SQL SUM OVER PARTITION BY 2 columns not working - sql

Question

Common question, I know. Just haven't been able to find a solution to my question, so hit me with the removal and or downvotes if you must.
(Oracle 12c)
I have data that looks like this:
Date ITEM QTY
01-MAR-20 STS 6920
01-MAR-20 STS 2581
01-MAR-20 S01 22606
01-MAR-20 S01 22312
01-MAR-20 S01 56000
....
I want to get QTY to aggregate (sum) at the Date and item level with only one record for each unique item on each date, so it looks like this:
Date ITEM QTY
01-MAR-20 STS 9501
01-MAR-20 S01 100918
The query I'm trying to use to do this is:
SELECT
WO.DATE,
D.ITEM,
SUM(WO.QUANTITY) OVER (PARTITION BY WO.DATE, D.ITEM) AS QTY
FROM SCHEMA_1.WO,
SCHEMA_2.D
WHERE WO.ITEM_DIM_KEY = D.ITEM_DIM_KEY AND
(DATE > '01 MAR 2020' AND DATE < '01 JUL 2020')
ORDER BY WO.COMPLETED_DATE;

Answer 1

A date data type in Oracle can have a time component. So you need to be careful. Unless you know hat you have no time component, trunc() is safer. Also, you can use the date keyword to handle date constants:
SELECT
SELECT TRUNC(WO.DATE), D.ITEM,
SUM(WO.QUANTITY)
FROM SCHEMA_1.WO JOIN
SCHEMA_2.D
ON WO.ITEM_DIM_KEY = D.ITEM_DIM_KEY
WHERE WO.DATE >= DATE '2020-03-01' AND
WO.DATE < DATE '2020-07-01'
GROUP BY TRUNC(WO.DATE), D.ITEM
ORDER BY TRUNC(WO.DATE);
Notes:
You don't need an analytic function. Aggregation should be sufficient.
Use proper, explicit, standard, readable JOIN syntax.
I assume the column in the ORDER BY is intended to be the first column in the result set.

Answer 2

You just need a basic GROUP BY query:
SELECT
WO.DATE,
D.ITEM,
SUM(WO.QUANTITY) AS QTY
FROM SCHEMA_1.WO
INNER JOIN SCHEMA_2.D
ON WO.ITEM_DIM_KEY = D.ITEM_DIM_KEY
WHERE
DATE > '01 MAR 2020' AND DATE < '01 JUL 2020'
GROUP BY
WO.DATE,
D.ITEM
ORDER BY
WO.COMPLETED_DATE;
Using SUM as a window function would make sense if you wanted to retain every record in the result set of the join. However, in your case, you want to report aggregate sums for each date/item group. Using GROUP BY is what you want here.

Answer 3

I think you just need a simple aggregation:
select trunc(date), item, sum(qty)
from schema_1.wo
join schema_2.d on wo.item_dim_key = d.item_dim_key
where date > date '2020-03-01' and date < date '2020-07-01'
group by trunc(date), item
order by wo.completed_date
Incidentally, I upgraded the JOIN to SQL-92 and fixed the dates literal to ISO dates instead of VARCHARs.