_char(to_date(IN_ENDDATE, 'YYMMDD WHATEVER') + INTERVAL '8' HOUR, 'DD-MM-YYYY HH24:MI:SS')
INTO IN_END_DATE_STRING
FROM DUAL
Or set your IN_ENDDATE parameter to really be a date type
i am trying to work with timestamps and manipulate the data out of them so i can measure different things in our database.
currently i have a column that holds a "DATE" but in fact contains a whole stamp 'DD/MM/YYYY HH24:MI:SS'
i want to be able to grab all entries where "DTIME" between "09:00" and "09:15" however have not been able to cast it correctly.
If i was to output the column without any conversion it would look like this
SELECT ia.DTIME3
FROM ISIS_AUDIT ia
WHERE ia.DTIME3 like to_date('24/01/2019', 'DD/MM/YYYY');
OUTPUT: 24/JAN/19
if i was to convert it to_char,
SELECT to_char(ia.DTIME3, 'DD/MM/YYYY HH24:MI:SS')
FROM ISIS_AUDIT ia
WHERE ia.DTIME3 like to_date('24/01/2019', 'DD/MM/YYYY');
OUTPUT: 24/01/2019 07:10:52
I want to be able to take this DTIME3 and find entries between the times but CAST and CONVERT to TIME doesnt work.
This is my working option but it outputs the date still and i dont want to have to specify the date so it can be run across any day of the week.
WHERE ia.DTIME3 between to_date('24/01/2019 09:00:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('24/01/2019 09:15:00', 'DD/MM/YYYY HH24:MI:SS');
OUTPUT: 24/01/2019 09:00:01
currently i have a column that holds a "DATE" but in fact contains a whole stamp 'DD/MM/YYYY HH24:MI:SS'
That's what Oracle DATE datatype does : storing a date and time (without fractional seconds, that belong to the TIMESTAMP datatypes). There is no specific format in Oracle for date only (without time).
To filter on the time of the day, you can use the TO_CHAR() function to convert your date to a string that represents its time, and that you can compare :
TO_CHAR(ia.DTIME3, 'hh24:mi') BETWEEN '09:00' AND '09:14'
You can also CAST the date to a timestamp and use the EXTRACT() function :
EXTRACT(HOUR FROM CAST(ia.DTIME3 AS TIMESTAMP)) = 9
AND EXTRACT(MINUTE FROM CAST(ia.DTIME3 AS TIMESTAMP)) < 15
Oracle has DATE and TIMESTAMP data types; both have year, month, day, hour, minute, second components (TIMESTAMP also has fractional seconds). Oracle does not have a TIME data type.
Instead, use TRUNC() to truncate the time component to midnight and add an interval literal:
SELECT *
FROM ISIS_AUDIT
WHERE DTIME BETWEEN TRUNC( DTIME ) + INTERVAL '09:00' HOUR TO MINUTE
AND TRUNC( DTIME ) + INTERVAL '09:15' HOUR TO MINUTE;
and ia.DTIME1 not between to_date('&&S_DATE 08:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 09:20:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME1 not between to_date('&&S_DATE 11:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 12:40:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME3 not between to_date('&&S_DATE 08:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 09:20:00', 'DD/MM/YYYY HH24:MI:SS')
and ia.DTIME3 not between to_date('&&S_DATE 11:50:00', 'DD/MM/YYYY HH24:MI:SS') and to_date('&&S_DATE 12:40:00', 'DD/MM/YYYY HH24:MI:SS')
i was trying to do this way however i noticed if i have a start time of 08:30 and a finish time of 09:30 then it falls between 09:00 and 09:15 so i want to exclude it from the table. the current WHERE clause im using is quite specific and will only exclude if the timestamp contains the values specified.
Really it would want to read "DTIME1 to DTIME3 not between 09:00 and 09:15"
I want to find rows in my database which have a timestamp within the last complete minute.
For example:
When it is 12:02:43 --> from 12:01:00 to 12:01:59 (inclusive)
When it is 14:01:00 --> from 14:00:00 to 14:00:59 (inclusive)
When it is 16:24:59 --> from 16:23:00 to 16:23:59 (inclusive)
I found the following statement.
select *
from table
where time < to_date(to_char(sysdate, 'DD.MM.YYYY HH24:MI'), 'DD.MM.YYYY HH24:MI')
and time >= to_date(to_char(sysdate - numtodsinterval(1, 'Minute'), 'DD.MM.YYYY HH24:MI'), 'DD.MM.YYYY HH24:MI')
The statement works, but converting the date to a string and then back to a date seems a little weird. Is there any other method to use only minutes as precision (without seconds)?
