I'm attempting to count the number of times apples and oranges appear in my fruit column.
The table looks like this:
Fruit
-------
Apples
Apples Oranges
Apples Oranges
Apples
Oranges
Expected output:
Apples 4
Oranges 3
My code thus far. I'm not sure how to do it when both appear and how to add them to the totals. I'm sure there is an easier way that this.
SELECT
COUNT (CASE WHEN Fruit LIKE '%Apples%' THEN '1' END) AS Apples
COUNT (CASE WHEN Fruit LIKE '%Oranges%' THEN '1' END) AS Oranges
FROM Fruits
Cheers
If those fruits are single-worded and separated by a space, then such a generic approach might be interesting for you.
Lines #1 - 8 represent sample data; you already have that so you don't type it. Code you might need starts at line #10.
SQL> with fruit (fruit) as
2 -- sample data; you have that in a table
3 (select 'Apples' from dual union all
4 select 'Apples Oranges' from dual union all
5 select 'Apples Oranges' from dual union all
6 select 'Apples Lemon' from dual union all
7 select 'Oranges Plums' from dual
8 ),
9 -- split fruits to rows
10 temp as
11 (select regexp_substr(fruit, '[^ ]+', 1, column_value) fruit
12 from fruit cross join
13 table(cast(multiset(select level from dual
14 connect by level <= regexp_count(fruit, ' ') + 1
15 ) as sys.odcinumberlist))
16 )
17 select fruit, count(*)
18 from temp
19 group by fruit
20 order by fruit;
FRUIT COUNT(*)
-------------------------------------------------------- ----------
Apples 4
Lemon 1
Oranges 3
Plums 1
SQL>
Either with sum or count, it works
Connected to:
Oracle Database 12c Enterprise Edition Release 12.2.0.1.0 - 64bit Production
SQL> with t as
(
select 'Apples' as fruits from dual union all
select 'Apples Oranges' as fruits from dual union all
select 'Apples Oranges' as fruits from dual union all
select 'Apples' as fruits from dual union all
select 'Oranges' as fruits 6 from dual
) select
SUM (CASE WHEN fruits LIKE '%Apples%' THEN '1' END) AS Apples ,
SUM (CASE WHEN fruits LIKE '%Oranges%' THEN '1' END) AS Oranges
FROM t
;
APPLES ORANGES
---------- ----------
4 3
SQL> with t as
(
select 'Apples' as fruits from dual union all
select 'Apples Oranges' as fruits from dual union all
select 'Apples Oranges' as fruits from dual union all
select 'Apples' as fruits from dual union all
select 'Oranges' as fruits from dual
) select
COUNT (CASE WHEN fruits LIKE '%Apples%' THEN '1' END) AS Apples ,
COUNT (CASE WHEN fruits LIKE '%Oranges%' THEN '1' END) AS Oranges
FROM t ;
APPLES ORANGES
---------- ----------
4 3
SQL>
Related
I am looking to get the max weight of Apple, Orange, Mango - there could be any number of fruits. Bold items from the table is what i would like to have my query response.
I know this can be done by partitioning the table for example:
SELECT fruits,max(weight) OVER(PARTITION BY fruits)
FROM fruitstat
GROUP BY fruits;
But this is not getting my expected results. I need the ones which are the max weight fruits in its category.
Fruits
Color
Weight
Apple
red
23
Orange
orange
6
Mango
yellow
13
Apple
red
15
Orange
orange
19
Mango
yellow
16
Apple
red
44
Orange
orange
31
Mango
yellow
12
Apple
red
14
Orange
orange
22
Mango
yellow
11
Just group the MAX(weight) by fruits:
WITH fruit AS
(
SELECT 'Apple' as fruits,'red' as color ,23 as weight FROM dual UNION ALL
SELECT 'Orange','orange',6 FROM dual UNION ALL
SELECT 'Mango','yellow',13 FROM dual UNION ALL
SELECT 'Apple','red',15 FROM dual UNION ALL
SELECT 'Orange','orange',19 FROM dual UNION ALL
SELECT 'Mango','yellow',16 FROM dual UNION ALL
SELECT 'Apple','red',44 FROM dual UNION ALL
SELECT 'Orange','orange',31 FROM dual UNION ALL
SELECT 'Mango','yellow',12 FROM dual UNION ALL
SELECT 'Apple','red',14 FROM dual UNION ALL
SELECT 'Orange','orange',22 FROM dual UNION ALL
SELECT 'Mango','yellow',11 FROM dual
)
SELECT fruits, MAX(weight)
FROM fruit
GROUP BY fruits;
P.S. MAX for the apple is 44, not 23, at least in your sample data
You don't need to use group by on window functions. You can do this, instead.
