Thanks to 2 posts (here and here), I know how to highlight text of a textbox in PowerPoint with VBA code.
However, the problem of unhighlighting text remains unsolved. I tried to set properties of a non-highlighted textbox to TextRange2.Font (e.g. .TextFrame2.TextRange.Font.Highlight.SchemeColor = -2) but receive errors when trying so (The typed value is out of range).
Can someone help to solve this issue, please?
Additionally, when changing the highlight color
(e.g. TextRange2.Font.Highlight.RGB = RGB(255, 255, 175)) the formatting of my textbox changes, so the font is changing its color from my preset white to black and the font size gets smaller. Is there any way to preserve the original settings for the textbox? Is this happening due to the access of .TextRange2 and not .TextRange?
Thanks for your help!
In PowerPoint 2019/365 it is possible to remove highlight by using built-in Mso "TextHighlightColorPickerLicensed".
This code sample illustrates how to unhighlight text in selected shapes. It finds Runs containing highlighting, selects them and removes highlight by programmatically invoking Command Bar "Highlight" button.
Preconditions: PowerPoint 2019 or 365. Presentation must be opened with window.
Option Explicit
Sub UnhighlightTextInSelectedShape()
Dim sh As Shape
For Each sh In ActiveWindow.Selection.ShapeRange
UnhighlightTextInShape sh
Next
End Sub
Sub UnhighlightTextInShape(sh As Shape)
On Error GoTo Finish
Dim highlightIsRemoved As Boolean
Dim tf As TextFrame2
Set tf = sh.TextFrame2
Do
Dim r As TextRange2
highlightIsRemoved = True
For Each r In tf.TextRange.Runs
If r.Font.Highlight.Type <> msoColorTypeMixed Then
' Indicate that text contains highlighting
highlightIsRemoved = False
' The text to un-highlight must be selected
r.Select
If Application.CommandBars.GetEnabledMso("TextHighlightColorPickerLicensed") Then
' This Mso toggles highlighting on selected text.
' That is why selection must contain highlight of the same type
Application.CommandBars.ExecuteMso ("TextHighlightColorPickerLicensed")
' Unhighlighting May invalidate number of runs, so exit this loop
Exit For
Else
Exit Do
End If
End If
Next
Loop Until highlightIsRemoved
Finish:
If Not highlightIsRemoved Then
MsgBox "Unhighlighting is not supported"
End If
End Sub
Sometimes Application.CommandBars.ExecuteMso() method gives access to features not available via PowerPoint API.
The MsoId is displayed in tooltip text in PowerPoint options window:
Related
I changed the size of text with the following line of code
shp.CellsSRC(visSectionCharacter, 0, visCharacterSize).FormulaU = " 3pt"
I'd like to change the style (to Bold) and color of the shape text with the same pattern of code ?
I didn't find the exact "formula", would you know how I could do that ?
Thank you very much in advance
Edit : I found this line for the color :
shp.CellsSRC(visSectionCharacter, 0, visCharacterColor).FormulaU = "THEMEGUARD(RGB(255,0,0))"
I'm not sure why there is no enumeration for setting the Style. In any case, it's Column 2 in the shape properties. So use
shp.CellsSRC(visSectionCharacter, 0, 2).FormulaU = 17
to set your text to Bold.
How do I know this you ask? Based on the Microsoft reference on Understanding the Shape Sheet, there is a helpful snippet of code to use.
First, select the shape in your drawing that you want to see information about the properties. Then open up the Shape Properties window in the Visio editor (not in the VBE) -- you can get there by viewing the Developer ribbon, then click on the Show ShapeSheet icon
In the shape properties window, scroll down until you see the Characters section. You MUST select one of the cells in the properties window. The example here has selected the Style column.
Once you have done this, then run the following code snippet below and you'll get the information you need in the Immediate Window of the VBE.
