SQL - Select in Select - sql

Question

I have the below working query from which I create a stacked-column-graph.
I now want to be able to filter top 10 [Prod_Model] with the highest count of [plugin ID] in total.
I tried to create an additional column summing [Plugin ID] (vulCnt) for each product disregarding [Risk].
My efforts to use INNER JOIN or SELECT inside the SELECT failed.
My working query:
select t.Prod_Model,
count(t.[Plugin ID]) as vulCnt,
(case t.Risk
when 'Critical' then 1
when 'High' then 2
when 'Medium' then 3
when 'Low' then 4
Else 5
End) As Rsk_Levl,
t.Risk
from ************ t
where t.prod_model <>''
group by t.Prod_Model, t.Risk
order by t.Prod_Model
Result is -
|Prod_Model|vulCnt| Risk_Level| Risk |
|procut 1 | 4 | 1 | Critical|
|procut 1 | 2 | 1 | High |
|procut 1 | 6 | 1 | Medium |
|procut 1 | 1 | 1 | Low |
|procut 2 | 4 | 1 | Critical|
|procut 2 | 2 | 1 | High |
|procut 2 | 6 | 1 | Medium |
|procut 2 | 1 | 1 | Low |
Now I need top##.
Help will be much appreciated.

Answer 1

I think that you want a window sum to generate the additional column. You can then use it this information to rank and limit:
select *
from (
select
Prod_Model,
count([Plugin ID]) as vulCnt,
(case Risk
when 'Critical' then 1
when 'High' then 2
when 'Medium' then 3
when 'Low' then 4
Else 5
End) As Rsk_Levl,
Risk,
dense_rank() over(order by cnt desc) rn
from (
select t.*, count(*) over(partition by Prod_Model) cnt
from mytable t
where prod_model <> ''
) t
group by Prod_Model, Risk
) t
where rn <= 10
order by rn