Make a report on the sales in 2015 of the products by categories (total value and
quantity sold). Also determine what% of the value of sales
for a given category represent the sales of each of the products in the category.
My query so far:
WITH sales AS
(SELECT t1.category_name
, t2.product_name
, (t3.unit_price*t3.quantity) Total_sales
, EXTRACT (YEAR FROM order_date) Year
FROM categories t1
INNER JOIN
products t2
ON t2.category_id=t1.category_id
INNER JOIN
order_details t3
ON t3.product_id=t2.product_id
INNER JOIN
orders t4
ON t4.order_id=t3.order_id
WHERE EXTRACT (YEAR FROM order_date) = '2015'
GROUP BY t1.category_name
, t2.product_name
, (t3.unit_price*t3.quantity)
, EXTRACT (YEAR FROM order_date)
ORDER BY 1
)
SELECT s.category_name
, s.product_name
, SUM (Total_sales)
FROM sales s
GROUP BY s.category_name
, s.product_name
ORDER BY 1
How to calculate %? Thank you
I think that you want window functions - if your database, that you did not specify, supports them:
SELECT
c.category_name
p.product_name
SUM(od.unit_price * od.quantity) as total_sales
1.0 * SUM(od.unit_price * od.quantity)
/ SUM(SUM(od.unit_price * od.quantity)) OVER(PARTITION BY c.category_id)
as category_sales_ratio
FROM categories c
INNER JOIN products t2 p ON p.category_id = c.ategory_id
INNER JOIN order_details od ON od.product_id = p.product_id
INNER JOIN orders o ON o.order_id = od.order_id
WHERE o.order_date >= '2015-01-01' AND o.order_date < '2016-01-01'
GROUP BY c.category_id, c.ategory_name, p.product_id, p.product_name
ORDER BY c.category_name, p.product_name
The window sum computes the total sales for the whole category, that you can divide the sales of the current product with.
Note that I changed your query in serveral ways:
meaningful table aliases make the query easier to write, read and maintain
filtering dates without transformation is much more efficient that using date functions
there is no need for a subquery
it is always a good idea to put the relevant primary keys in the GROUP BY clause (in case two different products or categories have the same name) - on the other hand, you also had additiona uneeded columns in that clause
Related
I am trying to add a new column to my table which will be the average value calculated as the division of two existing columns. Therefore Average value = Total Sales / Number of Orders.
My data looks like this:click to view picture
I don't understand why Example Code A does not work but Example Code B does. Please can someone explain?
Example Code A
%%sql
SELECT
c.country,
count(distinct c.customer_id) customer_num,
count(i.invoice_id) order_num,
ROUND(SUM(i.total),2) total_sales,
order_num / total_sales avg_order_value
FROM customer c
LEFT JOIN invoice i ON c.customer_id = i.customer_id
GROUP BY 1
ORDER BY 4 DESC;
Example Code B
%%sql
WITH
customer_sales AS
(
SELECT
c.country,
count(distinct c.customer_id) customer_num,
count(i.invoice_id) order_num,
ROUND(SUM(i.total),2) total_sales
FROM customer c
LEFT JOIN invoice i ON c.customer_id = i.customer_id
GROUP BY 1
ORDER BY 4 DESC
)
SELECT
country,
customer_num,
order_num,
total_sales,
total_sales / order_num avg_order_value
FROM customer_sales;
Thank you!
Depending on the DBMS some allow you to reference the alias in the calculation (in the same select) and others require you to either bring it outside in an outer query or state your previous aggregation/functions, such as counts or sums.