Public Sub DebugPrintCellProperties()
' Abort if ShapeSheet not selected in the Visio UI
If Not Visio.ActiveWindow.Type = Visio.VisWinTypes.visSheet Then
Exit Sub
End If
Dim cel As Visio.Cell
Set cel = Visio.ActiveWindow.SelectedCell
'Print out some of the cell properties
Debug.Print "Section", cel.Section
Debug.Print "Row", cel.Row
Debug.Print "Column", cel.Column
Debug.Print "Name", cel.Name
Debug.Print "FormulaU", cel.FormulaU
Debug.Print "ResultIU", cel.ResultIU
Debug.Print "ResultStr("""")", cel.ResultStr("")
Debug.Print "Dependents", UBound(cel.Dependents)
' cel.Precedents may cause an error
On Error Resume Next
Debug.Print "Precedents", UBound(cel.Precedents)
Debug.Print "--------------------------------------"
End Sub
This will tell you the Section, Row, and Column to use when you call CellsSRC. What I did was to figure out the property, then I manually set the text to BOLD and viewed the results of DebugPrintCellProperties again to see that the FormulaU = 17 for bold.
I would like to make a macro in Powerpoint that enables me to create shapes in a similar fashion as when you select the autoshapes in the autoshape overview (i.e. once you call the macro you have a possibility to click to set the coordinates and subsequently you drag and click to set the width&height). Also, I would like to give it pre-set cosmetic characteristics (e.g. certain inner margins, fill color, border style and transparancy), which will be defined in the vba code.
I am aware of .addshapes(), however, this requires coordinates and height/width as input. Moreover, I have not find any posts / documents on vba to create shapes without defined coordinates and height/width.
Anyone some ideas on how to tackle this challenge?
Many thanks in advance!
Sofar
Building on what John Korchok suggested, here's code that retrieves the just-drawn shape so that your code can resume and manipulate it...
Sub testAppComBars()
Dim SHP As Shape
Application.CommandBars.ExecuteMso ("ShapeFreeform")
Stop
Set SHP = Selection.ShapeRange(1)
With SHP.Fill
.ForeColor.RGB = RGB(192, 0, 0)
.Transparency = 0.75
End With
End Sub
I would hope there's a more elegant solution than using Stop to pause code execution while the user picks the shape's location (or in this case, draws a freeform polyline/polygon), but that's all I could come up with off the top of my head.
I was fascinated by this problem and think this might help you.
Consider that when you draw a new autoshape, you have changed the window selection, and created a new selection ShapeRange with exactly 1 item (the new shape).
So by setting a WindowSelectionChange event, you're able to apply any formatting you wish at the time of creation.
First create a class module called cPptEvents with the following:
Public WithEvents PPTEvent As Application
Private Sub PPTEvent_WindowSelectionChange(ByVal sel As Selection)
On Error GoTo Errhandler
Debug.Print "IN_PPTEvent_WindowSelectionChange"
Dim oShp As Shape
If (ActiveWindow.ViewType = ppViewNormal) Then
With sel
If .Type = ppSelectionShapes Then
If .ShapeRange.Count = 1 Then
Set oShp = .ShapeRange(1)
If oShp.Type = msoAutoShape Then
If oShp.AutoShapeType = msoShapeOval Then
If oShp.Tags("new_oval") = "" Then
oShp.Fill.ForeColor.RGB = RGB(255, 0, 0)
oShp.Tags.Add "new_oval", "true"
End If
End If
End If
End If
End If
End With
End If
Exit Sub
Errhandler:
Debug.Print "Error: " & Err.Description
End Sub
This checks the selection every time it changes. If there's an oval selected, it looks for the "new_oval" tag, which will not exist for a newly created shape. In that case, it applies a red fill, although of course once you get to this point you can call an entirely different sub, pass along the shape, and do whatever you want formatting-wise to it.
By adding that "new_oval" tag, you ensure that the formatting will not be applied to an oval that hasn't been newly created. This allows the user to make manual changes to the formatting as needed -- otherwise you're just resetting the formatting every time the user selects an oval.
Note that for the _WindowSelectionChange event to be running in the background, you have to call this at some point:
Public MyEventClassModule As New cPptEvents
'
Public Sub StartMeUp()
Set MyEventClassModule.PPTEvent = Application
End Sub
You can include that one line from StartMeUp above in whatever Ribbon_Onload sub is triggered by your addin, if you're making a new addin ribbon.
With this solution, you don't even have to give the end user a special button or set of tools to create the shapes that are being formatted. It happens invisibly whenever the user draws a new shape from the native PPT tools.
