I have a table which follows the state of the item delivery:
ID | ContractID | State
----------------------------------
1 | 125 | Created
2 | 125 | Activated
3 | 125 | PickupStarted
4 | 125 | PickedUp
5 | 125 | DeliveryStarted
6 | 125 | Delivered
7 | 126 | Created
8 | 126 | Activated
9 | 126 | PickupStarted
10 | 126 | PickedUp
11 | 126 | DeliveryStarted
12 | 126 | Delivered
13 | 127 | Created
14 | 127 | Activated
15 | 127 | PickupStarted
16 | 127 | PickedUp
I would like to create SQL query which counts only those 'ContractIds' which are not delivered yet (only those whose current status has reached 'PickedUp' status). In this case that would be 'ContractId' 127.
Is there a way to do that type of COUNT()?
You can use not exists:
select count(distinct contractId)
from t
where not exists (select 1
from t t2
where t2.contractId = t.contractid and
t2.status not like 'Deliver%'
);
Or, if you specifically want to get PickedUp as the last status:
select count(*)
from t
where t.id = (select max(t2.id) from t t2 2here t2.contractid = t.contractid) and
t.status = 'PickedUp';
The two are different. The second is specifically that the last status is PickedUp. The first is anyone that has not reached a "deliver" status.
Related
I'm trying to write an SQL query (SQL Server) that returns the latest value of a field from a history table.
The table structure is basically as below:
ISSUE TABLE:
issueid
10
20
30
CHANGEGROUP TABLE:
changegroupid | issueid | updated |
1 | 10 | 01/01/2020 |
2 | 10 | 02/01/2020 |
3 | 10 | 03/01/2020 |
4 | 20 | 05/01/2020 |
5 | 20 | 06/01/2020 |
6 | 20 | 07/01/2020 |
7 | 30 | 04/01/2020 |
8 | 30 | 05/01/2020 |
9 | 30 | 06/01/2020 |
CHANGEITEM TABLE:
changegroupid | field | newvalue |
1 | ONE | 1 |
1 | TWO | A |
1 | THREE | Z |
2 | ONE | J |
2 | ONE | K |
2 | ONE | L |
3 | THREE | K |
3 | ONE | 2 |
3 | ONE | 1 | <--
4 | ONE | 1A |
5 | ONE | 1B |
6 | ONE | 1C | <--
7 | ONE | 1D |
8 | ONE | 1E |
9 | ONE | 1F | <--
EXPECTED RESULT:
issueid | updated | newvalue
10 | 03/01/2020 | 1
20 | 07/01/2020 | 1C
30 | 06/01/2020 | 1F
So each change to an issue item creates 1 change group record with the date the change was made, which can then contain 1 or more change item records.
Each change item shows the field name that was changed and the new value.
I then need to link those tables together to get each issue, the latest value of the field name called 'ONE', and ideally the date of the latest change.
These tables are from Jira, for those familiar with that table structure.
I've been trying to get this to work for a while now, so far I've got this query:
SELECT issuenum, MIN(created) AS updated FROM
(
SELECT ISSUE.IssueId, UpdGrp.Created as Created, UpdItm.NEWVALUE
FROM ISSUE
JOIN ChangeGroup UpdGrp ON (UpdGrp.IssueID = CR.ID)
JOIN CHANGEITEM UpdItm ON (UpdGrp.ID = UpdItm.groupid)
WHERE UPPER(UpdItm.FIELD) = UPPER('ONE')
) AS dummy
GROUP BY issuenum
ORDER BY issuenum
This returns the first 2 columns I'm looking for but I'm struggling to work out how to return the final column as when I include that in the first line I get an error saying "Column is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause."
I've done a search on here and can't find anything that exactly matches my requirements.
Use window functions:
SELECT i.*
FROM (SELECT i.IssueId, cg.Created as Created, ui.NEWVALUE,
ROW_NUMBER() OVER (PARTITION BY i.IssueId ORDER BY cg.Created DESC) as seqnum
FROM ISSUE i JOIN
ChangeGroup cg
ON cg.IssueID = CR.ID JOIN
CHANGEITEM ci
ON cg.ID = ci.groupid
WHERE UPPER(UpdItm.FIELD) = UPPER('ONE')
) i
WHERE seqnum = 1
ORDER BY issueid;
I have following 3 tables and last entered reasoncode from Reasons table against each claimno in claims table.