First, sort the fruits weight by using rank.
select rank() over (partition by fruits order by weight) as rank, fruits, weight
from fruitstat
After that, you can use subquery to return the first value only.
select fruits, weight
from (select rank() over (partition by fruits order by weight) as rank, fruits, weight from fruitstat) a
where rank = 1
I have a table like below. My aim is to count apple and mango under fruit.
I want to do this using case when statement. I run this query but it didn't work.
This works:
CASE
WHEN Food_type = 'vegetables'
AND Names IN ('apple', 'mango')
THEN 1
ELSE 0
END IN (0)
CASE
WHEN Names IN ('apple', 'orange', 'mango')
THEN 'fruit'
END Food_type2
Output:
Names
Food_type
apple
vegetables
eggplant
vegetables
carrot
vegetables
orange
fruit
onion
vegetables
spinach
vegetables
mango
vegetables
How can I do this ? Thank you.
This? Sample data till line #9; query begins at line #10.
SQL> with test (names, food_type) as
2 (select 'apple' , 'vegetables' from dual union all
3 select 'eggplant', 'vegetables' from dual union all
4 select 'carrot' , 'vegetables' from dual union all
5 select 'orange' , 'fruit' from dual union all
6 select 'onion' , 'vegetables' from dual union all
7 select 'spinach' , 'vegetables' from dual union all
8 select 'mango' , 'vegetables' from dual
9 )
10 select case when names in ('apple', 'mango') or food_type = 'fruit' then 'fruit'
11 else 'vegetables'
12 end food_type,
13 count(*)
14 from test
15 group by
16 case when names in ('apple', 'mango') or food_type = 'fruit' then 'fruit'
17 else 'vegetables'
18 end;
FOOD_TYPE COUNT(*)
---------- ----------
vegetables 4
fruit 3
SQL>
This is a sample table data
Date | Fruit | Number
-----------------------
1 | Apple | 1
1 | Apple | 2
1 | Apple | 3
1 | Kiwi | 6
1 | Kiwi | 10
2 | Apple | 4
2 | Apple | 5
2 | Apple | 6
2 | Kiwi | 4
2 | Kiwi | 7
I try to concatenate the table column values to get the following:
Date | Fruit | Number
-----------------------
1 | Apple | 1-2-3
1 | Kiwi | 6-10
2 | Apple | 4-5-6
2 | Kiwi | 4-7
Code that I use:
SELECT fruit,
LTRIM( MAX(SYS_CONNECT_BY_PATH(number,','))
KEEP (DENSE_RANK LAST ORDER BY curr), ',') AS fruits_agg
FROM( SELECT Date,
fruit,
number,
ROW_NUMBER() OVER (PARTITION BY fruit ORDER BY number) AS curr,
ROW_NUMBER() OVER (PARTITION BY fruit ORDER BY number) - 1 AS prev
FROM table_name)
GROUP BY Date,fruit
CONNECT BY prev = PRIOR curr AND fruit = PRIOR fruit AND Date = PRIOR Date
START WITH curr = 1;
It doesn't work the way I want it to be. Where Did I do wrong?
PS: I'm on version 10g, so I can't use listagg.
For Oracle 10, using your approach - the issue is the partitioning in your inner query.
