In my program we originally were using Java with Preview Features enabled, which gave as a feature to use String blocks defined in between three double quotes. For example:
String s = """
Line one
Line two
""";
Now, we decided to go back to Java 14 and I need to replace those with regular String declaration in all project (which is around ~1000 occurrences). Is there a way to do that in bulk?
String s = "Line one\n"+
"Line two\n";
You can run the inspection "Text block can be replaced with regular string literal" inspection on your code using the "Run Inspection by Name" action. It has a quick fix to do the conversion for you.
Related
My site was hacked and I was able to retrieve some SQL from binlog, they look like
<p>some text</p>\r\n<p><img src=\"images/2019-04-27/1.jpg\" alt=\"1\" /></p>
I need to convert \r\n to new line and unescape the double quotes.
Of course I can write my own function to achieve this, but since there are lots of SQLs to convert, I am not sure if \r\n and \" are the only things I need to deal with.
I think the key here is to find out what this conversion is called so I can google. I tried "html encode", "html escape" and "sql escape", none of them worked.
So, is there any PHP or JAVASCRIPT function that can handle this? Or is there any online tools?
Python automatically converts /n into a new line for you. For example, if you go onto this website here - www.repl.it/languages/python3
string = '<p>some text</p>\r\n<p><img src=\"images/2019-04-27/1.jpg\" alt=\"1\" /></p>'
print(string)
Copy the above code into it and you'll see the string is given a new line
If you need to use a multi line string put the string in 3 quotation marks like so.
string = '''
I
am
a
multi
line
string
'''
Been searching around for this for a couple hours, can't find anything which will do this correctly. When writing a string to a text file, a blank line is outputted at the end.
writeString = New StreamWriter(path, False)
writeString.WriteLine("Hello World")
writeString.Flush()
writeString.Close()
This will write the following to file:
Hello World
(Blank Line)
I've tried removing last character of string (both as regular string with varString.Substring(0, varString.Length - 1) and also as a list of string with varList.RemoveAt(varList.Count - 1)) but it just removes the literal last character.
I've also tried using Replace(vbCrLf, "") and many variations of it but again, they only remove literal new lines created in the string, not the new line at the end that is magically created.
Preferably, I'm seeking a method which will be able to remove that magical newline before the string is ever written to the file. I found methods which read from the file and then write back to it which would require Write > Read > Write, but in all cases the magical new line still appeared. :(
If it's important to note: The file will contain a string which may contain actual new lines (it's 'Song Artist - Song Title', though can contain other information and new lines can be added if the user wishes). That text file is then read by other applications (such as mIRC etc) of which output the contents by various means depending on application.
Eg. If an application were to read it and output it into a textbox.. the new line will additionally output to that textbox.. which is a problem! I have no control of the applications which will read the file as input considering it's the client which decides the application, so the removal of the new line needs to be done when outputted.
Help is appreciated~!
Use the Write method instead of WriteLine. The WriteLine method is the one adding a blank 0 length line to the file because it is terminating the "Hello World" string with a newline.
writeString.Write("Hello World")
I am running a VBA program from SAS. The SAS code for this basically looks like:
%let worksheet =&i; *worksheet number;
%let xlsfile = %STR(""C:\Data\Excel Workbook.xlsx"");
%let csvfile = %STR(""C:\Data\CSV File..csv"");
x 'cd "C:\Data\MN2013\Alignment\Data\SAS Programs"';
x "XlsWsToCsv.vbs &xlsfile &worksheet &csvfile";
I need to be able to include two double quotes (i.e. "") at the beginning and end of the file paths in the xlsfile and csvfile for the VBA program to recognize the spaces in the file paths and run correctly.
MY PROBLEM:
I run this in SAS Enterprise Guide using SAS 9.3. In my log, directly after the variable definition is read in, the double quotes are underlined in red (usually indicating an error) with the number 49 below. There is no error message, but instead, in green I get the following note:
NOTE 49-169: The meaning of an identifier after a quoted string might change in a future SAS
release. Inserting white space between a quoted string and the succeeding
identifier is recommended.
