React Native getting navigation prop in a regular object - react-native

I have a navigation component where my screens are give a header component
<Stack.Screen
name="AddNewHabitScreen"
component={AddNewHabitScreen}
options={{ ...HeaderBar, title: "New Habits" }}
/>
The HeaderBar is just a simple object with option configurations
const HeaderBar = {
...
headerRight: () => (
<TouchableOpacity onPress={navigate(route)}>
<Image
source={require('../../assets/icons/B_icon_header_info.png')}
/>
</TouchableOpacity>
),
Since it's not a class or functional component I'm not sure how to use hooks or props to give the route information so it can navigate correctly. How would I go about doing this?

Something like
const HeaderBar = ({navigation}) {
...
headerRight: (navigation) => (
<TouchableOpacity onPress={navigation.navigate(route)}>
<Image
source={require('../../assets/icons/B_icon_header_info.png')}
/>
</TouchableOpacity>
),

Related

react navigation drawer reopen after navigate to screen

I'm working on a simple app and have now added drawer navigation, but I'm having a weird problem with the drawer that opens again after navigating to the screen from the drawer content.
PlayerZone is a BottomTabNavigation that contains Profile and other screens.
I tried to dispatch close drawer action before and after navigate to screen, also I tried requestAnimationFrame but nothing helps.
how it looks like
DrawerScreens:
<Animated.View style={[styles.stack, style]}>
<Stack.Navigator
screenOptions={{
header: () => null,
}}>
<Stack.Screen name="PlayerZone" component={PlayerZone} />
</Stack.Navigator>
<GameBottomNavigation />
</Animated.View>
Drawer:
<DrawerItem
label="Profile"
style={styles.item}
labelStyle={styles.itemLabel}
onPress={() => {
props.navigation.navigate('PlayerZone', {
screen: 'Profile',
id: null,
});
}}
/>
<DrawerItem
label="Items"
style={styles.item}
labelStyle={styles.itemLabel}
onPress={() => {
props.navigation.navigate('PlayerZone', {
screen: 'Profile',
id: 'some-id',
});
}}
/>
PlayerZone:
<Tab.Navigator
initialRouteName="Profile"
screenOptions={{
header: () => null,
}}>
<Tab.Screen name="Profile" component={Profile} />
{!peeking && <Tab.Screen name="Items" component={Items} />}
</Tab.Navigator>
Items:
import React, {FC} from 'react';
import {BottomTabScreenProps} from '#react-navigation/bottom-tabs';
import Block from '../../components/Block';
import Text from '../../components/Text';
import {PlayerZoneTabParamList} from '.';
type Props = BottomTabScreenProps<PlayerZoneTabParamList, 'Items'>;
const Items: FC<Props> = () => {
return (
<Block middle center>
<Text>Items</Text>
</Block>
);
};
export default Items;
So after some time trying everything I could think of I found solution (kind of). In drawer navigator I had props useLegacyImplementation set to false because I have configured reanimated 2. I removed this props and everything start working properly.

Trigger an onPress Function from anonther component

I want to trigger an onPress function from the search icon in the navbar.
This is the search component:
function SearchIcon(props) {
const theme = useSelector(state => state.themer.theme);
return (
<Icon.Button
name="search"
size={22}
color={theme.icons}
backgroundColor={theme.top_tab}
onPress={() => {}}
/>
);
}
export default SearchIcon;
The search component is being called in the specific stack, where it's needed.
<Stack.Screen
name="Home"
component={Home}
options={({navigation, route}) => ({
...,
headerRight: props => (
<View style={{flexDirection: 'row'}}>
<SearchIcon />
<CartIcon navigation={navigation} />
</View>
),
})}
/>
On the home screen, I have an isSeacrhing constant that should change value from false to true and vice versa.
const [data, setData] = React.useState({
isSearching: false,
search: '',
...
});
// TRIGGERED BY SEARCH ICON IN NAV BAR
const toggleSearch = () => setData({...data, isSearching: !isSearching});
{data.isSearching == false ? (
<ScrollView
...
</ScrollView>
) : (
<View>
<TextInput
style={[styles.textInput, [{color: theme.text, ...FONTS.body4}]]}
value={data.search}
placeholder="Search..."
placeholderTextColor={theme.text}
onChangeText={()=>{}}
/>
</View>
)}
Is it possible to trigger the onPress function or is there another way I can make it work? The search icon is on two screen, does calling the same function make the TextInput appear on both?
Wherever you use <SearchIcon /> just add a prop in that like this
<SearchIcon onPress={() => { // Do Something }} />
Then in your SearchIcon
function SearchIcon(props) {
const theme = useSelector(state => state.themer.theme);
return (
<Icon.Button
name="search"
size={22}
color={theme.icons}
backgroundColor={theme.top_tab}
onPress={props.onPress} // Access it here like this
/>
);
}
export default SearchIcon;

