I'm stumped as in how to do this.
I have 3 columns the first is a parent company, second is the child and the third is it's revenue. I want to find out which child per parent has the most revenue and what that revenue is.
So like the below
Vodafone. Argentina. 5b
Vodafone. Spain. 4b
Vodafone. England. 10b
So the answer would be
Vodafone. England 10b
Apologies for the formatting, on my phone.
You can use row_number(). Here is the demo.
select
company,
child,
revenue
from
(
select
*,
row_number() over (partition by company order by cast(revenue as int) desc) as rn
from yourTable
) subq
where rn = 1
output:
| company | child | revenue |
| -------- | ------- | ------- |
| Vodafone | England | 10 |
You can use dense_rank() if more than one company have same revenue.
You can try the below one -
select * from tablename
where cast(revenue as int) = (select max(cast(revenue as int)) from tablename)
Related
I have a table that contains customer transactions. It looks like this:
Tha data is sorted by Total Transaction. I want to create a column that contains number by City. For Example, the first row shows City is London so the values is 1, second row becaus it's from London too, the value is also 1. When the Next Row is not London, the value is 2. So it looks like this:
Is there a way to create that row number in SQL Server?
You can try using dense_rank()
select *,dense_rank() over(order by city) as cityNumber
from tablename
order by total_transaction desc
I believe the question is valid and as per my understanding on the requirement , you need a two level of sub query to get to the final result,
Here I have used max as the data first has to be sorted by Total Transaction and then we can use dense_rank to give a row number using the max value and city.
select t.city as "City"
,dense_rank() over (order by max_total_per_city desc,city) as "City Number"
,t.customer as "Customer"
,t.total_transaction as "Total Transaction"
from
(
select *
,max(total_transaction) over (partition by city) as max_total_per_city
from tableName t
) t
order by total_transaction desc
You can get the CityNumbers with ROW_NUMBER() window function:
select City, row_number() over (order by max(TotalTransaction) desc) CityNumber
from tablename
group by City
so you can join the above query to the table:
select t.City, c.CityNumber, t.Customer, t.Totaltransaction
from tablename t inner join (
select City, row_number() over (order by max(TotalTransaction) desc) CityNumber
from tablename
group by City
) c on c.City = t.City
order by t.TotalTransaction desc
Or with DENSE_RANK() window function:
select t.City,
dense_rank() over (order by (select max(TotalTransaction) from tablename where City = t.City) desc) as cityNumber,
t.Customer,
t.TotalTransaction
from tablename t
order by t.TotalTransaction desc
See the demo.
Results:
> City | CityNumber | Customer | Totaltransaction
> :--------- | ---------: | :------- | ---------------:
> London | 1 | Michael | 250
> London | 1 | Edward | 180
> Paris | 2 | Michael | 160
> Madrid | 3 | Luis | 153
> London | 1 | Serena | 146
> Madrid | 3 | Lionel | 133
> Manchester | 4 | Frank | 96
I have a set of sorted line items. They are sorted first by ID then by Date:
| ID | DESCRIPTION | Date |
| --- | ----------- |----------|
| 100 | Red |2019-01-01|
| 101 | White |2019-01-01|
| 101 | White_v2 |2019-02-01|
| 102 | Red_Trim |2019-01-15|
| 102 | White |2019-01-16|
| 102 | Blue |2019-01-20|
| 103 | Red_v3 |2019-01-14|
| 103 | Red_v3 |2019-03-14|
I need to insert rows in a SQL Server table, which represents a project header, so that the first row for each ID provides the Description and Date in the destination table. There should only be one row in the destination table for each ID.
For example, the source table above would result in this at the destination:
| ID | DESCRIPTION | Date |
| --- | ----------- |----------|
| 100 | Red |2019-01-01|
| 101 | White |2019-01-01|
| 102 | Red_Trim |2019-01-15|
| 103 | Red_v3 |2019-01-14|
How do I collapse the source so that I take only the first row for each ID from source?
I prefer to do this with a transformation in SSIS but can use SQL if necessary. Actually, solutions for both methods would be most helpful.
This question is distinct from Trouble using ROW_NUMBER() OVER (PARTITION BY …)
in that this seeks to identify an approach. The asker of that question has adopted one approach, of more than one available as identified by answers here. That question is about how to make that particular approach work.
You can use row_number() :
select t.*
from (select t.*, row_number() over (partition by id order by date) as seq
from table t
) t
where seq = 1;
A correlated subquery will help here:
SELECT *
FROM yourtable t1
WHERE [Date] = (SELECT min([Date]) FROM yourtable WHERE id = t1.id)
use first_value window function
select * from (select *,
first_value(DESCRIPTION) over(partition by id order by Date) as des,
row_number() over(partition by id order by Date) rn
from table
) a where a.rn =1
You can use the ROW_NUMBER() window function to do this. For example:
select *
from (
select
id, description, date,
row_number() over(partition by id order by date) as rn
from t
)
where rn = 1
Come up against an issue where I want to summarize results in a query.
Example as follows:
NAME | FRUIT | PRICE
-----+-------+------
JOHN | APPLE | 2
JOHN | APPLE | 2
JOHN | APPLE | 2
JOHN | APPLE | 2
DAVE | GRAPE | 3
DAVE | GRAPE | 3
DAVE | GRAPE | 3
This is my table at the moment, what i need though is to have a summary of Johns business, like below:
NAME | FRUIT | PRICE
-----+-------+------
JOHN | APPLE | 2
JOHN | APPLE | 2
JOHN | APPLE | 2
JOHN | APPLE | 2
JOHN | TOTAL | 8
DAVE | GRAPE | 3
DAVE | GRAPE | 3
DAVE | GRAPE | 3
DAVE | TOTAL | 9
I have tried to group the information but it does not reflect what i want, plus if John were to have different fruit it would need to sum that up before it sums up the next part and it needs to have a running total for all values in the NAME field as there will be a number of customers.
