I can't correctly write a query.
I need to select a person who has only one value in the column. For example,
select * (
select PersonID, sum(TotalAmount)
from Table1
group by PersonID
HAVING sum(TotalAmount) = 0 )
where Group = A
It means that I would select all customers that belong to ONLY 'A' group...
Could someone help me?
If you want the persons with only one value, then having count(*) = 1 comes to mind:
select personid
from table1
group by personid
having count(*) = 1;
Related
I have a result set that looks like this:
As you can see some of the contactID are repeated with same QuestionResponse. And there is one with a different QuestionResponse (the one with red lines).
I want to group this by ContactID, but select the latter row. Eg: In case of ContactID = 78100299, I want to select the row with CreateDate = 17:00:44.907 (or rowNum = 2).
I have tried this:
select
ContactID,
max(QuestionResponse) as QuestionResponse,
max(CreateDate) as CreateDate
from
theResultSet
group by
ContactID
This will NOT work because there could be QuestionResponse 2 and then 1 for the same contactID. In that case the latter one will be the one with response 1 not 2.
Thank you for you help.
I would use ROW_NUMBER() that way:
WITH Query AS
(
SELECT rowNum, ContactID, QuestionResponse, CreateDate,
ROW_NUMBER() OVER (PARTITION BY ContactID ORDER BY CreateDate DESC) Ordered
FROM theResultSet
)
SELECT * FROM Query WHERE Ordered=1
Assign numbers in ContactID group by date, descending
Filter results having number <> 1
This might work if your SQL Engine can handle it...
SELECT trs1.*
FROM theResultSet trs1
INNER JOIN
(SELECT ContactID, max(CreateDate) as CreateDate
FROM theResultSet
GROUP BY ContactID) trs2
ON trs1.ContactID = trs2.ContactID
AND trs1.CreateDate = trs2.CreateDate
The end result will be all rows from theResultSet where the creation date is the max creation date.
This should work too:
SELECT
ContactID, QuestionResponse,CreateDate
FROM (
select rowNum, ContactID, QuestionResponse,CreateDate,
max(rowNum) over(partition by ContactID) as maxrow
from theResultSet
) x
WHERE rowNum=maxrow
I am trying to get a count of the userID's that exist in 2 tables,
I also have an inner join for the tables on the userID so that I can search for the count of one table, based off the BadgeID from the other table.
So far it returns the user count for one table, but I can't seem to figure out how to return a count for userID on both tables, Any suggestions?
SELECT DISTINCT live_event.usid, COUNT(1) AS membercount
FROM live_event
INNER JOIN member_badges ON live_event.usid = member_badges.usid
WHERE bdgid = 14
Not sure what you are looking for; but based on what I could understand, are sub-queries perhaps the route you are wanting to go?
select
(select count(*) from firsttable where userid = {userid})
as count1,
(select count(*) from secondtable where userid = {userid})
as count2
Where {userid} would be your bdgid.
Try to use union select to connect results from two tables
select useid, count(*) from (
select useid from firsttable
union select useid from second table ) group by useid
Try this:
SELECT
user_id,
COALESCE(MAX(
CASE
when tbl_name='live_event' then cnt_records
else null
END), 0) as cnt_live_event,
COALESCE(MAX(CASE
when tbl_name='member_badges' then cnt_records
else null
END), 0) as cnt_member_badges
FROM
(
SELECT
'live_event' AS tbl_name,
usid as user_id,
count(*) AS cnt_records
FROM live_event
GROUP BY 'live_event', usid
UNION
SELECT
'member_badges',
usid as user_id,
count(*)
FROM member_badges
GROUP BY 'member_badges', usid
) grouped_counts
GROUP BY user_id
ORDER BY user_id;
The above query would get you the user counts even if the usid is present in only one of the tables.
I have a table that contain UserID's and Departments. UserID's can belong to several departments so their combo makes it unique.
However I have been trying to query trying to find where the UserID belongs to either one of two departments (hr or customer).
SELECT UserId, Dept, COUNT(*) Total
FROM MyTable
GROUP BY UserID
HAVING COUNT(*) = 1
However this still brings back duplicates if a UserId has both departments I guess because the combo makes it a unique record.
What I get back is this
UserID | Department | Total
1 hr 1
2 customer 1
3 customer 1
1 customer 1
3 hr 1
But what I am trying to get back is this
UserID | Department | Total
2 customer 1
Where any instances of UserId belonging to both departments are not included only if they belong to one or the other.
This should do the job
select t1.UserId, Dept, t2.Total
FROM MyTable t1
INNER JOIN
(
SELECT UserId, COUNT(*) Total
FROM Table1
GROUP BY UserID
HAVING COUNT(*) = 1
) t2 on t1.UserId = t2.UserId
try
SELECT UserId, COUNT(distinct Dept) Total
FROM MyTable
GROUP BY UserID
HAVING COUNT(distinct Dept) = 1
You can try something like this
select UserId, Dept
FROM Mytable where UserId in
(
SELECT UserId, COUNT(*) Total
FROM MyTable
GROUP BY UserID
HAVING COUNT(*) = 1
)
If you add the Dept column in your Group by you will always retrieve all the combinations.
So you have to select all users with only one Dept and then retrieve the additional informations
There is maybe syntax errors because I am usually working with oracle but I think the concept is correct
This will select users in 'hr' that do not have id's in 'customer' and then users in 'customer' that do not have ids in 'hr'.
I didn't include count on purpose as it can always only be one.