Oracle-specific functions could be used, but I'd prefer a standard SQL way.
You can use TRUNC(SYSDATE,'MI') -> TRUNC('12:02:43','MI') = 12:02.
Or you can use this select extract(MINUTE from current_timestamp) from dual;
You can truncate timestamps (and dates) to the nearest minute - so you can use TRUNC( SYSTIMESTAMP, 'MI' ) to round to the start of the current minute and subtract INTERVAL '1' MINUTE to get the start of the previous minute:
select *
from table_name
where time >= TRUNC( SYSTIMESTAMP, 'MI' ) - INTERVAL '1' MINUTE
and time < TRUNC( SYSTIMESTAMP, 'MI' )
You are right, converting it to string an back seems unnecessary. I'd leave it as a date. How about:
SELECT *
FROM t
WHERE t BETWEEN TRUNC(SYSDATE,'MI')
AND TRUNC(SYSDATE,'MI')+1/24/60/60*59;
TRUNC(...,'MI') chops of the seconds, for instance
SELECT trunc(sysdate,'MI'), TRUNC(SYSDATE,'MI')+1/24/60/60*59 from dual;
returns
2018-06-06 11:04:00 2018-06-06 11:04:59
EDIT: As David Faber pointed out, this works only if your column has the datatype DATE. For the datatype TIMESTAMP, you're better of with #MT0's solution.
I am using the following query to extract data. But, I want the time to be exact instead of variable.
WHERE DAILY_OPEN_POSITIONS.REPORT_TIMESTAMP <= SYSTIMESTAMP - INTERVAL '3' HOUR + INTERVAL '1' MINUTE
AND DAILY_OPEN_POSITIONS.REPORT_TIMESTAMP >= SYSTIMESTAMP - INTERVAL '3' HOUR - INTERVAL '1' MINUTE
I want the time to be given like this:
where REPORT_TIMESTAMP BETWEEN '2016-08-11 20:59:00' AND '2016-08-11 20:59:01'
The time is a constant, but the date always points to yesterday, that's why I used the first query. is there anyway to mix both?
Time stamp between yesterday's date, time between 20:59:00 and 20:59:01.
Functions used: to_timestamp , to_char , sysdate
where REPORT_TIMESTAMP BETWEEN
TO_TIMESTAMP (to_char(sysdate-1,'DD-Mon-RR') || ' 20:59:00', 'DD-Mon-RR HH24:MI:SS')
and
TO_TIMESTAMP (to_char(sysdate-1,'DD-Mon-RR') || ' 20:59:01', 'DD-Mon-RR HH24:MI:SS')
I have to calculate time difference in minutes from current(sysdate) and modified time:-
to_date(to_char(sysdate, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
- to_date(to_char(modified, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
but problem is to_char returns proper time:-
to_char(whenmodified, 'YYYY-MM-DD HH24:MI:SS')
Outputs 2016-05-23 14:55:50
and to_date doesn’t show time:-
to_date(to_char(modified, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS')
Outputs: 2016-05-23
Please assist how I can get time difference by converting to_char to to_date.
NOTE:
I cant do sysdate-modified because both sysdate and modified gives date without time e.g 2016-05-23
Using to_char for sysdate or modified give date with time 2016-05-23 14:55:50
As we cant subtracts dates in to_char function I am again converting back them to to_date for getting time.
I am expecting:
2016-05-23 14:55:50 - 2016-05-23 14:53:50 = 2 min
I have to calculate time difference in minutes from current(sysdate) and modified time
Oracle Setup:
CREATE TABLE table_name ( modified DATE );
INSERT INTO table_name
SELECT TIMESTAMP '2016-05-23 14:20:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-05-23 00:00:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-05-01 00:00:00' FROM DUAL UNION ALL
SELECT TIMESTAMP '2016-01-01 00:00:00' FROM DUAL;
Query:
SELECT ( sysdate - modified ) * 24 * 60 AS minute_difference
FROM table_name;
Output:
MINUTE_DIFFERENCE
-----------------
3.66666667
863.666667
32543.6667
206783.667
And to address your comment that:
to_date doesn’t show time
A date always has a time component and never has a format internally to the database (it is represented by 7 or 8 bytes) - the formatting of a date is done by the client program that you use to access the database (and often the default is not to show the time component - however, the time component still exists).
You can change this either in the preferences of your client program or, if they don't use that to control it, by changing the NLS_DATE_FORMAT session parameter:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';