I have three values expected in a table case, Serious, Non-Serious, Unknown for each case_id
select case_id, case_seriousness
from case;
I have to build a SQL query which should show one row per case_id.
If there are rows for a case_id with multiple values, then only one row should appear based on priority - Serious, Non-Serious then Unknown.
e.g. Serious is in one row rest of four rows have Non-Serious or Unknown then Serious will be he value to show in one record.
If there are records with Non-serious and Unknown then Non-Serious should appear.
So Priorities will be like from S, NS and UK
You can use the analytical function as follows:
select case_id, case_seriousness
from
(select case_id, case_seriousness,
row_number() over (partition by case_id
order by case case_seriousness
when 'Serious' then 1
when 'Non-Serious' then 2
else 3
end ) as rn
from case)
where rn = 1;
Alternatively, You can also use DECODE instead of CASE..WHEN
Related
I have a table, Ellipses (...), represent multiple columns of a similar type
TABLE: diagnosis_info
COLUMNS: visit_id,
patient_diagnosis_code_1 ...
patient_diagnosis_code_100 -- char(100) with a value of ‘0’ or ‘1’
How do I find the most common diagnosis_code? There are 101 columns including the visit_id. The table is like a matrix table of 0s and 1s. How do I write something that can dynamically account for all the columns and count all the rows where the value is 1?
What I would normally do is not feasable as there are too many columns:
SELECT COUNT(patient_diagnostic_code_1), COUNT(patient_diagnostic_code_2),... FROM diagnostic_info WHERE patient_diagnostic_code_1 = ‘1’ and patient_diagnostic_code_2 = ‘1’ and ….
Then even if I typed all that out how would I select which column had the highest count of values = 1. The table is more column oriented instead of row oriented.
Unfortunately your data design is bad from the start. Instead it could be as simple as:
patient_id, visit_id, diagnosis_code
where a patient with 1 dignostic code would have 1 row, a patient with 100 diagnostic codes 100 rows and vice versa. At any given time you could transpose this into the format you presented (what is called a pivot or cross tab). Also in some databases, for example postgreSQL, you could put all those diagnostic codes into an array field, then it would look like:
patient_id, visit_id, diagnosis_code (data type -bool or int- array)
Now you need the reverse of it which is called unpivot. On some databases like SQL server there is UNPIVOT as an example.
Without knowing what your backend this, you could do that with an ugly SQL like:
select code, pdc
from
(
select 1 as code, count(*) as pdc
from myTable where patient_diagnosis_code_1=1
union
select 2 as code, count(*) as pdc
from myTable where patient_diagnosis_code_2=1
union
...
select 100 as code, count(*) as pdc
from myTable where patient_diagnosis_code_100=1
) tmp
order by pdc desc, code;
PS: This would return all the codes with their frequency ordered from most to least. You could limit to get 1 to get the max (with ties in case there are more than one code to match the max).
the column code has values that have duplicate on it , i do want to remove the duplicate of that row.
for example i want to remove the duplicates of column code as well the row that has duplicate on it. it doesent matter if the other column has duplicate but i do want to base it on the code column. what sql query can i use.? Thank you
this is the table I am working to.
as you can see there are isdeleted column that has value of 1 on them. I only want the recored with a value of 0 on them
here is a sample record, in here you can see that row 1 has a isdeleted value of 1, which mean that this record is deleted and i only need the row 2 of this code.
You could use the windowing function ROW_NUMBER() to single out the last entry per code like in:
SELECT code, shortdesc, longdesc, isobsolete, effectivefromdate
FROM (
SELECT ROW_NUMBER() OVER(PARTITION BY code ORDER BY effectivefromdate DESC) AS rn, *
FROM CodingSuite_STG
WHERE isobsolete=1 AND isdeleted=0
) AS cs
WHERE rn=1
ORDER BY effectivefromdate
Explanation:
Core of the operation is a "sub-query". That is a "table-like" expression generated by having a SELECT clause surrounded by parentheses and followed by a table name like:
( SELECT * FROM CodingSuite_STG WHERE iobsolete=1 ) AS cs
For the outer SELECT it will appear like a table with the name "cs".