To me, this says SAS is reading these double quotes. They are somehow only partially being masked. My VBA program runs, so I could continue with this; but I like clean error logs. Does anyone have any recommendations for how to completely mask my xlsfile and csvfile variables? I've tried using %STR (as shown in my example above), %BQUOTE, %SUPERQ, and a few other things to make this work.
Those pesky error messages! You were very close, but try this syntax instead:
%let xlsfile = %STR("")C:\Data\Excel Workbook.xlsx%STR("");
%let csvfile = %STR("")C:\Data\CSV File..csv%STR("");
Double double quotes inside double quotes resolve to a single double quote character, ie...
x """c:\program files\office\excel.exe"" stuff stuff stuff ""stuff"" stuff";
should work just fine. Don't worry about the 'identifier' message, that's largely saying something like
"01JAN2013"d
could be possible with other things. You can add a space after the last " if it's a problem to have that in the log.
I've made some good progress with my first attempt at a program, but have hit another road block. I'm taking standard output (as a string) froma console CMD window (results of dsquery piped to dsget) and have found small rectangles in the output. I tried using Regex to clean the little bastards but it seems they are related to the _ (underscore), which I need to keep (to return 2000/NT logins). Odd thing is - when I copy the caharcter and paste it into VS2K10 Express it acts like a carrige return??
Any ideas on finding out what these little SOB's are -- and how to remove them?
Going to try using /U or /A CMD switch next..
The square is often just used whenever a character is not displayable. The character could very well be a CR. You can use a Regular Expression to just get normal characters or remove the CR LF characters using string.replace.
You mentioned that you are using the string.replace function, and I am wondering if you are replacing the wrong character or something like that. If all your trying to do is remove a carriage return I would skip the regular expressions and stick with the string.replace.
Something like this should work...
strInputString = strInputString.replace(chr(13), "")
If not could you post a line or two of code.
On a side note, this might give some other examples....
Character replacement in strings in VB.NET
I am trying to use a copy command for Windows and we have directories such as c:\oracle.
While trying to execute one such, we get the following error:
source_file=folder+"\"
^
SyntaxError: Lexical error at line 17, column 23. Encountered: "\r" (13), after : ""
Here folder is my path of c:\oracle and while trying to add file to it like:
source=folder+"\"+src_file
I am not able to do so. Any suggestion on how to solve this issue?
I tried with / but my copy windows calling source in os.command is getting "the syntax is incorrect" and the only way to solve it is to use \ but I am getting the above error in doing so.
Please suggest. Thanks for your help
Thanks.
Short answer:
You need:
source_file = folder + "\\" + src_file
Long answer:
The problem with
source_file = folder + "\" + src_file
is that \ is the escape character. What it's doing in this particular case is escaping the " so that it's treated as a character of the string rather than the string terminator, similar to:
source_file = folder + "X + src_file
which would have the same problem.
In other words, you're trying to construct a string consisting of ", some other text and the end of line (\r, the carriage return character). That's where your error is coming from:
Encountered: "\r" (13)
Paxdiablo is absolutely correct about why \ isn't working for you. However, you could also solve your problem by using os.path.normpath instead of trying to construct the proper platform-specific path characters yourself.
In all programming languages I know of, you can't put a quote inside a string like this: "this is a quote: "." The reason for this is that the first quote opens the string, the second then closes it (!), and then the third one opens another string - with the following two problems:
whatever is between the quotes #2 and #3 is probably not valid code;
the quote #3 is probably not being closed.
There are two common mechanisms of solving this: doubling and escaping. Escaping is far more common, and what it means is you put a special character (usually \) in front of characters that you don't want to be interpreted in their usual value. Thus, "no, *this* is a quote: \"." is a proper string, where the quote #2 is not closing the string - and the character \ does not appear.
However, now you have another problem - how do you actually make the escape character appear in a string? Simple: escape it! "This is an escape: \\!" is how you do it: the backslash #1 is the escape character, and the backslash #2 is the escapee: it will not be interpreted with its usual escape semantics, but as a simple backslash character.
Thus, your line should say this:
source=folder+"\\"+src_file
BTW: upvote for both #paxdiablo (who got in before my diatribe) and #Nick (who has a proper Pythonic way to do what you want to do)