I have a requirement to repeat the Week-Off pattern in table2 based on given week-off frequency in table1 .
Frequency: means it could be a number with multiple of 7 only like (7 , 14 , 21 ,28 so on..)
Week-Off: for each employee week-off could be Nth rows.
Please find the SQL fiddle for demo
http://sqlfiddle.com/#!18/7cb68a/2
In given screenshot, If you have noticed "WhatIsGetting" field then it's working only for two week-off after that it's getting null bcz RuleTableTemp.ShiftId is not matching with TempMainTable.ShiftId.
I need a experts help on my requirement to repeat the week-off for given date range based on given RuleTableTemp.WeekOffFrequencyInDays.
For now in demo I have used '7' as a hard-coded value for week-off frequency like this
((te.Id / 7) + 1 )
Please find the screen shot for more clarifications.
Feel free to ask if any information is misleading or not cleared.
Note: For now I have taken only example of one employee in real scenario it could be nth employees and week-off should repeat for each employee for given date range based on given week-off frequency...
Conditions or points to remember:
RuleTableTemp: for now we have two ShiftPattern for each employee but it may vary, it could be 3 or 4 patterns too.
RuleTableTemp Filed's name WeekOffFrequencyInDays having value '7' for EmployeeId(4536) but it can also vary for each employee and yes for eg. if there are 4 entries for "4536" employee then WeekOffFrequencyInDays value will be same for all.
Example 1:
if (RuleTableTemp.WeekOffFrequencyInDays == 7 ) {
// ShiftPattern's count is 2:
// ShiftPattern will switch after every 7 days.
}
Example 2:
if ( RuleTableTemp.WeekOffFrequencyInDays == 14) {
// if ShiftPattern's count is 3:
// ShiftPattern will keep switching between 3 patterns after every 14 days
}
Example 3:
if ( RuleTableTemp.WeekOffFrequencyInDays == 21) {
// if ShiftPattern's count is 1 means no switching is required
}
I took almost 1 hour to explain my requirements but somebody still down-vote it instead of asking what was uncleared... so said to see this.... :(
This answers the original version of the question.
This logic should match the shifts:
SELECT mt.* ,
(SELECT rtt.ShiftPattern
FROM RuleTableTemp rtt
WHERE rtt.EmployeeID = mt.EmployeeId AND
rtt.id = (((mt.seqnum - 1) % 14) / 7) + 1
) as Sh
FROM (SELECT mt.*,
ROW_NUMBER() OVER (PARTITION BY mt.EmployeeId ORDER BY id) as seqnum
FROM TempMainTable mt
) mt;
Note that I added an explicit sequence number on the main table. This is just to be sure that the numbers are doing what you really want (automatically generated ids can be a problem).
The key to the logic is modulo arithmetic -- taking the remainder when the sequence number of divided by 14 and then using that for matching to the week.
Here is a db<>fiddle.
Related
I need to try to check some device IDs for work. These are values (15 characters, random string of numbers+letters) that mostly remain constant for users. However, every now and then these deviceIDs will change. And I'm trying to detect when they do change. Is there a way to write this kind of a dynamic query with SQL? Say, perhaps with a CASE statement?
user
device
date
1
23127dssds1272d
10-11
1
23127dssds1272d
10-11
1
23127dssds1272d
10-12
1
23127dssds1272d
10-12
1
04623jqdnq3000x
10-12
Count distinct device by id having count > 1?
Consider below approach
select *
from your_table
where true
qualify device != lag(device, 1, '') over(partition by user order by date)
if applied to sample data in your question - output is
As you can see here - at 10-11 first 'change, assignment' happened for user=1 ; and then on 10-12 he device changed
I have a table with the following fields
ID,Content,QuestionMarks,TypeofQuestion
350, What is the symbol used to represent Bromine?,2,MCQ
758,What is the symbol used to represent Bromine? ,2,MCQ
2425,What is the symbol used to represent Bromine?,3,Essay
2080,A quadrilateral has four sides, four angles ,1,MCQ
2614,A circular cone has a curved surface area of ,2,MCQ
2520,Two triangles have sides 5 cm, 11 cm, 2 cm . ,2,MCQ
2196,Life supporting process mediated by water? ,2,Essay
I would like to get random questions where total marks is an input number.
For example if I say 25, the result should be all the random questions whose Sum(QuestionMarks) is 25(+/-1)
Is this really possible using a SQL
select content,id,questionmarks,sum(questionmarks) from quiz_question
group by content,id,questionmarks;
Expected Input 25
Expected Result (Sum of Question Marks =25)
Update:
How do I ensure I get atleast 2 Essay Type Questions (this is just an example) I would extend this for other conditions. Thank you for all the help
S-Man's cumulative sum is the right approach. For your logic, though, I think you want to get up to the first row that is 24 or more. That logic is:
where total - questionmark < 24
If you have enough questions, then you could get exactly 25 using:
with q25 as (
select *
from (select t.*,
sum(questionmark) over (order by random()) as running_questionmark
from t
) t
where running_questionmark < 25
)
select q.ID, q.Content, q.QuestionMarks, q.TypeofQuestion
from q25 q
union all
(select t.ID, t.Content, t.QuestionMarks, t.TypeofQuestion
from t cross join
(select sum(questionmark) as questionmark_25 from q25) x
where not exists (select 1 from q25 where q25.id = t.id)
order by abs(questionmark - (25 - questionmark_25))
limit 1
)
This selects questions up to 25 but not at 25. It then tries to find one more to make the total 25.