SELECT
c.country,
count(distinct c.customer_id) customer_num,
count(i.invoice_id) order_num,
ROUND(SUM(i.total),2) total_sales,
count(i.invoice_id) / ROUND(SUM(i.total),2) avg_order_value
FROM customer c
LEFT JOIN invoice i ON c.customer_id = i.customer_id
GROUP BY 1
ORDER BY 4 DESC;
I have 3 tables (production, sales, wastage)
All 3 tables have the columns: Product and Quantity
I need a query statement that will join all 3 tables in the following manner:production - sales - wastage Grouped by Product
Thanks in advance for the tips and tricks :)
Combine tables using left join, group by product and get total quantity by substracting values assuming that there can be no record for a given product within sales or wastage tables and then count them as 0.
select p.product, sum(p.quantity - coalesce(s.quantity,0) - coalesce(w.quantity,0)) as qty
from production p
left join sales s on p.product = s.product
left join wastage w on p.product = w.product
group by p.product
You can group each table individually and then [left] join them:
SELECT p.product, p_quantity - COALESCE(s_quantity, 0) - COALESCE(w_quantity, 0)
FROM (SELECT product, SUM(quantity) AS p_quantity
FROM production
GROUP BY product) p
LEFT JOIN (SELECT product, SUM(quantity) AS s_quantity
FROM sales
GROUP BY product) s ON p.product = s.product
LEFT JOIN (SELECT product, SUM(quantity) AS w_quantity
FROM wastage
GROUP BY product) w ON p.product = w.product
Product1
Purchase quantity from 3 invoices are 50+100+50 = 200 and
Sale quantity from 1 invoice is 10
I am using below code for getting the result as
Total Purchase - Total Sale = Closing Qty
200 - 10 = 290
but I am getting the wrong result as shown in the attached image:
Please guide me to correct my code
SELECT
P.PRODUCT as PRODUCTNAME,
P.QUANTITY AS PURCHASE,
ISNULL(S.QUANTITY, 0) AS SALE,
ISNULL(P.QUANTITY, 0) - ISNULL(s.QUANTITY, 0) AS CLOSINGQTY
FROM
[PurchaseData] P
LEFT OUTER JOIN
[DeliveryData1] S ON P.Product = s.PRODUCT
When working with aggregates from different tables, don't join the tables and aggregate then, but aggregate first and join the aggregates:
select
p.product as productname,
p.sum_quantity as purchase,
coalesce(s.sum_quantity, 0) as sale,
p.sum_quantity - coalesce(s.sum_quantity, 0) as closingqty
from
(
select product, sum(quantity) as sum_quantity
from purchasedata
group by product
) p
left join
(
select product, sum(quantity) as sum_quantity
from deliverydata1
group by product
) s on s.product = p.product;
I've replaced ifnull with coalesce, so the query is fully standard SQL compliant.
If you want the final result you should use sum and group by
SELECT
P.PRODUCT as PRODUCTNAME,
sum(P.QUANTITY AS PURCHASE),
sum(isnull(S.QUANTITY,0)) AS SALE,
sum(isnull(P.QUANTITY,0))-sum(isnull(s.QUANTITY,0)) AS CLOSINGQTY
FROM [PurchaseData] P LEFT OUTER JOIN [DeliveryData1] S ON P.Product = s.PRODUCT
GROUP BY P.PRODUCT
If I understand correctly, you have a problem because you have multiple purchase records for a given product. If that is the case, then just aggregate before the JOIN:
SELECT p.*, COALESCE(S.QUANTITY, 0) AS SALE,
COALESCE(P.QUANTITY, 0)-COALESCE(s.QUANTITY, 0) AS CLOSINGQTY
FROM (SELECT p.product, p.quantity
FROM PurchaseData P
GROUP BY p.product
) p LEFT OUTER JOIN
DeliveryData1 S
ON P.product = s.producct;
Actually, I'm unclear which of the two tables has the duplicates -- or even if both do. So, you might need to do something similar for S.
I am pretty new to using MS SQL 2012 and I am trying to create a query that will:
Report the order id, the order date and the employee id that processed the order
report the maximum shipping cost among the orders processed by the same employee prior to that order
This is the code that I've come up with, but it returns the freight of the particular order date. Whereas I am trying to get the maximum freight from all the orders before the particular order.