React Navigation Tab.Screen set Component as name

What i want to do is the following when using the react navigation package.
The docs allow the following:
<Tab.Screen name="name" component={FeedScreen} />
what i want to achieve is this:
<Tab.Screen name={<NameMarkdown />} component={FeedScreen} />
because i want to render markdown as the name of a tab in my application.
is there a way to solve the problem?
The name prop only accepts the string name of the screen you can't pass the component into a name prop.
To give customize the style of your tab you can use it like this
<Tab.Navigator
screenOptions={tabScreenOptions}
tabBarOptions={tabBarOptions}
>
<Tab.Screen name="name" component={FeedScreen} />
tabBarOptions = {
showLabel: false,
style: styles.tabContainer,
tabStyle: styles.tabStyle,
};
tabScreenOptions = props => {
const { route } = props;
return {
tabBarIcon: ({ focused }) => <TabIcon {...{ route, focused }} />,
};
};
const TabIcon = ({ focused, route }) => (
// Here you can use your own component according to your need
<Image
source={Images.tabs[route.name]}
style={{ tintColor: focused ? Colors.primary : Colors.white214 }}
/>
);
Hope this helps you out.

React Navigation V5 does not receive focused parameter when using custom bottomTab component

I am currently trying to implement a custom tabBar design into my react native app which is using React Navigation 5 as the navigation library. Everything is working correctly, except that my tabBarIcons don't receive any props, so i cannot determine whether i have to show the active or inactive tabIcon. Whenever i use a default tabbar i do receive the props, so there must be something wrong in my custom tabbar. I did follow the docs though, and only find the instruction to emit the 'tabPress' event. I do however think that i should emit more events to get the correct focused prop. I have set up the navigator like this:
const Tabs = createBottomTabNavigator();
export default () => (
<Tabs.Navigator tabBar={TabBarComponent} initialRouteName="Home">
<Tabs.Screen
name="Home"
component={HomeScreen}
options={{
tabBarIcon: ({ focused }) => {
// The props here are {}, so focused is undefined.
const icon = focused
? require('images/iconOverviewRed.png')
: require('images/iconOverviewGrey.png');
return <Image source={icon} />;
},
}}
/>
<Tabs.Screen
name="Overview"
component={OverviewScreen}
options={{
tabBarIcon: props => {
console.log(props);
return <Image source={require('images/logoRed.png')} />;
},
}}
/>
<Tabs.Screen
name="Account"
component={AccountScreen}
options={{
tabBarIcon: ({ focused }) => {
const icon = focused
? require('images/iconAccountRed.png')
: require('images/iconAccountGrey.png');
return <Image source={icon} resizeMethod="resize" />;
},
}}
/>
</Tabs.Navigator>
);
And this is my custom tabBar compnent:
const TabBar = ({ navigation, state, descriptors }: any) => {
return (
<View style={styles.container}>
{state.routes.map((route: any) => {
const onPress = () => {
const event = navigation.emit({
type: 'tabPress',
target: route.key,
canPreventDefault: true,
});
if (!event.defaultPrevented) {
navigation.dispatch({
...TabActions.jumpTo(route.name),
target: state.key,
});
}
};
return (
<TabIcon
key={route.key}
Icon={descriptors[route.key].options.tabBarIcon}
onPress={onPress}
isBig={route.name === 'Home'}
/>
);
})}
</View>
);
};
const TabIcon = ({ onPress, Icon, key, isBig }: any) => {
return (
<TouchableWithoutFeedback key={key} onPress={onPress}>
<View style={isBig ? styles.bigTab : styles.defaultTab} key={key}>
<Icon />
</View>
</TouchableWithoutFeedback>
);
};
Thanks in advance.
descriptors[route.key].options just gives you the options as you have specified them. If you log the value of descriptors[route.key].options.tabBarIcon, you'll see that it prints the function that you have specified.
In your custom tab bar, it's upto you to use the option as you need. Since it's a function here, you'll have to call it and pass desired arguments.
descriptors[route.key].options.tabBarIcon({ focused: state.index === index })
This also means that you fully control the option. You can put whatever type you'd like, function, a require statement directly etc. and then use that. You also don't have to call it tabBarIcon, you can call it whatever you want.