Any advice would be great
EDIT
I have tried using Rollup but I keep getting totals of all values in a seperate column where as I would like to see it as the way it is formatted above
A solution with UNION and GROUP BY.
;WITH PricesWithTotals AS
(
SELECT
Name,
Fruit,
Price
FROM
YourTable
UNION ALL
SELECT
Name,
Fruit = 'TOTAL',
Price = SUM(Price)
FROM
YourTable
GROUP BY
Name
)
SELECT
Name,
Fruit,
Price
FROM
PricesWithTotals
ORDER BY
Name,
CASE WHEN Fruit <> 'Total' THEN 1 ELSE 999 END ASC,
Fruit
This will get you a running total per customer per fruit:
create table #Sales([Name] varchar(20), Fruit varchar(20), Price int)
insert into #Sales([Name], Fruit, Price)
values
('JOHN','APPLE',2),
('JOHN','APPLE',2),
('JOHN','APPLE',2),
('JOHN','APPLE',2),
('DAVE','GRAPE',3),
('DAVE','GRAPE',3),
('DAVE','GRAPE',3)
Select c.*
, SUM(Price) OVER (PARTITION BY c.[Name], c.[Fruit] ORDER BY c.[Name], c.[Fruit] rows between unbounded preceding and current ROW ) as RunningTotal
from #Sales c
order by c.[Name], c.[Fruit] asc
drop table #Sales
Output:
The solution to your problem is GROUPING SETS. However, your rows are not unique. Alas, so this adds a unique value, just so you can keep your original rows:
with t as (
select t.*, row_number() over (order by (select null)) as seqnum
from t
)
select name, ,
coalesce(fruit, 'Total') as fruit,
sum(price) as price
from t
group by grouping sets ( (name, fruit, seqnum), (name) )
order by name,
(case when fruit is not null then 1 else 2 end);
I have the following code for example:
SELECT id, order_day, purchase_id FROM d
customer_id and purchase_id are unique. Each customer_id could have multiple purchase_id. Assume every one has made at least 5 orders.
Now, I just want to pull the first 5 purchase IDs of each customers ID (this depends on the earliest dates of purchases). I want the result to look like this:
id | purchase_id | rank
-------------------------
A | WERFEW43 | 1
A | ERTGDSFV | 3
A | FDGRT45 | 2
A | BRTE4TEW | 4
A | DFGDV | 5
B | DSFSF | 1
B | CF345 | 2
B | SDFSDFSDFS | 4
I thought of Ranking order_day, but my knowledge is not good enough to pull this off.
select id,purchase_id, rank() over (order by order_day)
from d
you also can try dense_rank() over (order by order_day) and row_number() over (order by order_day) and choose which one will be more suitable for you
select *
from
( SELECT
id
,order_day
,purchase_id
,row_number() -- ranking
over (partition by id -- each customer
order by order_day) as rn -- based on oldest dates
FROM d
) as dt
where rn <= 5
I have the following table :
+----------+------+
| country | event |
+----------+-----------+
| usa | running |
| usa | running |
| usa | running |
| canada | running |
| Canada | running |
| usa | javline |
| canada | javline |
| canada | javline |
| canada | javline |
+----------+-----------+
I want to get the following out by sql query:
USA | Running | 3
Canada | Javline | 3
i tried using the following query on MS sql server :
select country, case when c > 1 then null else event end event
from (select country, [ModelName], recs, count(*) over (partition by event, recs ) c,
row_number() over (partition by country order by recs desc) rn
from (select country, event, count(*) recs
from table
group by country, event) )
where rn = 1
order by 1
But I get an error :
Msg 102, Level 15, State 1, Line 12
Incorrect syntax near ')'.
Any pointers to correct solution is appreciated. Thanks.
You need to put an alias on your subquery:
select
country,
case when c > 1 then null else event end event
from (
select -- No event here
country,
[ModelName],
recs,
count(*) over (partition by event, recs ) c,
row_number() over (partition by country order by recs desc) rn
from (
select country, event, count(*) recs -- No ModelName here
from [table]
group by country, event
) x -- You need to put an alias here
)t -- and here
where rn = 1
order by 1
Note that the above query will still produce errors:
Invalid column name 'ModelName'.
Invalid column name 'event'.
This is because ModelName is not included in your innermost subquery and event is not included in the outermost subquery.
Based on your sample data, you can use this query to achieve the desired result:
;WITH Cte AS(
SELECT Country, Event, COUNT(*) AS CC
FROM [Table]
GROUP BY Country, Event
)
,CteRowNumber AS(
SELECT *,
RN = ROW_NUMBER() OVER(PARTITION BY Country ORDER BY CC DESC)
FROM Cte
)
SELECT Country, Event, CC
FROM CteRowNumber
WHERE RN = 1
You could do it using window function inside a cte:
-- this counts a number per each country and event
with q as(
select country,event,
row_number() over(partition by country,event order by country) r
from your_table t
)
--this takes only the maximum of them
select *
from q
where r=(select max(r)
from q q2
where q2.country=q.country)
Result:
| country | event | r |
|---------|---------|---|
| canada | javline | 3 |
| usa | running | 3 |