I want to convert the following date format to "May 13 2020 12:00:00:000AM" to UNIX formatted timestamps in milliseconds. Can you please advice on doing this. Thanks in advance.
Related
I would like to convert a String containing values in the format yyyymmddhhmmss to MM/DD/YYYY HH:MM (AM or PM) in Snowflake. The String contains time in UTC format. Also would like the final output to be in CST timezone.
Eg of String : 20220120035900
Expected output : 01/20/2022 03:59:00
Appreciate the help!
Please check below select try_to_timestamp('20220120035900', 'YYYYMMDDHHMISS');
UTC to CST:
SELECT try_to_timestamp('20220120035900', 'YYYYMMDDHHMISS') as t_str,
t_str::timestamp_ntz as UTC_tz,
convert_timezone('UTC','America/Chicago', UTC_tz) chicago_time;
I have a requirement to convert the yyyy-MM-dd date format into DD-MMM-YY.
e.g.: 2018-06-14 -> 14-JUN-18.
I tried to_char(date,'DD-MMM-YY'), however it's resulting in 14-06M-18.
Is this possible?
The format mask for the three letter month abbreviation in all caps is MON, not MMM:
to_char(date, 'DD-MON-YY')
Maybe you are coming from another API/language where MMM would have worked in that case.
I have a date value (Mon Feb 29 06:01:14 CST 2016) in column. I need to convert this to the format 'YYYY-MM-DD' in hive.
Can any one please help me on this.
There is a unix_timestamp function which should help you. to_date(unix_timestamp(your_column, 'EEE MMM dd HH:mm:ss z yyyy')) This should return a string representing your date.
I need to convert Decimal(17,9) datatype to Timestamp(6).
Example, I am having Decimal(17,9) value as 20150619.154519 and I need to convert it to timestamp like Jun 19, 2015 15:45.
You have a strange format. First convert it to a string, then to a date:
select to_date(to_char(col, '99999999.999999'), 'YYYYMMDD.HHMISS')
Actually, this would probably work without the to_char() part, but it seems safer to do the conversion explicitly.
I currently have a timestamp in this format Tue Jun 03 17:17:05 +0000 2014 in one column in my table. I want to count the number of records happening in specific intervals (15 minutes). I have tried to follow the answer found in Group records by time. Although my timestamp is in a different format and I haven't seen any support function available in SQLite to convert this. Is this possible in SQL?
The SQLite date and time functions can be used to convert a timestring to a canonical format, or to a Julian Day Number. Unfortunately, the SQLite date and time functions only accept timestring in a limited number of formats:
YYYY-MM-DD
YYYY-MM-DD HH:MM
YYYY-MM-DD HH:MM:SS
YYYY-MM-DD HH:MM:SS.SSS
YYYY-MM-DDTHH:MM
YYYY-MM-DDTHH:MM:SS
YYYY-MM-DDTHH:MM:SS.SSS
If your timestring format has fixed field widths, you can use the substr function and the || string concatenation operator to convert it to a format SQLite understands. You'll have to use a case expression to convert the month names to numbers; here's an example.
You may use NEW_TIME in Oracle to convert the time to a specific timezone. Here is an example. This example is converting SYSDATE from PDT to GMT.
SELECT NEW_TIME (SYSDATE, 'PDT', 'GMT') FROM DUAL;
This thread is detailing how to add required minutes to your timestamp.