I need to send contents of a file as mail boy and i am using below command
cat filename.txt | tr -d \\r | mailx -s "test" abc#xyz.com
Below is content of file
this is first line
this second line
this is third line
this is fourth line
Below is what i am receiving over mail
this is fist line this is
second line this is third
line this is fourth line
so there is problem with formatting.
I tried to use other options to send content of file as mail body like below . But they did not work.
cat filename.txt | mail -s test abc#xyz.com
So please help
thanks in advance.
After trying below command
Below is content of file
Below is what i received over mail
Related
I am working with the following input:
"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"
I need to be able to extract both the phone number and email of each line into separate files. However, both values don't always appear in the same field - they will always be prefaced with "phone": or "email":, but they may be in the first, second, third or even twentieth field.
I have tried chopping together solutions in SED and AWK to remove everything up until "phone" and then every after the next , but this doesn't not work as desired. It also means that, if "phone" and/or "email do not exist, the line is not changed at all.
I need a solution that will give me an output with the phone value of each line in one file, and the email value in another. HOWEVER, if no phone or email value exists, a blank line in the output needs to be in place.
Any ideas?
This might work for you (GNU sed):
sed -Ene 'h;/.*"phone":([^,]*).*/!z;s//\1/;w phoneFile' -e 'g;/.*"email":([^,]*).*/!z;s//\1/;w emailFile' file
Make a copy of line.
If the line does not contain a phone number empty the line, otherwise remove everything but the phone number.
Write the result to the phone number file.
Replace the current pattern space by the copy of the original line.
Repeat as above for an email address.
N.B. My first attempt used s/.*// instead of z to empty the line which worked but should not have. If the line contained no phone/email, the substitution should have reset default regexp and the second substitution should have objected that it did not contain a back reference. However the second substitution worked in either case.
After fixing your file to be valid json and adding an extra line missing the phone attribute so we can test more of your requirements:
$ cat file
{"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"}
{"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"city":"Marshall","gender":"female","email":"foo.bar#gmail.com"}
you can do whatever you like with the data:
$ jq -r '.email // ""' file
mortina.curabia#gmail.com
foo.bar#gmail.com
$
$ jq -r '.phone // ""' file
549-287-5287
$
As long as it doesn't contain embedded newlines you can used sed 's/.*/{&}/' file to convert the input in your question to valid json as in my answer:
$ cat file
"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"
"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"city":"Marshall","gender":"female","email":"foo.bar#gmail.com"
$ sed 's/.*/{&}/' file
{"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"}
{"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"city":"Marshall","gender":"female","email":"foo.bar#gmail.com"}
$ sed 's/.*/{&}/' file | jq -r '.email // ""'
mortina.curabia#gmail.com
foo.bar#gmail.com
but I'm betting you started out with valid json and removed the {} by mistake along the way so you probably just need to not do that.
Using grep
Try:
grep -o '"phone":"[0-9-]*"' < Input > phone.txt
grep -o '"email":"[^"]*"' <Input > email.txt
Demo:
$echo '"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"' | grep -o '"phone":"[0-9-]*"'
"phone":"549-287-5287"
$echo '"visit_date":{"$date":"2017-11-28T04:43:00.000Z"},"phone":"549-287-5287","city":"Marshall","gender":"female","email":"mortina.curabia#gmail.com"' | grep -o '"email":"[^"]*"'
"email":"mortina.curabia#gmail.com"
$
I have a file called "text.bz2" which contains a number of records which i want to process. I have a script which successfully processes all the data in a standard text file and outputs the results to a different "results.txt" file, but the command I'm currently running outputs all the results of the bz2 file to the command prompt (like cat does), creates the results.txt file - but it is empty.
This is the cammand I'm running:
bzip2 -dc text.bz2 | awk ... '
'
> results.txt
The format of the data in the decompressed bz2 file is:
field1=xxx;field2=xxx;field3=111222222;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222222;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222333;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222444;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222555;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222555;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222777;field4=xxx;field5=xxx
field1=xxx;field2=xxx;field3=111222888;field4=xxx;field5=xxx
and the output is exactly as expected, as below, but instead of the results being output to a text file, it's output to the command window:
111222333 111
111222444 111
111222555 111
111222777 222
111222888 111
What am i doing wrong with my bzip / redirection command?
Many thanks
Put the > file at the end of the awk command, not on the line after it:
foo | awk 'script' > file
not
foo | awk 'script'
> file
How to overwrite the file while a cronjob is running?I have a command running there every 5 minutes and I want the result to be stored in a text file and it should be overwritten every 5 minutes with new result.How?
You can write a cronjob to write your file in a new file before the next cronjob.
To send content from a file to another file you can use cat file.txt > file2.txtor append with cat file.txt >> file2.txt
I'm trying to parse some text from a text file in Linux using the following command:
grep "x" | cut -d ":" -f 2 EthernetData1.txt
Everything seems to be working fine as in the display I can see the expected result but the process does not finish so I can't execute another command without clicking [Ctrl + c].
The file is quite big but the proccess seems to reach the end of it.
Any suggestion?
Thank you.
I think you mean
grep "x" EthernetData1.txt | cut ...
i.e. you need to give your input file to grep not cut.
How to get the first few lines from a gziped file ?
I tried zcat, but its throwing an error
zcat CONN.20111109.0057.gz|head
CONN.20111109.0057.gz.Z: A file or directory in the path name does not exist.
zcat(1) can be supplied by either compress(1) or by gzip(1). On your system, it appears to be compress(1) -- it is looking for a file with a .Z extension.
Switch to gzip -cd in place of zcat and your command should work fine:
gzip -cd CONN.20111109.0057.gz | head
Explanation
-c --stdout --to-stdout
Write output on standard output; keep original files unchanged. If there are several input files, the output consists of a sequence of independently compressed members. To obtain better compression, concatenate all input files before compressing
them.
-d --decompress --uncompress
Decompress.
On some systems (e.g., Mac), you need to use gzcat.
On a mac you need to use the < with zcat:
zcat < CONN.20111109.0057.gz|head
If a continuous range of lines needs be, one option might be:
gunzip -c file.gz | sed -n '5,10p;11q' > subFile
where the lines between 5th and 10th lines (both inclusive) of file.gz are extracted into a new subFile. For sed options, refer to the manual.
If every, say, 5th line is required:
gunzip -c file.gz | sed -n '1~5p;6q' > subFile
which extracts the 1st line and jumps over 4 lines and picks the 5th line and so on.
If you want to use zcat, this will show the first 10 rows
zcat your_filename.gz | head
Let's say you want the 16 first row
zcat your_filename.gz | head -n 16
This awk snippet will let you show not only the first few lines - but a range you can specify. It will also add line numbers which i needed for debugging an error message pointing to a certain line way down in a gzipped file.
gunzip -c file.gz | awk -v from=10 -v to=20 'NR>=from { print NR,$0; if (NR>=to) exit 1}'
Here is the awk snippet used in the one liner above. In awk NR is a built-in variable (Number of records found so far) which usually is equivalent to a line number. the from and to variable are picked up from the command line via the -v options.
NR>=from {
print NR,$0;
if (NR>=to)
exit 1
}