i have this table,
id activity type start_date
1 a type_o 01/01/20
1 b type_o 05/01/20
1 c type_o 07/01/20
1 d type_o 23/01/20
1 e type_o 24/01/20
2 a type_k 08/01/20
2 b type_k 10/01/20
2 c type_k 11/01/20
2 d type_k 12/01/20
3 a type_h 12/01/20
3 c type_h 13/01/20
3 e type_h 14/01/20
all activities are (a,b,c,d,e)
i want it to look like this,
id type a b c d e
1 type_o 01/01/20 05/01/20 07/01/20 23/01/20 24/01/20
2 type_k 08/01/20 10/01/20 11/01/20 null null
3 type_h 12/01/20 null 13/01/20 null 12/01/20
where we compensate null in other activities not exists in some id's,
i don't understand the pivot keyword in sql, any help ?
You must be looking for this:
SELECT * FROM
(SELECT * FROM YOUR_TABLE)
PIVOT
(MAX(START_DATE) as START_DATE FOR ACTIVITY IN ('a' as a, 'b' as b, 'c' as c, 'd' as d, 'e' as e))
A more universal solution is to use CASE - WHEN statements.
The advantage is - the code is more portable across different SQL flavours and you can take care of duplicates in the records, if needed down the line.
select id,type
,case when activity = 'a' then min(start_date) else null end as `a`
,case when activity = 'b' then min(start_date) else null end as `b`
,case when activity = 'c' then min(start_date) else null end as `c`
,case when activity = 'd' then min(start_date) else null end as `d`
group by 1,2
Use conditional aggregation:
select id, type,
max(case when activity = 'a' then start_date end) as a,
max(case when activity = 'b' then start_date end) as b,
max(case when activity = 'c' then start_date end) as c,
max(case when activity = 'd' then start_date end) as d,
max(case when activity = 'e' then start_date end) as e
from thistable
group by id, type;
Related
Edit: when 5 or 9 does not exist, i need a null value (or another flag)
I have 3 columns. SECTION, STATUS and NAME. Within a SECTION there are a maximum of 10 rows (STATUS 1 to 10). I have to compare the value of NAME for STATUS 5 and 9 within a SECTION. AND then indicate if those 2 NAMES (for STATUS 5 and 9) are the same for each SECTION.
section status name
1 5 a
1 6 a
1 9 b
2 4 c
2 5 d
2 9 d
2 10 d
3 5 e
3 10 e
Desired output
Section equalnames
1 no
2 yes
3 null/flag
select
a.section,
case
when a.name = b.name then 'YES'
when a.name <> b.name then 'NO'
when (a.name is null or b.name is null) then 'NULL' end
from
(select * from <table> where status = 5) a
full join (select * from <table> where status = 9) b
on a.section = b.section
With conditional aggregation:
SELECT section,
MAX(CASE WHEN status = 5 THEN name END) =
MAX(CASE WHEN status = 9 THEN name END) equalnames
FROM tablename
WHERE status IN (5, 9)
GROUP BY section
ORDER BY section
See the demo.
Results:
section | equalnames
------- | ----------
1 | f
2 | t
3 | null
You could try using a left join on same table for 5 and 9
select a.section, a.status s5, a.name n5, b.status b9, b.name n9
, case when a.name = b.name the yes
when a.name is null or b.name is nul the NULL
when a.name <> b.name then no end equalname
from my_table a
left join my_table b a.section = b.section and a.status =5 and b.status=9
A more optimised solution could be with cte and window function:
with cte as (
select section, count(status)over(partition by section,name order by section) count_with_same_name,
count(status)over(partition by section order by section) count_with_different_name
from tname where status in (5,9))
select section,(case when (max(count_with_same_name)=2) then 'Yes' when (max(count_with_different_name)=2) then 'No' else 'null/flag' end)
from cte
group by section
Output:
I think you just want conditional aggregation:
select section,
(case when min(case when status = 5 then name end) =
min(case when status = 9 then name end)
then 'yes'
when count(case when status in (5, 9) then status end) < 2
then 'null/flag'
else 'no'
end)
from t
group by section;
No join is needed and I would not advise one for this problem.
In PostgreSQL, how can I merge multiple columns into one column with multiple rows?
