I have a query which gives me 2 columns,
select
name as name,
code as code
from
table1
UNION
select
name as name,
code as code
from
table2
I would like to apply one more union in the result if from the above query i did not get a row with name as 'Default'. So if above query didnt have a record with default name i need to have 1 more union with above query:
select
'Default' as name,
code as code
from
table1
where condition = condition
I tried putting first query in a view and use not exists function in second query but it gives column not found error.
This is how I understood the question: lines #1 - 9 represent sample data; one of rows contains the Default name, so your resulting query should return the union-ed result as is:
SQL> with
2 table1 (name, code) as
3 (select 'Little', 1 from dual union all
4 select 'Foot' , 2 from dual
5 ),
6 table2 (name, code) as
7 (select 'Default', 3 from dual union all --> Default is here
8 select 'Oracle' , 4 from dual
9 ),
10 -- the "original" union
11 oriun as
12 (select name, code from table1
13 union
14 select name, code from table2
15 )
16 select name, code from oriun
17 union
18 select 'Default' name, null code from table1
19 where not exists (select null from oriun
20 where name = 'Default'
21 )
22 order by code;
NAME CODE
------- ----------
Little 1
Foot 2
Default 3
Oracle 4
SQL>
But, if there's no Default in those tables (see change made in line #7), then you'd get an "extra" Default row:
SQL> with
2 table1 (name, code) as
3 (select 'Little', 1 from dual union all
4 select 'Foot' , 2 from dual
5 ),
6 table2 (name, code) as
7 (select 'xxx', 3 from dual union all --> No more Default here
8 select 'Oracle' , 4 from dual
9 ),
10 -- the "original" union
11 oriun as
12 (select name, code from table1
13 union
14 select name, code from table2
15 )
16 select name, code from oriun
17 union
18 select 'Default' name, null code from table1
19 where not exists (select null from oriun
20 where name = 'Default'
21 )
22 order by code;
NAME CODE
------- ----------
Little 1
Foot 2
xxx 3
Oracle 4
Default
SQL>
When you have order by in union you need to put it inside a view or create a block with select * from (.. order by)
Related
I have a table with one column (just to simplify the problem) with values 0-23 or *.
I want to count occurrences of each value 0-23, but treat * as occurrence of all other values
for example:
column_name
-------------
3
4
5
6
7
*
4
4
3
*
I want to get something like that:
column_name | count
--------------------
1 | 2
2 | 2
3 | 4
4 | 5
5 | 3
6 | 3
7 | 3
.....
I tried experimenting with different count and "group by" methods, but always getting very strange results. Basically the main problem here is to how count rows when I need to have one value in all other groups.
You could use analytic function that counts values where * is replaced by actual value between 0 and 23:
SELECT DISTINCT n.RN "COL_1", Count(REPLACE(t.COL_1, '*', n.RN)) OVER(Partition By n.RN) "CNT"
FROM tbl t
INNER JOIN ( Select To_Char(LEVEL - 1) "RN" From Dual Connect By LEVEL <=24 ) n ON(n.RN = REPLACE(t.COL_1, '*', n.RN))
WHERE n.RN IN(SELECT COL_1 FROM tbl)
ORDER BY To_Number(n.RN)
which with your sample data:
WITH
tbl (COL_1) AS
(
Select '3' From Dual Union All
Select '4' From Dual Union All
Select '5' From Dual Union All
Select '6' From Dual Union All
Select '7' From Dual Union All
Select '*' From Dual Union All
Select '4' From Dual Union All
Select '4' From Dual Union All
Select '3' From Dual Union All
Select '*' From Dual Union All
Select '3' From Dual
)
... results as:
COL_1 CNT
---------------------------------------- ----------
3 5
4 5
5 3
6 3
7 3
... and if you exclude the Where clause you will get all the rows (0 - 23) with number of occurances counted by REPLACE of * with any of the numbers
COL_1 CNT
---------------------------------------- ----------
0 2
1 2
2 2
3 5
4 5
5 3
6 3
7 3
8 2
9 2
10 2
11 2
12 2
13 2
14 2
15 2
16 2
17 2
18 2
19 2
20 2
21 2
22 2
23 2
You can do it using successive WITH's :
First one to calculate number of occurrence of *.