Within this sub-query I placed a special function (a "window function") consisting of two parts:
ROWN_NUMBER() OVER ( PARTITION BY code ORDER BY effectivefromdate DESC) AS rn
The ROW_NUMBER() function returns a sequential number for a certain "window" of records defined by the immediately following OVER ( ... ) clause. The PARTITION BY inside it defines a group division scheme (similar to GROUP BY), so the row numbers start from 1 for each partitioned group. ORDER BY determines the numbering order within each group. So, with entries having the same code value ROW_NUMBER() will supply the number sequence 1, 2, 3... for each record, with 1 being assigned to the record with the highest value of effectivefromdate because of ORDER BY effectivefromdate DESC.
All we need to do in the outer SELECT clause is to pick up those records from the sub-query cs that have an rn-value of 1 and we're done!
I have in database records
My sql:
SELECT
DISTINCT name, date(mod_wr)
FROM
test.object_stg
WHERE
ir = '4552724'
GROUP BY
name, date(mod_wr)
ORDER BY name
The last record is the same as the last but one. It has only a different date.
Is it possible to somehow query to return all records where there has been a change in the "name" column?
For record 4 and 5 there is the same name, only a different date. I would like it to return only a record of 4 and 5, because there was no change.
If you don't want to remove rows where values are resused. E.g. your line #2, you can use LAG() and then only include rows where the value is different to the previous. E.g.
select name, date(mod_wr) from
(
SELECT
name, mod_wr, lag(name) over(order by mod_wr) as prev_name
FROM
test.object_stg
WHERE
ir = '4552724'
)
WHERE prev_name IS NULL OR name <> prev_name
From your sample data, you have 3 distinct names. However, you cannot use distinct in your select statement because it applies to every field listed and none of the dates would provide an exact match.
However, you can use a group by statement in order to collate your titles together.
// MySQL 5.6 Statement
select name, date(mod_wr) from object_stg group by name;
// MSSQL 2017 Statement
select name, max(mod_wr) from object_stg group by name;
Both statements return 3 lines with just the BMW, 1.0 GL and 1.0 GLS showing with a single date.
SQL Fiddle
I want to distinguish Rows on the basis of two or more columns value of the same table at the same time returns all columns from the table.
Ex: I have this table
DB Table
I want my result to be displayed as: filter on the basis of type and Number only. As in abover table type and Number for first and second Row is same so it should be suppressed in result.
txn item Discrip Category type Number Mode
60 2 Loyalty L 6174 XXXXXXX1390 0
60 4 Visa C 1600 XXXXXXXXXXXX4108 1
I have tried with sub query but yet unsuccessful. Please suggest what to try.
Thanks
You can do what you want with row_number():
select t.*
from (select t.*,
row_number() over (partition by type, number order by item) as seqnum
from t
) t
where seqnum = 1;
Write Oracle SQL query to fetch from Tasks table top Approval Statuses that appear after some first null value in the Approval_Status Column and then Approval Status sequence and then some null values
Facts
I only need the top Approval Statuses sequence
Serial Number for each task ID Sequence starts from 1 and then comes in Sequence like 1.2.3... and so on
There are thousands of tasks in the table like from T1 .... Tn
See the Query Result below i need to write a query that returns data in that format
I have heard analytic function i.e. "Partition By clause" for this can be used but i don't know how to use that
Tasks
Query Result
I really appreciate experts help in this regard
Thanks
You can do this with analytic functions, but there is a trick. The idea is to look only at rows where approval_status is not null. You want the first group of sequential serial numbers in this group.
The group is identified by the difference between a sequence that enumerates all the rows and the existing serial number. To get the first, use dense_rank(). Finally, choose the first by looking for the ones with a rank equal to 1:
select t.*
from (select t.*, dense_rank(diff) over (partition by taskid) as grpnum
from (select t.*,
(row_number() over (partition by taskid order by serial_number) -
serial_number
) as diff
from tasks
where approval_status is not null
) t
) t
where grpnum = 1;