The columns are all boolean, so I want to:
Filter for true values only
Replace the true value (1) with the name of the column (A, B or C)
I have this table:
ID | A | B | C
1 0 1 0
2 1 1 0
3 0 0 1
4 1 0 1
5 1 0 0
6 0 1 1
I want to get this table:
ID | Letter
1 B
2 A
2 B
3 C
4 A
4 C
5 A
6 B
6 C
I think you need something like this:
SELECT ID, 'A' as Letter FROM table WHERE A=1
UNION ALL
SELECT ID, 'B' as Letter FROM table WHERE B=1
UNION ALL
SELECT ID, 'C'as Letter FROM table WHERE C=1
ORDER BY ID, Letter
SELECT ID,
(CASE
WHEN TABLE.A = 1 then 'A'
WHEN TABLE.B = 1 then 'B'
WHEN TABLE.C = 1 then 'C'
ELSE NULL END) AS LETTER
from TABLE
You may try this.
insert into t2 select id, 'A' from t1 where A=1;
insert into t2 select id, 'B' from t2 where B=1;
insert into t2 select id, 'C' from t3 where C=1;
If you care about the order, then you can do this.
insert into t3 select id, letter from t2 order by id, letter;
W/o UNION
You can use a single query to get the desired output.Real time example
select id
,regexp_split_to_table((
concat_ws(',', case
when a = 0
then null
else 'a'
end, case
when b = 0
then null
else 'b'
end, case
when c = 0
then null
else 'c'
end)
), ',') l
from c1;
regexp_split_to_table() & concat_ws()
I am using sql 2008
My data set looks like
Entity Type1 Type2 Balance
1 A R 100
1 B Z 200
1 C R 300
2 A X 1000
2 B Y 2000
My output should look like
Entity A-Type2 A-Balance B-Type2 B-Balance C-Type2 C-Balance
1 R 100 Z 200 R 300
2 X 1000 Y 2000 0
Now I started writing a pivot query, and I think I can get away with MAX because there should be one record per Entity/Type1 combination. But can not figure out how to do two fields in one pivot. Is this possible? Is this something that CTE could help out with?
Easiest is the MAX idea, but with a CASE statement, e.g.:
SELECT
Entity,
MAX(CASE WHEN Type1 = 'A' THEN Type2 ELSE NULL END) AS AType2,
MAX(CASE WHEN Type1 = 'A' THEN Balance ELSE NULL END) AS ABalance,
MAX(CASE WHEN Type1 = 'B' THEN Type2 ELSE NULL END) AS BType2,
MAX(CASE WHEN Type1 = 'B' THEN Balance ELSE NULL END) AS BBalance,
MAX(CASE WHEN Type1 = 'C' THEN Type2 ELSE NULL END) AS CType2,
MAX(CASE WHEN Type1 = 'C' THEN Balance ELSE NULL END) AS CBalance
FROM
...
GROUP BY
Entity
In other words, only use the value when Type1 is a specific value (with other Type1 values getting a null).
You just use conditional aggregation for the pivoting like this:
select Entity,
max(case when Type1 = 'A' then Type2 end) as A_Type2,
max(case when Type1 = 'A' then Balance else 0 end) as A_Balance,
max(case when Type1 = 'B' then Type2 end) as B_Type2,
max(case when Type1 = 'B' then Balance else 0 end) as B_Balance,
max(case when Type1 = 'C' then Type2 end) as C_Type2,
max(case when Type1 = 'C' then Balance else 0 end) as C_Balance
from MyDataSet mds
group by Entity;
Here's doing it with a pivot and a lookup.
SELECT
data.Entity,
ISNULL(a.Type2,'') AS [A-Type2],
ISNULL([A-Balance],0) AS [A-Balance],
ISNULL(b.Type2,'') AS [B-Type2],
ISNULL([B-Balance],0) AS [B-Balance],
ISNULL(c.Type2,'') AS [C-Type2],
ISNULL([C-Balance],0) AS [C-Balance]
FROM
(
SELECT
Entity,
A AS [A-Balance],
B AS [B-Balance],
C AS [C-Balance]
FROM
(
SELECT Entity, Type1, Balance FROM #table
) t
PIVOT (
MAX(Balance)
FOR Type1 IN ([A],[B],[C])
) piv
) data
LEFT OUTER JOIN #table a on a.Type1 = 'A'
AND a.Entity = data.Entity AND a.Balance = [A-Balance]
LEFT OUTER JOIN #table b on b.Type1 = 'B'
AND b.Entity = data.Entity AND b.Balance = [B-Balance]
LEFT OUTER JOIN #table c on c.Type1 = 'C'
AND c.Entity = data.Entity AND c.Balance = [C-Balance]
I have to compare two tables values;
TABLE_A TABLE_B
ID TYPE ID TYPE
12345 12345 3
67891 12345 7
36524 67891 3
67891 2
67891 5
36524 3
Logic: I have to compare table_A id with Table_B id
if found 3&7
good
else found 3 only
avg
else if found 7 only
bad
These good, bad and avg should go back to table A type values.