Getting undefined is not an object (evaluating '_this.props.navigation')

I'm using DrawerNavigator and I have 3 pages: Router page, mainScreen and a photos page.
I maked a header navbar area and I used This <TouchableHighlight onPress={() => this.props.navigation.navigate('DrawerOpen')}> to open Drawer menu in mainScreen and used that for photos page too, menu is ok in mainScreen but when I click <TouchableHighlight onPress={() => this.props.navigation.navigate('DrawerOpen')}> in photos page, I get the error:
undefined is not an object (evaluating '_this.props.navigation')
How can I fix that?
My photos page:
import React from 'react';
import { Button, ScrollView, View, Text, StyleSheet, TouchableHighlight } from 'react-native';
import { DrawerNavigator } from 'react-navigation';
import MaterialIcons from 'react-native-vector-icons/MaterialIcons';
import Icon from 'react-native-vector-icons/FontAwesome'
const MyNavScreen = ({ navigation }) => (
<View>
<View style={styles.containerNavbar}>
<TouchableHighlight onPress={() => this.props.navigation.navigate('DrawerOpen')}>
<Icon name="bars" size={30} color="#fff" />
</TouchableHighlight>
<Text style={styles.navbarTitle}>Photos</Text>
</View>
<ScrollView>
<View><Text>photo</Text></View>
<Button onPress={() => navigation.goBack(null)} title="Go back" />
</ScrollView>
</View>
);
const MyPhotosHomeScreen = ({ navigation }) => (
<MyNavScreen navigation={navigation} />
);
MyPhotosHomeScreen.navigationOptions = {
title: 'Photos',
drawerIcon: ({ tintColor }) => (
<MaterialIcons
name="photo"
size={24}
style={{ color: tintColor }}
/>
),
};
export default MyPhotosHomeScreen;
mainScreen:
export default class MainScreen extends React.Component {
static navigationOptions = {
drawerLabel: 'Home',
drawerIcon: ({ tintColor }) => (
<MaterialIcons
name="home"
size={24}
style={{ color: tintColor }}
/>
)
};
render() {
return (
<View>
<View style={styles.containerNavbar}>
<TouchableHighlight onPress={() => this.props.navigation.navigate('DrawerOpen')}>
<Icon name="bars" size={30} color="#fff" />
</TouchableHighlight>
<Text style={styles.navbarTitle}>mainScreen</Text>
</View>
<View>
<View style={styles.containerFooter}>
<Text style={styles.footerTitle}>Footer</Text>
</View>
</View>
</View>
)
}
}
If you are using navigation in child component don't forget to send navigation in props to child
<ChildComponent navigation={this.props.navigation}/>
Access in child component like this
props.navigation.navigate("ScreenName")
Perhaps I'm overlooking something, but it just looks like a simple Javascript error. You're destructing your props in your pure component MyNavScreen:
const MyNavScreen = ({ navigation }) => (
This means that you don't have access to this.props. You just have access to the destructured prop navigation. Hence the reason for the undefined error as this really is undefined:
<TouchableHighlight onPress={() => this.props.navigation.navigate('DrawerOpen')}>
If you change it instead to use navigation directly, it should work:
<TouchableHighlight onPress={() => navigation.navigate('DrawerOpen')}>
On mainScreen, you are fine because it's not a pure component with destructured arguments. So you still have access to this.props in render().
You should brush up on destructing if this is causing you trouble.
Binding this worked for me
In my case it worked when I bind this to the method that calls the prop it in the constructor.
constructor(props){
super(props);
this.showDetails = this.showDetails.bind(this);// you should bind this to the method that call the props
}
showDetails(_id){
this.props.navigation.navigate('Details');
}
for functional components try useNavigation hook for deep navigation
Or Simply use arrow function
showDetails = (_id) => {
this.props.navigation.navigate('Details');
}
because while you use expression function it is going to create it's own scope.
Try this:
import { withNavigation } from 'react-navigation';
withNavigation serves the props all over the project/app, you access the navigation props from anywhere.
and
onPress={() => this.props.navigation.navigate('DrawerOpen')}
Finally,
export default withNavigation(MyPhotosHomeScreen);
check out this https://reactnavigation.org/docs/en/connecting-navigation-prop.html
If you use TouchableOpacity/Height in your child element, pass it this.props.onPress like this:
<TouchableOpacity onPress={this.props.onPress}/>
Then call the onPress function in your parent component like this:
<Parent onPress={this.Handlepress} />
very simple: follow some steps here
import {useNavigation} from '#react-navigation/native';
const Home =()=>{
//add this line under function scope.
const navigation = useNavigation();
return(
<TouchableOpacity onPress={() => navigation.navigate('Detail')}>
//your code.......................
)
}
This is how I have done it in React Navigation 2 release: I call the openDrawer() method from a StackNavigator that is a child navigator of the DrawerNavigator.
This is my DrawerNavigator:
export const Drawer = DrawerNavigator(
{
MyAccount: {screen: TabsStack},
});
export const TabsStack = StackNavigator({
Tabs: {
screen: Tabs, navigationOptions: ({navigation}) => ({
headerLeft: (
<TouchableOpacity style={{marginLeft: 10, marginTop: 3}}
onPress={() => navigation.openDrawer()}>
<Image source={require('./assets/menu_h.png')}/>
</TouchableOpacity>)
})
functional components take props as argument.
You should try this
const MyNavScreen = ({props}) =>
and then call the props without this key word
onPress = {() => props.navigation.navigate('DrawerOpen')}
If you want navigation in child component,then you have to get props in child component.
Suppose you have 3 components - Comp_1,Comp_2,Comp_3 and you want to navigate from Comp_2 -> Comp_3. To do this follow these steps.
Pass props in Comp_1 component.Like this
<Comp_2 navigation={this.props.navigation}/>
Now in Comp_2, we can navigate from Comp_2 -> Comp_3 like this.
this.props.navigation.navigate('Comp_3');
For example -
<Button
onPress = {() => this.props.navigation.navigate('Comp_3')}
title = 'Go to Comp_3 Screen'
/>
In then compnent that you're trying enter to another view you must send the object navigation by you use this in the onPress of component imported
example
Implementing component in a view
<CardComponent title="bla bla" navigation={this.props.navigation} />
Component template
<View>
<Button title={this.props.title} onPress={()=>
this.props.navigation.navigate("anotherAwesomeView")}/>
</View>
This problem is because the component that you're trying implement is not defined on stackNavigation, and by this the methot navigation is not avalible for you, and passing this object navigator by params you'll can access to it
For those who are not using class components and prefer functional components:
First import useNavigation then from the screen that you wish to navigate from, initiate (declare) the variable navigation = useNavigation();
import { useNavigation } from '#react-navigation/native';
function ScreenToNavigateFrom() {
const navigation = useNavigation();
return(
<TouchableOpacity onPress={() => navigation.navigate('AnotherScreen')}>
<Text style={{fontWeight: "bold", color:"white" }} >Performance</Text>
</TouchableOpacity>
);
}
This answer is courtesy of this gisthub issue: https://github.com/react-navigation/react-navigation/issues/7961
i had the same problem when i was using the header component
now you can use the navigation variable in other component like this
<TouchableOpacity onPress={() => { this.props.navigation.navigate("Play");}}>
Happy Codding :)
try this instead you might be missing to import useNavigation() from '#react-navigation/native';
import { useNavigation } from '#react-navigation/native';
function NotificationsScreen() {
const navigation = useNavigation();
return(
<Button
onPress={() => navigation.navigate('Notifications')}
title="Go to notifications"
/>
);
}
enter code here
I encountered the same problem. That's how I solved it:
Verify that all your constructors have "props" has argument
Bind the function with use the function this.props.navigation.navigate in the constructor like this: this.your_function = this.your_function.bind(this)
when you defined screen in createStackNavigator , it by default pass a props called navigation,
something like this => navigation={this.props.navigation}
but when you using this.props.navigation.navigator("YOUR SCREEN ")
and didn't defined this screen at createStackNavigator you must pass the navigation={this.props.navigation} form the screen that you defined in createStackNavigator and then you can use it in your component .
class ProductScreen extends Component {
export default ProductScreen; // make sure bottom this line mention
Call this
<TouchableOpacity
onPress = {() => this.props.navigation.navigate('ProductAddScreen')}
activeOpacity={0.7} style={styles.button}>
<Text style={styles.message}>{this.state.notFound} </Text>
</TouchableOpacity>