SELECT * FROM [MyTable] T WHERE Department = 'hr' AND NOT EXISTS (SELECT 1 FROM [MyTable] WHERE [MyTable].UserID =T.UserID AND Department = 'customer') UNION
SELECT * FROM [MyTable] T WHERE Department = 'customer' AND NOT EXISTS (SELECT 1 FROM [MyTable] WHERE [MyTable].UserID =T.UserID AND Department = 'hr')
I do not think the above query will run as Dept is not in group by clause and also count comparsion cannot be in that way.
Coming to your issue:
Select userid, Dept
from #temp
where userid in (Select userid from (Select userid,count(*) 'C'
from #temp group by userid ) u where u.c=1)
I do not think you require count as it is always 1
It's a fake question because you can't use Dept in this query.
I'm don't understand why author doesn't explain us about any compiler warnings and tells us some results of this query.
but you can yse this way if you really want to get some result:
SELECT UserId, min(Dept) as Dept
FROM MyTable
GROUP BY UserID
HAVING COUNT(*) = 1
The problem is the COUNT (*) at the end.
Try this:
SELECT UserId, Dept, COUNT(*) Total
FROM MyTable
GROUP BY UserID
HAVING COUNT(UserId) = 1
so i have two tables, one is RAWtable and the other is MAINtable, I have to get the latest groupID if there
are more than one records exist (comparing same name, code). For example, I have this on RAWtable:
id groupid name code
1 G09161405 Name1 Code1
2 G09161406 Name1 Code1
the two records should be treated as one and should return this value only:
id groupid name code
2 G09161406 Name1 Code1
This row is the only row that shiuld be inserted in the main table. Provided returning the latest GroupID (the groupid is the combination of date and time)
I've tried this but its not working:
SELECT MAST.ID, MAST.code, MAST.name FROM RAWtable AS MAST INNER JOIN
(SELECT code, name, grouid,id FROM RAWtable AS DUPT GROUP BY code, name, groupid,id HAVING COUNT(*) >= 2) DUPT
ON DUPT.code =MAST.code and DUPT.name =MAST.name where dupt.groupid >mast.groupid
how can i do this? thanks a lot.
select R.id,
R.groupid,
R.name,
R.code
from (select id,
groupid,
name,
code,
row_number() over(partition by name, code order by groupid desc) as rn
from RawTable
) as R
where R.rn = 1
Or if you don't have row_number()
select R1.id,
R1.groupid,
R1.name,
R1.code
from RawTable as R1
inner join (
select name, code, max(groupid) as groupid
from RawTable
group by name, code
) as R2
on R1.name = R2.name and
R1.code = R2.code and
R1.groupid = R2.groupid
Try this way, it will give you max group id which will be latest :
SELECT MAX(GroupId), Name, Code
FROM RAWtable
GROUP BY Name, Code
select max(id),name, code from RaTable
group by name,code having count(*)>1
Will return:
id name code
2 Name1 Code1
Will return the max gorupid for all the records that have more than one record in the table
Try this:
select max(t.groupid), t.name, t.code
from RAWtable t
group by t.name, t.code
This will basically select the max value of groupid for each name and code combination.
I'm looking for a way to handle the following scenario. I have a database table that I need to return only one record for each "group id" that is contained within the table, furthermore the record that is selected within each group should be the oldest person in the household.
ID Group ID Name Age
1 134 John Bowers 37
2 134 Kerri Bowers 33
3 135 John Bowers 44
4 135 Shannon Bowers 42
So in the sample data provided above I would need ID 1 and 3 returned, as they are the oldest people within each group id.
This is being queried against a SQL Server 2005 database.
SELECT t.*
FROM (
SELECT DISTINCT groupid
FROM mytable
) mo
CROSS APPLY
(
SELECT TOP 1 *
FROM mytable mi
WHERE mi.groupid = mo.groupid
ORDER BY
age DESC
) t
or this:
SELECT *
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY groupid ORDER BY age DESC) rn
FROM mytable
) x
WHERE x.rn = 1
This will return at most one record per group even in case of ties.
See this article in my blog for performance comparisons of both methods:
SQL Server: Selecting records holding group-wise maximum
Use:
SELECT DISTINCT
t.groupid,
t.name
FROM TABLE t
JOIN (SELECT t.groupid,
MAX(t.age) 'max_age'
FROM TABLE t
GROUP BY t.groupid) x ON x.groupid = t.groupid
AND x.max_age = t.age
So what if there's 2+ people with the same age for a group? It'd be better to store the birthdate rather than age - you can always calculate the age for presentation.
Try this (assuming Group is synonym for Household)
Select * From Table t
Where Age = (Select Max(Age)
From Table
Where GroupId = t.GroupId)
If there are two or more "oldest" people in some household (They all are the same age and there is noone else older), then this will return all of them, not just one at random.
If this is an issue, then you need to add another subquery to return an arbitrary key value for one person in that set.
Select * From Table t
Where Id =
(Select Max(Id) Fom Table
Where GroupId = t.GroupId
And Age =
(Select(Max(Age) From Table
Where GroupId = t.GroupId))
SELECT GroupID, Name, Age
FROM table
INNER JOIN
(
SELECT GroupID, MAX(Age) AS OLDEST
FROM table
) AS OLDESTPEOPLE
ON
table.GroupID = OLDESTPEOPLE.GroupID
AND
table.Age = OLDESTPEOPLE.OLDEST
SELECT GroupID, Name, Age
FROM table
INNER JOIN
(
SELECT GroupID, MAX(Age) AS OLDEST
FROM table
**GROUP BY GroupID**
) AS OLDESTPEOPLE
ON
table.GroupID = OLDESTPEOPLE.GroupID
AND
table.Age = OLDESTPEOPLE.OLDEST