Supposing, questionmark is of type integer. Then you want to get some records in random order whose questionmark sum is not more than 25:
You can use the consecutive SUM() window function. The order is random. The consecutive SUM() adds every current value to the previous sum. So, you could filter where SUM() <= <your value>:
demo:db<>fiddle
SELECT
*
FROM (
SELECT
*,
SUM(questionmark) OVER (ORDER BY random()) as total
FROM
t
)s
WHERE total <= 25
Note:
This returns a records list with no more than 25, but as close as possible to it with an random order.
To find an exact match of your value is some sort of combinatorical problem which shouldn't be solved in a database. Especially when there's a random factor. What if your current SUM is 22 and the next randomly chosen value is 4. Would you retry maybe until infinity to randomly find a value = 3? Or are you trying to remove an already counted record with value = 1?
I have a simple inline view that contains 2 columns.
-----------------
rn | val
-----------------
0 | A
... | ...
25 | Z
I am trying to select a val by matching the rn randomly by using the dbms_random.value() method as in
with d (rn, val) as
(
select level-1, chr(64+level) from dual connect by level <= 26
)
select * from d
where rn = floor(dbms_random.value()*25)
;
My expectation is it should return one row only without failing.
But now and then I get multiple rows returned or no rows at all.
on the other hand,
>>select floor(dbms_random.value()*25) from dual connect by level <1000
returns a whole number for each row and I failed to see any abnormality.
What am I missing here?
The problem is that the random value is recalculated for each row. So, you might get two random values that match the value -- or go through all the values and never get a hit.
One way to get around this is:
select d.*
from (select d.*
from d
order by dbms_random.value()
) d
where rownum = 1;
There are more efficient ways to calculate a random number, but this is intended to be a simple modification to your existing query.
You also might want to ask another question. This question starts with a description of a table that is not used, and then the question is about a query that doesn't use the table. Ask another question, describing the table and the real problem you are having -- along with sample data and desired results.
I have a two column table currently, with the columns 'probability' and 'age'. I have a given probability, and I need to search the table and return the age related to the closest probability. It's already in ascending order next to age, for example:
20 0.01050
21 0.02199
22 0.03155
23 0.04710
The only thing I can think of doing right now is returning all ages with probabilities greater than the given probability, and taking the first one.
select age from mydb.mytest
where probability > givenProbability;
I'm sure there is a better approach to this than doing that, so I'm wondering what that would be.
What about something like this:
SELECT * FROM mytest
ORDER BY ABS( .0750 - probability )
LIMIT 1
Should return the top 1 closest value, based on a sorted list of the Absolute value of the Difference between Probability and givenProbability.
Different solutions will work for different DBMS. This one works in DB2 and is standard sql:
select age
from (
select age
, row_number() over (order by abs(probability - givenProbability)) as rn
from mydb.mytest
)
where rn = 1
I am working on a project that keeps a track of repaired cell phones.
In the select statement, I would like to find the duplicate IMEI numbers and check if the AddedDate between the duplicates is less than 30 days. Another words, the select should list all the phones even including the duplicated IMEI numbers if the AddedDate is more than 30 days.
I hope I described it clear enough. Thank you.
Additional notes:
I have tried it by including groupBy under a sub-select which did find the duplicates, but I wasn't able to implement an if condition. Instead, I was going to place all duplicates into a dynamic table and then use a select statement against this table. Before doing so, I thought of posting my question here.
For example DB_Phones has the following rows
ID - AddedDate - IMEI
1 - 01.10.2012 - 123456789012345
2 - 15.10.2012 - 987654321012345
3 - 20.10.2012 - 123456789012345
Based on the table above, I would like to list only the second row (ID# 2) because the last duplicate (ID# 3) wasn't added 30 days after the row with the ID# 1. If rows were as below:
ID - AddedDate - IMEI
1 - 01.10.2012 - 123456789012345
2 - 15.10.2012 - 987654321012345
3 - 20.10.2012 - 123456789012345
4 - 21.11.2012 - 123456789012345
Then the second and fourth row should be returned. I need to return just one of the duplicates (last one) if the 30 day condition is met.
I hope it make more sense now. Thanks again.
A guess at what you're after:
SELECT
r.*,
(SELECT COUNT(*) FROM Repairs r2 WHERE r.IMEI = r2.IMEI
AND r.ID != r2.ID) as NumberOfAllDuplicates,
(SELECT COUNT(*) FROM Repairs r2 WHERE r.IMEI = r2.IMEI
AND ABS(DATEDIFF(day, r.AddedDate, r2.AddedDate)) < 30
AND r.ID != r2.ID) as NumberOfNearDuplicates
FROM
Repairs r
This depends on having an ID field, and everything existing in one table. With the correlated sub queries, it may not be very fast on long data.