This will put your cursor in drawing mode to draw an oval. After running, you may have to click on the slide once, then the cursor will change shape and you can draw an oval:
Sub DrawOval()
Application.CommandBars.ExecuteMso ("ShapeOval")
End Sub
Other commands to substitute for ShapeOval:
ShapeRectangle
ShapeElbowConnectorArrow
ShapeStraightConnectorArrow
Get the full list in Excel spreadsheets from Microsoft Office 2016 Help Files: Office Fluent User Interface Control Identifiers
Look for the powerpointcontrols.xlsx file and search the first column with "shape"
There are 173 shapes in the menu, so you have a lot of macros to write.
I have a VBA Code to resize objects in PowerPoint including Font size, margins and everything else. But I haven’t found a solution to update/change an existing TapStop. There is a the Ruler Object with different levels und a default value. I double checked also the TextRange Object with Characters.
Are there any ideas to update the TabStop size?
Here is an example of a TextBox, i would like to resize:
TextBox Example
Shape.textframe.ruler.tabstops.count is always 0, if I "take" just the shape by For-Each-Loop. If I select it manual, it's also 0 at the sub menu TabStops of Paragraph menu.
If I click inside the shape (blinking cursor) and open the TabStops menu again, I see one TabStopPosition.
How can I access this information by VBA?
I tried it already by Line.Selection and nothing works.
Thanks!
Moe
PowerPoint used to allow only one set of paragraph settings per textframe (ie, per shape). That changed in PPT2007; now each paragraph can have its own tab and other settings. Have a go with this:
Sub ShowMeTabs()
Dim X As Long
Dim lTabCount As Long
With ActiveWindow.Selection.ShapeRange(1).TextFrame2.TextRange
For X = 1 To .Paragraphs.Count
Debug.Print X
With .Paragraphs(X).ParagraphFormat
For lTabCount = 1 To .TabStops.Count
Debug.Print .TabStops(lTabCount).Position
Next ' Tab
Debug.Print "Level:" & .IndentLevel & " Position:" & .LeftIndent 'etc
End With
Next ' paragraph x
End With
End Sub
I have the following code in VBA (MS Word), that is meant to run after I click in a button, named cmdFormPreencher inserted in my Document:
Private Sub cmdFormPreencher_Click()
'
If ActiveDocument.FormsDesign = False Then
ActiveDocument.ToggleFormsDesign
End If
'
ThisDocument.cmdFormPreencher.Select
ThisDocument.cmdFormPreencher.Delete
ActiveDocument.ToggleFormsDesign
'
UserForm2.Show
End Sub
The purpose of the code above is to delete that button inserted in my document.
But when I run the code only the button is selected. When I tried to figure out what is happening by debugging, it showed me the code runs until ActiveDocument.ToggleFormsDesign and not running the code remaining
Is this a bug of VBA, or am I doing something wrong? If so, how can I get around this problem?
Thanks!
Note: The ActiveX button is not in Header and Footer. The Text Wrap is set to In Front of Text
Edit:
When I try to run a macro, activating FormDesign, Selecting the ActiveX button and then deleting, I get this code:
Sub Macro1()
'
' Macro1 Macro
'
'
ActiveDocument.ToggleFormsDesign
ActiveDocument.Shapes("Control 52").Select
Selection.ShapeRange.Delete
ActiveDocument.ToggleFormsDesign
End Sub
But when I run this code nothing happens...
This is by design. When an Office application is in Design Mode code should not run on an ActiveX object that's part of the document.
I take it this is an ActiveX button and in that case, it's a member of the InlineShapes or Shapes collection - Word handles it like a graphic object. It should be enough to delete the graphical representation, which you can do by changing it to display as an icon instead of a button.
For example, for an InlineShape:
Sub DeleteActiveX()
Dim ils As word.InlineShape
Set ils = ActiveDocument.InlineShapes(1)
ils.OLEFormat.DisplayAsIcon = True
ils.Delete
End Sub
You just have to figure out how to identify the InlineShape or Shape. You could bookmark an InlineShape; a Shape has a Name property.
EDIT: Since according to subsequent information provided in Comments you have a Shape object, rather than an InlineShape, the following approach should work:
Dim shp As word.Shape
Set shp = ActiveDocument.Shapes("Shape Name") 'Index value can also be used
shp.Delete
Note that Word will automatically assign something to the Shape.Name property, but in the case of ActiveX controls these names can change for apparently no reason. So if you identify a control using its name instead of the index value it's much better to assign a name yourself, which Word will not change "on a whim".
