Extract a part of string between multiple delimiters - sql

Question

I have a column with value as '/1064_MyHoldings/ONLINE/Adhoc/Rpt_CompanyCodeElig'
Now, my requirement is to extract every value which is there between the delimeters; '1064 MyHoldings', 'ONLINE', 'Adhoc' etc?
I tried the below code, but it is only taking '1064 MyHoldings'. But I need the other values as well
Can someone please help me here?
WITH yourTable AS (
SELECT '/1064_MyHoldings/ONLINE/Adhoc/Rpt_CompanyCodeElig' AS Path
)
SELECT
CASE WHEN Path LIKE '%/%/%' THEN
SUBSTRING(Path,
CHARINDEX('/', Path) + 1,
CHARINDEX('/', Path, CHARINDEX('/', Path) + 1) - CHARINDEX('/', Path) - 1)
ELSE 'NA' END AS first_component
FROM yourTable;

Answer 1

Use string_split():
select s.value
from t cross apply
string_split(path, '/') s

Answer 2

You can go for recursive search using CTE and split the strings.
WITH yourTable AS (
SELECT '/1064_MyHoldings/ONLINE/Adhoc/Rpt_CompanyCodeElig' AS Path
),
cte_splitTable as
(
SELECT value as val, 1 as lvl
from yourTable
cross apply
string_split(Path,'_')
UNION ALL
SELECT t.value as val, lvl+1 as lvl
from cte_splitTable as c
cross apply
string_split(c.val,'/') as t
where CHARINDEX('/',val) > 0
)
select * from cte_splitTable
where PATINDEX('%[_/]%',val) = 0 and len(val) > 0
+-----------------+
| val |
+-----------------+
| CompanyCodeElig |
| MyHoldings |
| ONLINE |
| Adhoc |
| Rpt |
| 1064 |
+-----------------+