Get name after and before certain character in SQL Server - sql

Question

I got the following entry in my database:
\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv
So basically, I want everything after the last \ and before .
the namefile in that example
Thanks in advance.

Answer 1

If you are making use of an older version of SQL server which doenst support string_split. The reverse function comes in handy as follows.
The steps i do is reverse the string, grab the char position of ".", grab the char position of "\" then apply the substring function on it to slice the data between the two positions. Finally i reverse it again to get the proper value.
Here is an example
with data
as(select '\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv' as col
)
select reverse(substring(reverse(col)
,charindex('.',reverse(col))+1
,charindex('\',reverse(col))
-
charindex('.',reverse(col))-1
)
) as file_name
from data
+-----------+
| file_name |
+-----------+
| namefile |
+-----------+
dbfiddle link
https://dbfiddle.uk/?rdbms=sqlserver_2014&fiddle=8c0fc11f5ec813671228c362f5375126

Answer 2

You can use:
select t.*,
left(s.value, charindex('.', s.value))
from t cross apply
string_split(t.entry, '\') s
where t.entry like concat('%', s.value);
This splits the string into different components and matches on the one at the end of the string. If components can repeat, the above can return duplicates. That is easily addressed by moving more logic into the apply:
select t.*, s.val
from t cross apply
(select top (1) left(s.value, charindex('.', s.value)) as val
from string_split(t.entry, '\') s
where t.entry like concat('%', s.value)
) s

Answer 3

You can just use String functions (REVERSE,CHARINDEX,SUBSTRING).
SELECT
REVERSE(
SUBSTRING(REVERSE('\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv'),
CHARINDEX('.',REVERSE('\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv'))+1,
CHARINDEX('\',REVERSE('\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv'))-
CHARINDEX('.',REVERSE('\\folder.abc\es\Folder-A\\2020-08-03\namefile.csv'))-1))
OR
SELECT
REVERSE
(
SUBSTRING( --get filename
reverse(path), --to get position last \
CHARINDEX('.',reverse(path))+1,
CHARINDEX('\',reverse(path))- CHARINDEX('.',reverse(path))-1)
)