WITH tab as (
SELECT 1 as fdate, 'Apple' as fruit, 1 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 2 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 3 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 6 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 10 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 5 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 6 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 7 as num from dual )
SELECT fdate, fruit,LTRIM(MAX(SYS_CONNECT_BY_PATH(num,','))
KEEP (DENSE_RANK LAST ORDER BY curr),',') AS fruits_agg
FROM (SELECT fdate,
fruit,
num,
ROW_NUMBER() OVER (PARTITION BY fdate, fruit ORDER BY num) AS curr,
ROW_NUMBER() OVER (PARTITION BY fdate, fruit ORDER BY num) -1 AS prev
FROM tab)
GROUP BY fdate,fruit
CONNECT BY prev = PRIOR curr AND fruit = PRIOR fruit AND fdate = PRIOR fdate
START WITH curr = 1;
Gives:
FDATE FRUIT FRUITS_AGG
1 "Kiwi" "6,10"
1 "Apple" "1,2,3"
2 "Kiwi" "4,7"
2 "Apple" "4,5,6"
The Oracle 11 solution is a whole lot easier:
WITH tab as (
SELECT 1 as fdate, 'Apple' as fruit, 1 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 2 as num from dual union
SELECT 1 as fdate, 'Apple' as fruit, 3 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 6 as num from dual union
SELECT 1 as fdate, 'Kiwi' as fruit, 10 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 5 as num from dual union
SELECT 2 as fdate, 'Apple' as fruit, 6 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 4 as num from dual union
SELECT 2 as fdate, 'Kiwi' as fruit, 7 as num from dual )
select fdate
, fruit
, listagg(num,'-') within group ( order by num ) fruit_agg
from tab
group by fdate, fruit
Returns:
FDATE FRUIT FRUIT_AGG
1 Kiwi 6-10
1 Apple 1-2-3
2 Kiwi 4-7
2 Apple 4-5-6
I need to transpose rows to columns in Oracle. I've the data in this format:
Apple Orange Mango Banana
15 20 12 67
The required result is:
Fruit Number
Apple 15
Orange 20
Mango 12
Banana 67
I used Union to get this result but this is not the generic one.
SELECT ‘Apple’ AS Fruit, Apple AS Number FROM fruits_tbl UNION
SELECT ‘Orange’, Orange FROM fruits_tbl UNION
SELECT ‘Mango’, Mango FROM fruits_tbl UNION
SELECT ‘Banana’, Banana FROM fruits_tbl;
I want standard procedure to get the output as suggested.
Update: Figured out Pivot is the correct approach!
Since Oracle 11g (tab is your table name):
select * from tab
UNPIVOT (num for fruit in (apple as 'apple', orange as 'orange', mango as 'mango', banana as 'banana'));
Oracle 10g:
with col_names as (
select 'apple' fruit from dual
union all select 'orange' from dual
union all select 'mango' from dual
union all select 'banana' from dual
)
select c.fruit,
case c.fruit
when 'apple' then t.apple
when 'orange' then t.orange
when 'mango' then t.mango
when 'banana' then t.banana
end as num
from tab t
cross join col_names c;
I have a table e.g.
**Fruit Number**
Apple 5
Grape 9
Orange 1
Coconut 54
Mango 22
I want to :
Select the whole list
Put 'Apple, Mango,Coconut' at top of the list.
Update the current order, where number = rownum
The list should look as follows :
**Fruit Number**
Apple 1
Mango 2
Coconut 3
Grape 4
Orange 5
I tried the following however getting syntax issues ..
update tablename
set id = rownum
where fruit in (select fruit from table order by decode(fruit,'Apple',1,'Mango',2,'Coconut',3))
UPDATE (
SELECT ROWNUM+5 AS r, fruit, number FROM TABLE
WHERE fruit NOT IN ('Apple', 'Mango', 'Coconut', 'Grape', 'Orange')
UNION
SELECT 1 AS r, 'Apple' AS fruit, number FROM TABLE
UNION
SELECT 2 AS r, 'Mango' AS fruit, number FROM TABLE
UNION
SELECT 3 AS r, 'Coconut' AS fruit, number FROM TABLE
UNION
SELECT 4 AS r, 'Grape' AS fruit, number FROM TABLE
UNION
SELECT 5 AS r, 'Orange' AS fruit, number FROM TABLE
)
SET number = r;
Following query will do that for you.
UPDATE table SET number =
CASE fruit
WHEN 'Apple' THEN 1
WHEN 'Mango' THEN 2
WHEN 'Coconut' THEN 3
WHEN 'Grape' THEN 4
WHEN 'Orange' THEN 5
END;