Oracle SQL - Add numbers separated by delimiter, columnwise - sql

Question

I have multiple rows with values like
a_b_c_d_e_f and x_y_z_m_n_o
and I need a SQL query with a result like a+x_b+y_c+z_d+m.......
Sample data as requested
What I am willing to do is aggregate it at Datetime..aggregating Total is simple, but how can I do that for the last column, thanks.
Expected Result

Answer 1

Here's one option; read comments within code. I didn't feel like typing too much so two dates will have to do.
Sample data (you already have that & don't type it. Code you need begins at line #10):
SQL> with
2 -- sample data
3 test (datum, total, col) as
4 (select date '2020-07-20', 100, '10,0,20,30,0' from dual union all
5 select date '2020-07-20', 150, '15,3,40,30,2' from dual union all
6 --
7 select date '2020-07-19', 200, '50,6,50,30,8' from dual union all
8 select date '2020-07-19', 300, '20,1,40,10,2' from dual
9 ),
Split CSV values into rows. Note the RB value which will help us sum matching values
10 -- split comma-separated values into rows
11 temp as
12 (select
13 datum,
14 total,
15 to_number(regexp_substr(col, '\d+', 1, column_value)) val,
16 column_value rb
17 from test cross join
18 table(cast(multiset(select level from dual
19 connect by level <= regexp_count(col, ',') + 1
20 ) as sys.odcinumberlist))
21 ),
Computing summaries is simple; nothing special about it. We'll keep the RB value as it'll be needed in the last step:
22 -- compute summaries
23 summary as
24 (select datum,
25 sum(total) total,
26 sum(val) sumval,
27 rb
28 from temp
29 group by datum, rb
30 )
The last step. Using LISTAGG, aggregate comma-separated values back, but this time added to each other:
31 -- final result
32 select datum,
33 total,
34 listagg(sumval, ',') within group (order by rb) new_col
35 from summary
36 group by datum, total
37 order by datum desc, total;
DATUM TOTAL NEW_COL
------------------- ---------- --------------------
20.07.2020 00:00:00 250 25,3,60,60,2
19.07.2020 00:00:00 500 70,7,90,40,10
SQL>