how do I write a SQL where statement that checks if a string contains some substring and a number. For example:
string: macsea01
where string like 'macsea' plus a number
Regex is the most obvious solution to this question. Without more detail about the specific format of the string, I can suggest the following, which will match a sequence of a letter in the alphabet followed immediately by a digit:
where column_name like '%[a-zA-Z][0-9]%'
If you're literally looking for macsea at the beginning of the string followed by a digit, it would be:
where column_name like 'macsea[0-9]%'
Regex seem to bee a little slippery here, depending on your needs you can for instance divide the string into several parts, first the text part, and take the rest of the string, try to convert it into a number.
Somthing like this (but I think this perticular code is broken
where substring(column_name, 1, 6) = 'macsea' and cast(substring(column_name, 7, 1000) as int) > 0
Related
I need to extract a string that will located between two characters, with always the same pattern
sample string:
A CRN_MOB_H_001 a--> <AVLB>
What is in bold AVLB is what I want to extract, the whole string will always have the same pattern, and everything that is before the < is irrelevant to me.
The string will always have the same pattern:
Some string with possible special characters such as <>, although very unlikely so, it can be ignored if too complicated
a space
then -->
a space
and then the part that is interesting <XXXXXXX>
The XXXXXXX representing the part I want to extract
thank you for your time.
I have tried several things, could not get anywhere I wanted.
Please try this REGEXP_SUBSTR(), which selects what is in the angled brackets when they occur at the end of the string.
Note the WITH clause just sets up test data and is a good way to supply data for people to help you here.
WITH tbl(str) AS (
SELECT 'A CRN_MOB_H_001 a--> <AVLB>' FROM dual
)
SELECT REGEXP_SUBSTR(str, '.*<(.*)>$', 1, 1, NULL, 1) DATA
FROM tbl;
DATA
----
AVLB
1 row selected.
I have a questions regarding below data.
You clearly can see each EMP_IDENTIFIER has connected with EMP_ID.
So I need to pull only identifier which is 10 characters that will insert another column.
How would I do that?
I did some traditional way, using INSTR, SUBSTR.
I just want to know is there any other way to do it but not using INSTR, SUBSTR.
EMP_ID(VARCHAR2)EMP_IDENTIFIER(VARCHAR2)
62049 62049-2162400111
6394 6394-1368000222
64473 64473-1814702333
61598 61598-0876000444
57452 57452-0336503555
5842 5842-0000070666
75778 75778-0955501777
76021 76021-0546004888
76274 76274-0000454999
73910 73910-0574500122
I am using Oracle 11g.
If you want the second part of the identifier and it is always 10 characters:
select t.*, substr(emp_identifier, -10) as secondpart
from t;
Here is one way:
REGEXP_SUBSTR (EMP_IDENTIFIER, '-(.{10})',1,1,null,1)
That will give the 1st 10 character string that follows a dash ("-") in your string. Thanks to mathguy for the improvement.
Beyond that, you'll have to provide more details on the exact logic for picking out the identifier you want.
Since apparently this is for learning purposes... let's say the assignment was more complicated. Let's say you had a longer input string, and it had several groups separated by -, and the groups could include letters and digits. You know there are at least two groups that are "digits only" and you need to grab the second such "purely numeric" group. Then something like this will work (and there will not be an instr/substr solution):
select regexp_substr(input_str, '(-|^)(\d+)(-|$)', 1, 2, null, 2) from ....
This searches the input string for one or more digits ( \d means any digit, + means one or more occurrences) between a - or the beginning of the string (^ means beginning of the string; (a|b) means match a OR b) and a - or the end of the string ($ means end of the string). It starts searching at the first character (the second argument of the function is 1); it looks for the second occurrence (the argument 2); it doesn't do any special matching such as ignore case (the argument "null" to the function), and when the match is found, return the fragment of the match pattern included in the second set of parentheses (the last argument, 2, to the regexp function). The second fragment is the \d+ - the sequence of digits, without the leading and/or trailing dash -.
This solution will work in your example too, it's just overkill. It will find the right "digits-only" group in something like AS23302-ATX-20032-33900293-CWV20-3499-RA; it will return the second numeric group, 33900293.
I am working with Sybase SQL and want to exclude all entries that look like this:
(NOT PRESENT)
So I tried using:
SELECT col FROM table WHERE col NOT LIKE '(%)'
Do you guys know what is happening? I think I need to escap ( somehow, but I do not know how. The following returns an error:
SELECT col FROM table WHERE col NOT LIKE '\(%\)' ESCAPE '\'
Kind Regards
Try this :
SELECT col FROM table WHERE col NOT LIKE ('(%)')
You might find this helpful
Sybase Event Stream Processor 5.0 CCL Programmers Guide - String Functions
like()
Scalar. Determines whether a given string matches a specified pattern string.
Syntax
like ( string, pattern )
Parameters
string A string.
pattern A pattern of characters, as a string. Can contain wildcards.
Usage
Determines whether a string matches a pattern string. The function returns 1 if the string matches the pattern, and 0 otherwise. The pattern argument can contain wildcards: '_' matches a single arbitrary character, and '%' matches 0 or more arbitrary characters. The function takes in two strings as its arguments, and returns an integer.
Note: In SQL, the infix notation can also be used: sourceString like patternString.
Example
like ('MSFT', 'M%T') returns 1.
CASE
WHEN <in_data> LIKE '[0-9][0-9][0-9][0-9][0-9][0-9]' THEN SUBSTR(<in_data>,1,3)
ELSE '000'
END
We're doing a migration project from Sybase to Teradata, and having a problem figuring this one out :) I'm still new to Teradata.
I would like to ask the equivalent TD code for this -
LIKE '[0-9][0-9][0-9][0-9][0-9][0-9]' to Teradata
Basically, it just checks whether the digits are numeric value.
Can someone give me a hint on this
You can also use REGEXP_SUBSTR to directly extract the three digits:
COALESCE(REGEXP_SUBSTR(in_data,'^[0-9]{3}(?=[0-9]{3}$)'), '000')
This looks for the first three digits and then does a lookahead for three following digits without adding them to the overall match.
^ indicates the begin of the string, '$' the end, so there are no other characters before or after the six digits. (?=...) is a so-called "lookahead", i.e. those three digits are checked, but ignored.
If there's no match the regex returns NULL which is changed to '000'.
You need to use regexp instead of like, since [0-9][0-9][0-9][0-9][0-9][0-9] is a regular expression.
To do an exact match, you need to add anchors. ie, to match the string which contains an exact 6 digit chars.
regexp '^[0-9]{6}$'
or
regexp '^[[:digit:]]{6}$'
I am trying to only return the second to last character from a string using MS SQL.
I've tried using MID and Substring but the length of the string isn't always the same for the column I am trying to return, So I can't do it that way.
So say I am returning the codes of something:
Code
'1234'
I want to just return '3' from that code.
How can I do this?
Cheers in advance :)
Use SUBSTRING and LEN. LEN gives you the length of the string, then subtract 1 to get the previous char:
SELECT SUBSTRING(Code, LEN(Code)-1,1)
How about
select left(right(code, 2), 1) from MyTable;
You might need to validate that the string actually has at least 2 chars, however.
SqlFiddle here