select o.employeeid, o.orderid, o.orderdate, t2.maxfreight
from orders o
inner join
(
select employeeid, orderdate, max(freight) as maxfreight
from orders
group by EmployeeID, OrderDate
) t2
on o.EmployeeID = t2.EmployeeID
inner join
(
select employeeid, max(orderdate) as mostRecentOrderDate
from Orders
group by EmployeeID
) t3
on t2.EmployeeID = t3.EmployeeID
where o.freight = t2.maxfreight and t2.orderdate < t3.mostRecentOrderDate
Step one is to read the order:
select o.employeeid, o.orderid, o.orderdate
from orders o
where o.orderid = #ParticularOrder;
That gives you everything you need to go out and get the previous orders from the same employee and join each one to the row you get from above.
select o.employeeid, o.orderid, o.orderdate, o2.freight
from orders o
join orders o2
on o2.employeeid = o.employeeid
and o2.orderdate < o.orderdate
where o.orderid = #ParticularOrder;
Now you have a whole bunch of rows with the first three values the same and the fourth is the freight cost of each previous order. So just group by the first three fields and select the maximum of the previous orders.
select o.employeeid, o.orderid, o.orderdate, max( o2.freight ) as maxfreight
from orders o
join orders o2
on o2.employeeid = o.employeeid
and o2.orderdate < o.orderdate
where o.orderid = #ParticularOrder
group by o.employeeid, o.orderid, o.orderdate;
Done. Build your query in stages and many times it will turn out to be much simpler than you at first thought.
It is unclear why you are using t3. From the question it doesn't sound like the employee's most recent order date is relevant at all, unless I am misunderstanding (which is absolutely possible).
I believe the issue lies in t2. You are grouping by orderdate, which will return the max freight for that date and employeeid, as you describe. You need to calculate a maximum total from all orders that occurred before the date that the order occurred on, for that employee, for every row you are returning.
It probably makes more sense to use a subquery for this.
SELECT o.employeeid, o.orderid, o.orderdate, m.maxfreight
FROM
orders o LEFT OUTER JOIN
(SELECT max(freight) as maxfreight
FROM orders AS f
WHERE f.orderdate <= o.orderdate AND f.employeeid = o.employeeid
) AS m
Hoping this is syntactically correct as I'm not in front of SSMS right now. I also included a left outer join as your previous query with an inner join would have excluded any rows where an employee had no previous orders (i.e. first order ever).
You can do what you want with a correlated subquery or apply. Here is one way:
select o.employeeid, o.orderid, o.orderdate, t2.maxfreight
from orders o outer apply
(select max(freight) as maxfreight
from orders o2
where o2.employeeid = o.employeid and
o2.orderdate < o.orderdate
) t2;
In SQL Server 2012+, you can also do this with a cumulative maximum:
select o.employeeid, o.orderid, o.orderdate,
max(freight) over (partition by employeeid
order by o.orderdate rows between unbounded preceding and 1 preceding
) as maxfreight
from orders o;
I have been trying to solve this problem for a lot of days. But wouldn't. Please help me.
I need a SQL to list product_code, product_name, qty_sold, last_order_date for all the products that have been sold within a date range sorted by the number of quantity sold.
My Table structure:
tbl_product(product_id,product_code,product_name)
tbl_order_detail(order_item_id,order_id,product_id,quantity)
tbl_order(order_id,order_date)
You could use group by to calculate statistics per product. Then you can use sum and max to retrieve the aggregate information required. For example:
select p.product_code
, p.product_name
, sum(od.quantity) as qty_sold
, max(o.order_date) as last_order_date
from tbl_product p
join tbl_order_detail od
on p.product_id = od.product_id
join tbl_order o
on od.order_id = o.order_id
where o.order_date between '2010-01-01' and '2010-02-01'
group by
p.product_code
, p.product_name
order by
sum(od.quantity) desc
select
p.product_code, p.product_name, sum(od.quantity) as qty_sold, max(o.order_date) as last_order_date
from tbl_product p join tbl_order o join tbl_order_detail od on
(p.product_id=o.product_id, o.order_id = od.order_id)
where
order_date between :first_day: and :last_day:
group by product_code, product_name
order by last_order_date
Sorry I can't test this right now.
Keypoints are: use the group by clause to aggregate the quantity and order date values, and use max and sum to find the desired values.
:first_day: and :last_day: are placeholders for the actual values
Hope I helped you