I have above entries in my database, my requirement is to extract the fields containing the non-english language characters ( including if the data containing the combination of english and non-english characters like HotelName field for the ID 45).
I tried by regexp_like function by looking for the alphanumeric and non-alphanumeric, but i have some data with combination of both the condition fails there.
Thanks in Advance
Raghavan
Does this do what you want?
where regexp_like(hotelname, '[^a-zA-Z0-9 ]')
That is, where the hotel name contains any character that is not a "letter" or digit. You may need to take additional characters into account as well, such as commas, periods, and hyphens.
Related
I've been searching and I couldnt found exactly what I need.
I have and SQL Server 2008
I have some strings in a table with special characters such as "!,;:-()" and I'm trying to make a script that could return this characters, BUT ONLY THOSE CHARACTERS (do you get it?)
For example, I have "Borges, Ricardo" and I need to return only the ","
Another example, "Calle 13 Nº 34, Mercedes Bs As ( 6600)", and I only need the "º,()"
I dont want to get the letters or numbers.
I wrote this simple script:
SELECT name FROM table WHERE name LIKE '%[^A-Za-z0-9 ]%'
SO I could get all the rows where there is a Special Character like a (,;.:-()&%$... but I need to RETURN ONLY the special Characters. Get it? No letters, no numbers, only the special characters in the row.
THank you very much for your help!
I have a field with text reviews in it and I want to spot where people have used special characters to get offensive words etc past the filters, so instead of typing badword they type b.a.d.w.o.r.d or b*a*d*w*o*r*d,
Is there a way to look for say 3 or more special characters in word in a text review, maybe some sort of count function for special characters?
If you have a table with a field containing words you dont want to allow you could add it in your WHERE clause like so using REGEX_REPLACE.
SELECT yourfield
FROM yourtable
WHERE REGEXP_REPLACE(yourfield,'[^a-zA-Z'']','') NOT IN (SELECT badwords
FROM badwordstable)
I want to find all rows for which values in string column does not possess certain characters (to be specific [a-Z0-9 \t\n]) how can I do it in sql ?
I tried to do it with like operator
SELECT ***
where column like '%[^ a-Z0-9 \t\n]%'
however, it does not work and I get rows that possess characters and numbers.
To fetch all records that contain any characters other than alphabets, numbers, spaces, tabs and new-line delimiters:
SELECT ***
WHERE column like '%[^A-Za-z0-9 \t\n]%'
Note that [^A-Za-z0-9 \t\n] represents anything other than alphanumeric characters, spaces, tabs, and new line delimitters.
Your logic is inverted. I think you want:
where column not like '%[^ a-Z0-9 \t\n]%'
I don't think that SQL Server interprets \t and \n as special characters. You may need to insert the actual values for the characters. (See here.)
SELECT ***
WHERE column like '%[^A-Za-z0-9 \t\n]%'
I have a column error_desc with values like:
Failure occurred in (Class::Method) xxxxCalcModule::endCustomer. Fan id 111232 is not Effective or not present in BL9_XXXXX for date 20160XXX.
What SQL query can I use to display only the number 111232 from that column? The number is placed at 66th position in VARCHAR column and ends 71st.
SELECT substr(ERROR_DESC,66,6) as ABC FROM bl1_cycle_errors where error_desc like '%FAN%'
This solution uses regular expressions.
The challenge I faced was on pulling out alphanumerics. We have to retain only numbers and filter out string,alphanumerics or punctuations in this case, to detect the standalone number.
Pure strings and words not containing numbers can be easily filtered out using
[^[:digit:]]
Possible combinations of alphanumerics are :
1.Begins with a character, contains numbers, may end with characters or punctuations :
[a-zA-Z]+[0-9]+[[:punct:]]*[a-zA-Z]*[[:punct:]]*
2.Begins with numbers and then contains alphabets,may contain punctuations :
[0-9]+[[:punct:]]*[a-zA-Z]+[[:punct:]]*
Begins with numbers then contains punctuations,may contain alphabets :
-- [0-9]+[a-zA-Z][[:punct:]]+[a-zA-Z] --Not able to highlight as code, refer solution's last regex combination
Combining these regular expressions using | operator we get:
select trim(REGEXP_REPLACE(error_desc,'[^[:digit:]]|[a-zA-Z]+[0-9]+[[:punct:]]*[a-zA-Z]*[[:punct:]]*|[0-9]+[[:punct:]]*[a-zA-Z]+[[:punct:]]*|[0-9]+[a-zA-Z]*[[:punct:]]+[a-zA-Z]*',' '))
from error_table;
Will work in most cases.
I have a table with a string field containing location information. I want to be able to query this table and retrieve all of the tags matching the format xxxxxxAA where xxxxxx is a 6-digit number and AA is two alphabetic characters.
Is there a method of querying this using SQL or is this something that I need to do in VBA?
Sample data:
BGS5 PM RGP5
022051PM
022201PM
030539PM
WAS3N
179546MM
And I want to return the following without knowing the values:
022051PM
022201PM
030539PM
179546MM
thanks in advance
Jason
You can use a query with a Like comparison in the WHERE clause.
SELECT y.text_field
FROM YourTable AS y
WHERE y.text_field Like '######[A-Z][A-Z]'
The # matches a digit.
[A-Z] matches one character from a character class consisting of only letters. That character class is actually upper case letters. However, the comparison is case-insensitive, so will match lower case letters, too.