I am trying to learn John. I've been through the FAQ and this tutorial, but am stuck.
I have made a RAR4 password hash. It's super simple. The password is 'test'. I now want to use a tool to crack it.
I've saved it to a file "test.txt".It has:
Red dead redemption.rar:$RAR3$*1*de613099dc859cfd*00000000*16*0*1*b52125c28c4fc60a1c00f313d0fb68ca*33:1::Red dead redemption.torrent
When running the following command, I get 'No password hashes loaded'
What should I do to get this working please?
Command: john.exe test.txt
$$ in your hash specify that they are encrypted with yescrypt, Hence you need to specify format to the john
john.exe --format=crypt test.txt
This should work
Related
im trying to create specific pattern for creating password via crunch but didnt found anywhere somthing like that and wanna now if it even possibale.
for example i want to make as pattern thw word "password" but i want that the letter p could be lowcase or highcase, and the letter a could be a or # and the s could be s/$.
so i try somthing like
crunch 10 10 pP+a#+s$word -t
but it not seems right.
try to lock allready in bunch of guide but didnt found way to make spesific char to been choseen from a spesicifc option.
any suggestion?
thank you
crunch 8 8 pP a# s$ s$ -t #,^^word
Gives the output:
password
pas$word
pa$sword
pa$$word
p#ssword
p#s$word
p#$sword
p#$$word
Password
Pas$word
Pa$sword
Pa$$word
P#ssword
P#s$word
P#$sword
P#$$word
If you want to write to a file, append this at the end: -o file.txt
when I try to run the command create role new_user with passowed 'passowrd' login; it just gives me postgres'> on a new line. I am logged in as a superuser in aws postgres rds. what does this mean and how do I fix this?
That means that your typing on the command line is as sloppy as your typing in Stackoverflow, and you didn't close the single quotes properly. Now psql is waiting for you to continue the string input.
Reset the query buffer by hitting Ctrl+C and start again, taking care that you balance the quotes.
Perhaps the password contains a single quote, which you would have to escape by doubling it.
Let me remark that setting a password like this is unsafe: the password is visible on your screen, will end up in your history file, is sent over the line in clear text and may end up in the PostgreSQL log. Use \password to set the password, then you also don't have to worry about escaping single quotes.
Hashcat doesn't support the target application I'm trying to crack, but I'm wondering whether the mask function can be 'fed' the list of passwords and parsed through the rockyou rule to generate an effective wordlist for me?
If so, how can this be done as the documentation leaves lots to be desired.. !
Many thanks
I used HashCatRulesEngine:
https://github.com/llamasoft/HashcatRulesEngine
You can chain all the HashCat rules together, it then union selects them, weeds out any duplicates and takes as input your sample password file.
It then generates all possible permutations.
For instance:
echo "password">foo
./hcre /Users/chris/Downloads/hashcat-4.0.0/rules/Incisive-leetspeak.rule /Users/chris/Downloads/hashcat-4.0.0/rules/InsidePro-HashManager.rule /Users/chris/Downloads/hashcat-4.0.0/rules/InsidePro-PasswordsPro.rule /Users/chris/Downloads/hashcat-4.0.0/rules/T0XlC-insert_00-99_1950-2050_toprules_0_F.rule /Users/chris/Downloads/hashcat-4.0.0/rules/T0XlC-insert_space_and_special_0_F.rule /Users/chris/Downloads/hashcat-4.0.0/rules/T0XlC-insert_top_100_passwords_1_G.rule /Users/chris/Downloads/hashcat-4.0.0/rules/T0XlC.rule /Users/chris/Downloads/hashcat-4.0.0/rules/T0XlCv1.rule /Users/chris/Downloads/hashcat-4.0.0/rules/best64.rule /Users/chris/Downloads/hashcat-4.0.0/rules/combinator.rule /Users/chris/Downloads/hashcat-4.0.0/rules/d3ad0ne.rule /Users/chris/Downloads/hashcat-4.0.0/rules/dive.rule /Users/chris/Downloads/hashcat-4.0.0/rules/generated.rule /Users/chris/Downloads/hashcat-4.0.0/rules/generated2.rule /Users/chris/Downloads/hashcat-4.0.0/rules/hybrid /Users/chris/Downloads/hashcat-4.0.0/rules/leetspeak.rule /Users/chris/Downloads/hashcat-4.0.0/rules/oscommerce.rule /Users/chris/Downloads/hashcat-4.0.0/rules/rockyou-30000.rule /Users/chris/Downloads/hashcat-4.0.0/rules/specific.rule /Users/chris/Downloads/hashcat-4.0.0/rules/toggles1.rule /Users/chris/Downloads/hashcat-4.0.0/rules/toggles2.rule /Users/chris/Downloads/hashcat-4.0.0/rules/toggles3.rule /Users/chris/Downloads/hashcat-4.0.0/rules/toggles4.rule /Users/chris/Downloads/hashcat-4.0.0/rules/toggles5.rule /Users/chris/Downloads/hashcat-4.0.0/rules/unix-ninja-leetspeak.rule < foo >passwordsx
1 password the word "password" was permutated a total of:
bash-3.2# wc -l passwordsx
227235 passwordsx
bash-3.2#
Times meaning that each word you feed into this generates 227235 possible combinations roughly giving you full coverage..