And the second is to calculate number of occurrence of each number.
with cte as (
select count(1) as c
from mytable
where column_name = '*'
),
cte2 as (
select column_name, count(1) as c
from mytable, cte
group by column_name
)
select column_name, cte.c + cte2.c
from cte2, cte;
You can with nested statements too,
SELECT ID,(count_ + (
SELECT COUNT(ID) FROM sql_test_a
WHERE ID = '*')) as count_
FROM (
SELECT ID,COUNT(ID) as count_
FROM sql_test_a WHERE ID != '*' GROUP BY ID);
I tried my best to figure and google this out, but couldn't really find a solid answer to it.
The problem I'm facing is that
Table 1:
ID Value 1
1 a
2 b
3 c
Table 2:
ID Value 2
1 4a
3 5b
4 6c
and I'd basically have to select the value from Table 1 that doesn't exist on Table 2 (Thus, 'b')
I can select and identify the ID that I want by using minus function between the tables, but can't seem to figure out a way to call a query to instead call the data.
Use the MINUS as a subquery (i.e. an inline view) (lines #14 - 16):
Sample data:
SQL> with
2 table1(id, value1) as
3 (select 1, 'a' from dual union all
4 select 2, 'b' from dual union all
5 select 3, 'c' from dual
6 ),
7 table2 (id, value2) as
8 (select 1, '4a' from dual union all
9 select 3, '5b' from dual union all
10 select 4, '6c' from dual
11 )
Query begins here:
12 select a.*
13 from table1 a
14 where a.id in (select t1.id from table1 t1
15 minus
16 select t2.id from table2 t2
17 );
ID VALUE1
---------- ----------
2 b
SQL>
Alternatively, use not exists:
<snip>
12 select a.*
13 from table1 a
14 where not exists (select null
15 from table2 b
16 where b.id = a.id
17 );
ID VALUE1
---------- ----------
2 b
SQL>
I have the following table and data,
TABLE - DEAL
ID DEALID
1 DEAL1
2 DEAL2
ALL DEAL2
3 DEAL2
4 DEAL5
5 DEAL5
ALL DEAL6
I want to get only the data as below
ID DEALID
1 DEAL1
4 DEAL5
5 DEAL5
ALL DEAL6
I want to select data based on the value of id column and dealid column.
If the value of id is 'ALL' and corresponding dealid repeats, omit all records with that dealid
Based on sample data you posted, see if this helps. Read comments within code.
SQL> with
2 test (id, dealid) as
3 -- sample data
4 (select '1' , 'deal1' from dual union all
5 select '2' , 'deal2' from dual union all
6 select 'ALL', 'deal2' from dual union all
7 select '3' , 'deal2' from dual union all
8 select '4' , 'deal5' from dual union all
9 select '5' , 'deal5' from dual union all
10 select 'ALL', 'deal6' from dual
11 ),
12 all2 as
13 -- DEALIDs that contain different ID values, and MAX of them is ALL
14 (select dealid
15 from test
16 group by dealid
17 having min(id) <> max(id)
18 and max(id) = 'ALL'
19 )
20 select t.id, t.dealid
21 from test t join all2 a on a.dealid <> t.dealid;
ID DEALI
--- -----
1 deal1
4 deal5
5 deal5
ALL deal6
SQL>
Here is the table where ORGID/USERID makes unique combination:
ORGID USERID
1 1
1 2
1 3
1 4
2 1
2 5
2 6
2 7
3 9
3 10
3 11
I need to select all records (organizations and users) wherever USERID 1 is present. So USERID=1 is present in ORGID 1 and 2 so then select all users for these organizations including user 1 itself, i.e.