could any one help me how to write this code in PLSQL.
Assuming that you are considering type 3 and 7 only for your calculations, you can use following merge statement, no need of PL-SQL
merge into table_a a
using (select id, case (listagg(type, ',') within group (order by type))
when '3,7' then 'Good'
when '3' then 'Avg'
when '7' then 'Bad'
else null
end new_type
from table_b
where type in (3,7)
group by id) b
on (a.id = b.id)
when matched then
update set type = new_type;
For Oracle versions prior to 11 g release 2, use following:
merge into table_a a
using (select id, case (trim(both ',' from min(decode(type, 3, 3, null))||','||min(decode(type, 7, 7, null))))
when '3,7' then 'Good'
when '3' then 'Avg'
when '7' then 'Bad'
else null
end new_type
from table_b
where type in (3,7)
group by id) b
on (a.id = b.id)
when matched then
update set type = new_type;
It has been assumed that there are unique combination of id an type in table_b.
I am interpreting what you mean as saying that you want to output 'good' when TableB contains both 3 and 7, 'avg' when it contains only 3, and so on. Here is a way to get this result:
select a.id,
(case when sum(case when b.type = 3 then 1 else 0 end) > 1 and
sum(case when b.type = 7 then 1 else 0 end) > 0
then 'good'
when sum(case when b.type = 3 then 1 else 0 end) > 1
then 'avg'
when sum(case when b.type = 7 then 1 else 0 end)
then 'bad'
end) as logic
from tableA a left outer join
tableB b
on a.id = b.id
group by a.id;
I have a table like below -
Student ID | History | Maths | Geography
1 A B B
2 C C E
3 D A B
4 E D A
How to find out how many students got A in history, B in maths and E in Geography with a single sql query ?
If you want to get number of students who got A in History in one column, number of students who got B in Maths in second column and number of students who got E in Geography in third then:
select
sum(case when [History] = 'A' then 1 else 0 end) as HistoryA,
sum(case when [Maths] = 'B' then 1 else 0 end) as MathsB,
sum(case when [Geography] = 'E' then 1 else 0 end) as GeographyC
from Table1
If you want to count students who got A in history, B in maths and E in Geography:
select count(*)
from Table1
where [History] = 'A' and [Maths] = 'B' and [Geography] = 'E'
If you want independent counts use:
SELECT SUM(CASE WHEN Condition1 THEN 1 ELSE 0 END) AS 'Condition1'
,SUM(CASE WHEN Condition2 THEN 1 ELSE 0 END) AS 'Condition2'
,SUM(CASE WHEN Condition3 THEN 1 ELSE 0 END) AS 'Condition3'
FROM YourTable
If you want multiple conditions for one count use:
SELECT COUNT(*)
FROM YourTable
WHERE Condition1
AND Condition2
AND Condition3
It sounds like you want multiple independent counts:
SELECT SUM(CASE WHEN History = 'A' THEN 1 ELSE 0 END) AS 'History A'
,SUM(CASE WHEN Maths = 'B' THEN 1 ELSE 0 END) AS 'Maths B'
,SUM(CASE WHEN Geography = 'E' THEN 1 ELSE 0 END) AS 'Geography E'
FROM YourTable
You can try to select from multiple select statements
SELECT t1.*, t2.*, t3.* FROM
(SELECT COUNT(*) AS h FROM students WHERE History = 'A') as t1,
(SELECT COUNT(*) AS m FROM students WHERE Maths = 'B') as t2,
(SELECT COUNT(*) AS g FROM students WHERE Geography = 'E') as t3