Reasons:
Rid |chargeid| enterydate user reasoncode
-----|--------|-------------|--------|----------
1 | 210 | 04/03/2018 | john | 99
2 | 212 | 05/03/2018 | juliet | 24
5 | 212 | 26/12/2018 | umar | 55
3 | 212 | 07/03/2018 | borat | 30
4 | 211 | 03/03/2018 | Juliet | 20
6 | 213 | 03/03/2018 | borat | 50
7 | 213 | 24/12/2018 | umer | 60
8 | 214 | 01/01/2019 | john | 70
Charges:
chargeid |claim# | amount
---------|-------|---------
210 | 1 | 10
211 | 1 | 24.2
212 | 2 | 5.45
213 | 2 | 76.30
214 | 1 | 2.10
Claims:
claimno | Code | Code
--------|-------|------
1 | AH22 | AH22
2 | BB32 | BB32
Expected result would be like this:
claimno | enterydate | user | reasoncode
--------|-------------|--------|-----------
1 | 01/01/2019 | john | 70
2 | 26/12/2018 | umer | 55
I have applied many solutions but no luck. Following is the latest solution I was trying using SQL Server 2008 but still got incorrect result.
With x As
(
select r.chargeid,r.enterydate,ch.claimno from charges ch
join (select chargeid,max(enterydate) enterydate,user from Reasons group by chargeid) r on r.chargeid = ch.chargeid
)
select x.*,r1.user, r1.reasoncode from x
left outer join Reasons r1 on r1.chargeid = x.chargeid and r1.enterydate = x.enterydate
--group by x.claimno
Is this what you want?
select claimno, enterydate, user, reasoncode
from (select c.claimno, r.*,
row_number() over (partition by c.claimno order by r.entrydate desc) as seqnum
from charges c join
reasons r
on c.chargeid = r.chargeid
) cr
where seqnum = 1;
You can try using row_number()
select * from
(
select r.chargeid,r.enterydate,ch.claimno,user,reasoncode,
row_number() over(partition by ch.claimno order by r1.enterydate desc) as rn
from charges ch left outer join Reasons r1 on r1.chargeid = ch.chargeid
)A where rn=1
I have 2 tables shown below:
Table 1
Student ID - DATE_NO - SCORE
Table 2
STUDENT_ID - DATE_NO - HT - WT
Table 1 has the physical test scores and the date of the test for each student while Table 2 lists their height (HT) and weight (WT) and the date they were measured.
Example Data:
Table 1
Student ID | DATE_NO | SCORE |
125 | 3 | 90 |
572 | 6 | 75 |
687 | 11 | 95 |
Table 2
Student_ID | DATE_NO | HT | WT |
125 | 2 | 70 | 150 |
125 | 3 | 72 | 155 |
125 | 6 | 72 | 160 |
572 | 2 | 70 | 200 |
572 | 5 | 70 | 225 |
572 | 8 | 70 | 215 |
572 | 9 | 70 | 220 |
687 | 4 | 65 | 140 |
687 | 7 | 67 | 150 |
687 | 11 | 70 | 155 |
687 | 12 | 67 | 160 |
I am not guaranteed to have the exact same DATE_NO for both HT/WT and the Test score date. I want the most recent HT and WT for each student when they took their physical test. Based on the example data above, the optimal join would give me the table below:
Modified Table 1
Student ID | DATE_NO | HT | WT |
125 | 3 | 72 | 155 |
572 | 6 | 70 | 225 |
687 | 11 | 70 | 155 |
I'd like to use the UPDATE statement on Table 1, so after altering Table 1 with HT int and WT int, I attempt to do the following:
UPDATE T1
SET HT = T2.HT, WT = T2.WT
FROM Table_1 as T1
INNER JOIN Table_2 AS T2 ON T1.STUDENT_ID = T2.STUDENT_ID
WHERE (T1.DATE_NO) >= (T2.DATE_NO)
But the result gives me the FIRST record that meets the criteria. Switching greater than to less than [ >= to <= ] Make the HT/WT for each student the entries for Month 6,8, and 12) when it should be month 3,8, and 11. Any suggestions?
FYI: Won't be able to apply any solutions till Friday.