ORGID USERID
1 1
1 2
1 3
1 4
2 1
2 5
2 6
2 7
Is it possible to do it with one SQL query rather than SELECT *.. WHERE USERID IN (SELECT...
You could use exists:
select *
from mytable t
where exists (select 1 from mytable t1 where t1.orgid = t.orgid and t1.userid = 1)
Another option is window functions. In Postgres:
select *
from (
select t.*,
bool_or(userid = 1) over(partition by orgid) has_user_1
from mytable t
) t
where has_user_1
Or a more generic approach, that uses portable expressions:
select *
from (
select t.*,
max(case when userid = 1 then 1 else 0 end) over(partition by orgid) has_user_1
from mytable t
) t
where has_user_1 = 1
Yes, you can do it with a single select statement - no in or exists conditions, no analytic or aggregate functions in a subquery, etc. Why you want to do it that way is not clear; in any case, it is possible that the solution below is also more efficient than the alternatives. You will have to test on your real-life data to see if that is true.
The solution below has two potential disadvantages: it only works in Oracle (it uses a proprietary extension of SQL, the match_recognize clause); and it only works in Oracle 12.1 or higher.
with
my_table(orgid, userid) as (
select 1, 1 from dual union all
select 1, 2 from dual union all
select 1, 3 from dual union all
select 1, 4 from dual union all
select 2, 1 from dual union all
select 2, 5 from dual union all
select 2, 6 from dual union all
select 2, 7 from dual union all
select 3, 9 from dual union all
select 3, 10 from dual union all
select 3, 11 from dual
)
-- End of SIMULATED data (for testing), not part of the solution.
-- In real life you don't need the WITH clause; reference your actual table.
select *
from my_table
match_recognize(
partition by orgid
all rows per match
pattern (x* a x*)
define a as userid = 1
);
Output:
ORGID USERID
---------- ----------
1 1
1 2
1 3
1 4
2 1
2 5
2 7
2 6
You can use exists:
select ou.*
from orguser ou
where exists (select 1
from orguser ou ou2
where ou2.orgid = ou.orgid and ou2.userid = 1
);
Apart from Exists and windows function, you can use IN as follows:
select *
from your_table t
where t.orgid in (select t1.orgid from your_table t1 where t1.userid = 1)
I have the following problem.
I want to join two tables.
The first table has entries like the following:
T1
PK Info
1 one
2 two
3 three
The second table is build like this:
T2
PK FKT1
1 1,3
2 1,2,3
3 2
My Result should show the following
PK2 FKT1 InfoT1
1 1,3 One,Three
2 1,2,3 One,two,Three
3 2 Two
I just cant get an idea how to solve this.
Is this possible only using sql selects or is a function needed?
kind regards
It's not that difficult, but - as you were told, you'd rather NOT do that.
SQL> with
2 t1 (pk, info) as
3 (select 1, 'one' from dual union
4 select 2, 'two' from dual union
5 select 3, 'three' from dual
6 ),
7 t2 (pk, fkt1) as
8 (select 1, '1,3' from dual union
9 select 2, '1,2,3' from dual union
10 select 3, '2' from dual
11 ),
12 t2rows as
13 (select pk, regexp_substr(fkt1, '[^,]+', 1, column_value) fkt1, column_value rn
14 from t2,
15 table(cast(multiset(select level from dual
16 connect by level <= regexp_count(fkt1, ',') + 1
17 ) as sys.odcinumberlist))
18 )
19 select t2r.pk,
20 listagg(t2r.fkt1, ',') within group (order by t2r.rn) fkt1,
21 listagg(t1.info, ',') within group (order by t2r.rn) infot1
22 from t2rows t2r join t1 on t2r.fkt1 = t1.pk
23 group by t2r.pk
24 order by t2r.pk;
PK FKT1 INFOT1
---------- -------------------- --------------------
1 1,3 one,three
2 1,2,3 one,two,three
3 2 two
SQL>