You can use hashcat itself as a candidate generator by adding the --stdout switch (then pipe to your file or program of choice). I haven't tried all the possibilities, but it should work with any of the supported hashcat modes.
Here's an example using a ruleset: https://hashcat.net/wiki/doku.php?id=rule_based_attack#debugging_rules
I am creating a "change password" form where the user is required to enter the previous password first, then a new password (twice).
I should compare the entered "previous password" to the one already stored.
My web application uses an LDAP server to store user credentials. Password is apparently stored using SHA.
So what I do is get the previous password entered by the user, digest it using SHA1, then compare it.
String oldPass = request.getParameter("oldpass");
String enteredOldPass= App.getInstance().getCipher().cipher(oldPass);
String ldapPassword= ctx.get("userpassword");
But this isn't working, because the passwords are different. When I store "test" in the LDAP I obtain {sha}qUqP5cyxm6YcTAhz05Hph5gvu9M= when calling .get("userPassword"), whilst I get a94a8fe5ccb19ba61c4c0873d391e987982fbbd3 when hashing "test" by myself.
What am I doing wrong here? It seems that a step is missing since my result is purely hex, while the one I get from the LDAP is ASCII. But I tried converting the string to hex (using string to hex online converters) but the result is still differnet.
You don't do any of this.
You attempt to rebind as the user with that password. It either succeeds or fails. That tells you whether it was right or wrong. The API and protocol and server will take care of any hashing required.
Or, if you're using an LDAP server that supports the extended change-password operation, you provide the old and new passwords in the extended operation.
you must convert to binary, then convert to base64. Try this:
echo -n "test" | sha1sum | awk '{print $1}' <br>
The result will be a94a8fe5ccb19ba61c4c0873d391e987982fbbd3
echo -n "test" | sha1sum | awk '{print $1}' | xxd -r -p | base64
The result will be qUqP5cyxm6YcTAhz05Hph5gvu9M=
I'm trying to write some code to work with an htdigest password file. The documentation I can find seems to claim that the format of that file is:
user:realm:MD5(user:realm:pass)
If that is the case, then why doesn't this work for me? I created a file with the command line htdigest thus:
htdigest -c test b a
When prompted for a password I entered 'c'. This creates a file with the contents:
a:b:02cc8f08398a4f3113b554e8105ebe4c
However if I try to derive this hash I can't,
echo a:b:c | md5
gives me "49d6ea7ca1facf323ca1928995420354". Is there something obvious that I'm missing here?
Thanks
echo by default adds a trailing new line:
echo -n a:b:c | md5
Should work as you expect.
Hm, I seem to have answered my own question. My test case was flawed, 'echo' is adding extra characters (not sure which). For instance
echo a:b:c | wc
gives 6 characters instead of 5. Calculating the hash at http://md5-hash-online.waraxe.us/ gives the correct value. Sorry everyone!
Here is how you set the password for a given user.
sudo htdigest /etc/apache2/.htdigest yourrealm.com yourusername