Is it something like this you're looking for:
UPDATE Q
SET
T1_HT = T2_HT
, T1_WT = T2_WT
FROM
(
SELECT
T1.HT T1_HT
, T1.WT T1_WT
, T2.HT T2_HT
, T2.WT T2_WT
, ROW_NUMBER() OVER (PARTITION BY T1.STUDENT_ID ORDER BY T2.DATE_NO DESC) R
FROM
Table_1 T1
JOIN Table_2 T2 ON
T1.STUDENT_ID = T2.STUDENT_ID
AND T2.DATE_NO <= T1.DATE_NO
) Q
WHERE R = 1
SELECT ts.student_id,
ts.date_no,
hw.ht,
hw.wt
FROM test_scores ts,
ht_wt hw
WHERE hw.student_id = ts.student_id
AND hw.date_no <= ts.date_no
AND hw.date_no =
(SELECT max(date_no)
FROM ht_wt
WHERE date_no <= ts.date_no
AND student_id = ts.student_id)
sql fiddle here
I have a table. It has a pk of id and an index of [service, check, datetime].
id service check datetime score
---|-------|-------|----------|-----
1 | 1 | 4 |4/03/2009 | 399
2 | 2 | 4 |4/03/2009 | 522
3 | 1 | 5 |4/03/2009 | 244
4 | 2 | 5 |4/03/2009 | 555
5 | 1 | 4 |4/04/2009 | 111
6 | 2 | 4 |4/04/2009 | 322
7 | 1 | 5 |4/05/2009 | 455
8 | 2 | 5 |4/05/2009 | 675
Given a service 2 I need to select the rows for each unique check where it has the max date. So my result would look like this table.
id service check datetime score
---|-------|-------|----------|-----
6 | 2 | 4 |4/04/2009 | 322
8 | 2 | 5 |4/05/2009 | 675
Is there a short query for this? The best I have is this, but it returns too many checks. I just need the unique checks at it's latest datetime.
SELECT * FROM table where service=?;
First you need find out the biggest date for each check
SELECT `check`, MAX(`datetime`)
FROM YourTable
WHERE `service` = 2
GROUP BY `check`
Then join back to get the rest of the data.
SELECT Y.*
FROM YourTable Y
JOIN ( SELECT `check`, MAX(`datetime`) as m_date
FROM YourTable
WHERE `service` = 2
GROUP BY check) as `filter`
ON Y.`service` = `filter`.service
AND Y.`datetime` = `fiter`.m_date
WHERE Y.`service` = 2
Basically, I want to achieve , for each months, like in this example, from January until March 2013, what is the Max(Most_Recent_Day) for each users.
Example, From January to March, every month in the Database, systems will capture the Most_Recent_Day for each users.
Below are the expected results:
User | Most_Recent_Day
--------------------------------
afolabi.banu | 1/31/2013
afolabi.banu | 2/7/2013
afolabi.banu | 3/21/2013
mario.sapiter | 1/22/2013
mario.sapiter | 2/7/2013
mario.sapiter | 3/11/2013
However, I want to have another DB column as well to be display .Below is the column.
User|Total_Hits | Recent_Month| Most_Recent_Day | Most_Recent_Days_Hits
I tried to use inner join, but the result are not what i expect. I got duplicated user name and duplicated recent day. Basically, I want only to display no duplicated record for the same user name.
Below is the result that I got. Please ignore the recent_month value since it's data from database.
User |Total_Hits | Recent_Month | Most_Recent_Day | Most_Recent_Days_Hits
-------------------------------------------------------------------------------------
afolabi.banu | 223 | 25 | 2/7/2013 | 5
afolabi.banu | 223 | 25 | 2/7/2013 | 5
afolabi.banu | 211 | 13 | 1/31/2013 | 3
afolabi.banu | 223 | 25 | 2/7/2013 | 5
afolabi.banu | 296 | 31 | 3/21/2013 | 1
afolabi.banu | 296 | 31 | 3/21/2013 | 1
mario.sapiter | 95 | 7 | 2/7/2013 | 5
mario.sapiter | 7 | 7 | 3/21/2013 | 1
mario.sapiter | 7 | 37 | 3/22/2013 | 1
mario.sapiter | 249 | 37 | 2/7/2013 | 5
This is my SQL Code
SELECT t.[User],
t.Total_Hits,
t.Recent_Month,
t.Most_Recent_Day,
t.Most_Recent_Day_Hits FROM UserUsageMonthly t
INNER JOIN
(
select
[User]
, max(Most_Recent_Day) as Most_Recent_Day
from UserUsageMonthly (NoLock)
where Application_Name='Daily Production Review' and Site_Collection='wrm13'
and Most_Recent_Day between '1/1/2013' and '3/31/2013'
group by [User], datepart(month,Most_Recent_Day)
) table2
ON
t.[User]=table2.[User]
AND t.Most_Recent_Day = table2.Most_Recent_Day
order by t.[User]
You should add the month value to your SQL SELECT
SELECT
MONTH(t.Most_Recent_Day) as 'MyMonth',
t.[User],
t.Total_Hits,
t.Recent_Month,
t.Most_Recent_Day,
t.Most_Recent_Day_Hits FROM UserUsageMonthly t
Then you can group by the month column
GROUP BY MyMonth