Activate Design Mode.
Click on the control to select it
Go to the VB Editor window
Ctrl+G to put the focus in the "Immediate Window"
Type the following (substituting the name you want), then press Enter to execute:
Selection.ShapeRange(1).Name = "Name to assign"
Use this Name in the code above
(disclaimer: i'm not a VBA programmer by occupation)
Attached to buttons in the Ribbon I have code to toggle the company logo in a Word Document.
One button for the logo type A, a second button for logo type B and a third for no logo (logo is preprintend on paper)
First I remove the logo with removeLogo and then i add it the requested logo with setLogoAt.
The first button click is fine (e.g. for Logo Type A), a logo is added to the header of the document. When i click an other button (e.g for Logo Type B) Word crashes (probably on removing the current logo)
What is wrong with my code (or less probably: with Word?)
Sub setLogoAt(left As Integer, path As String)
Dim logoShape As Shape
Dim anchorLocation As Range
Dim headerShapes As Shapes
Set logoShape = ActiveDocument. 'linebreks for readability
.Sections(1)
.Headers(wdHeaderFooterPrimary)
.Shapes
.AddPicture(FileName:=path, LinkToFile:=False,
SaveWithDocument:=True, left:=0,
Top:=0, Width:=100, Height:=80)
logoShape.name = "CompanyLogo"
logoShape.RelativeHorizontalPosition = wdRelativeHorizontalPositionPage
logoShape.RelativeVerticalPosition = wdRelativeVerticalPositionPage
logoShape.Top = CentimetersToPoints(0.1)
logoShape.left = CentimetersToPoints(left)
End Sub
Sub removeLogo()
Dim headerShapes As Shapes
Set headerShapes = ActiveDocument.Sections(1).Headers(wdHeaderFooterPrimary).Shapes
Dim shapeToDelete As Shape
If (headerShapes.Count > 0) Then
If Not IsNull(headerShapes("CompanyLogo")) Then
Set shapeToDelete = headerShapes("CompanyLogo")
End If
End If
If Not (shapeToDelete Is Nothing) Then
shapeToDelete.Delete
End If
End Sub
edit
I steped trough my code. All is fine until I reach the line shapteToDelete.Delete in removeLogo. Here Word crashes hard, even while debugging. I'm using Word 2007 (and that is a requirement)
edit2
I cleared all macros, all normals.dot, all autoloading templates, then created a new document with the two routines above and this test method:
Sub test()
setLogoAt 5, "C:\path\to\logo.jpg"
removeLogo
setLogoAt 6, "C:\path\to\logo.jpg"
End Sub
When I run test it crashes in removeLogo at shapeToDelete.Delete.
Edit 3
I 'solved' the problem by first making the headers/footers view the active view in Word, then deleting the Shape and then returning to normal view. Very strange. It works but as a programmer I'm not happy.
Another potential solution is to try and select the shape first and then delete the selection:
shapeToDelete.Select
Selection.Delete
You would probably want to switch off screen updating if this works, else you'll get flickering as Word moves around the document.
I've experienced this problem before and normally with an automation error: "The object invoked has disconnected from its clients". I haven't yet found a solution.
However a good workaround is to hide the shape rather than delete it.
So:
shapeToDelete.Visible = False
This works:
I only have 2 boxes to hide so this isn't generic
Private Sub btnPrint_Click()
Dim hdrShapes As Shapes
Dim S As Shape
Dim aTohide(2) As String
Dim iNdx, i As Integer
iNdx = 0
' Hide buttons and print
Set hdrShapes = ActiveDocument.Sections(1).Headers(wdHeaderFooterPrimary).Shapes
' GET BUTTON NAMES (ACTUALLY TEXT BOXES
For Each S In hdrShapes
If S.Type = msoTextBox Then
aTohide(iNdx) = S.Name
iNdx = iNdx + 1
End If
Next
' now hide , use the arrays as the for each statement crashes
For i = 0 To 1
hdrShapes(aTohide(i)).Visible = msoFalse
Next
' print it
With ActiveDocument
.PrintOut
End With
' and unhide the buttons
For i = 0 To 1
hdrShapes(aTohide(i)).Visible = msoTrue
Next
Set hdrShapes = Nothing
End Sub