For some odd reason, my code does not work in all instances. It does not catch every instance where there is only 1 space after a period. I was wondering if anyone knows why this may be. I went through every line and I can't figure out why it won't work. It's pretty basic of a code.
The goal behind this code:
period with 1 space goes to period with 2 spaces
period with 2 spaces stay the same
any double spaces in the document that do not follow a period are changed to 1 space.
Mr., Mrs., Miss., Ms. only have 1 space after them.
Sub Space_corrections()
' two spaces go to one space entire doc
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = " "
.Replacement.Text = " "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' One space after periods goes to two spaces
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ". "
.Replacement.Text = ". "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Three spaces after periods goes to two spaces
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ". "
.Replacement.Text = ". "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Mr. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Mr. "
.Replacement.Text = "Mr. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Mrs. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Mrs. "
.Replacement.Text = "Mrs. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Ms. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Ms. "
.Replacement.Text = "Ms. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
' Two spaces after Miss. goes to one space
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "Miss. "
.Replacement.Text = "Miss. "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub```
UPDATE/EDIT:
I changed over to this code, but it does to change all of the instances. I am not sure what the cause is.
There is no special font on them or anything. They are sentences that are contained by a list format, but every other instance that was changed was also contained in a list format.
These are the instances that went unchanged:
**"shipped. According"
"materials. The"**
updated code:
Sub Space_corrections_123()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(.)( {1,})"
.Replacement.Text = "\1 "
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = True
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
You can simplify the find and replace for the Mr/Mrs/Miss/Ms/Dr/Professor etc by using a wildcard search
.findtext="([rs])(. )"
.replacementText="\1. "
Which will find any word ending in a r or s followed by a point and two spaces and replace with the found character plus point and one space.
You can also do a wildcard search to consolidate the replacement of . by to . two spaces using
.findtext="(.)( {1,})"
.replacementText="\1 "
Try:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Format = False
.Wrap = wdFindContinue
.MatchWildcards = True
.Text = "([ ^s]){2,}"
.Replacement.Text = "\1"
.Execute Replace:=wdReplaceAll
.Text = "(. )"
.Replacement.Text = "\1 "
.Execute Replace:=wdReplaceAll
.Text = "([DM][irs]{1,3}.)[ ]{2,}"
.Replacement.Text = "\1 "
.Execute Replace:=wdReplaceAll
End With
End With
Application.ScreenUpdating = True
End Sub
Note the 'D' in '[DM]'. That allows you to find Dr., & Drs. as well (in case there's more than one). You can delete the 'D' if it's unnecessary.
Related
I am using Microsoft Visual Basic on Word. I want to limit the find and replace function to operate only on certain pages of the document. How do I do it?
As of now, it will execute it the whole document which is not preferred.
Sub X_entity()
'
' Replaces lower and greater than symbols to html entity
'
'
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = ">"
.Replacement.Text = ">"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
With Selection.Find
.Text = "<"
.Replacement.Text = "<"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Instead of using Selection (which is poor practice anyway), you should point to the range of each page in turn, using Find/Replace on the designated range only. For example:
Sub ProcessPages()
Application.ScreenUpdating = False
Dim i As Long, ArrPgs()
' Define the pages to process
ArrPgs = Array("7", "4", "3", "2")
For i = 0 To UBound(ArrPgs)
' Process the defined pages
With ActiveDocument.Range.GoTo(What:=wdGoToPage, Name:=ArrPgs(i)).GoTo(What:=wdGoToBookmark, Name:="\page").Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWildcards = False
.Text = ">"
.Replacement.Text = ">"
.Execute Replace:=wdReplaceAll
.Text = "<"
.Replacement.Text = "<"
.Execute Replace:=wdReplaceAll
End With
Next i
Application.ScreenUpdating = True
End Sub
With the above code, the pages are processed in reverse order in case the Find/Replace messes with the pagination.
I have a Word 2010 document with some plus minus symbols surrounded by numbers.
I would like to format the plus minus symbols so that there is an empty space before and after each plus minus symbol.
My code is able to find the symbol.
Unfortunately, the ReplaceString leaves a white box instead of the plus minus symbol.
Dim ReplaceString As String
ReplaceString = " " & ChrW(-3919) & " "
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Highlight = True
With Selection.Find
.Text = ChrW(-3919) 'plus/minus symbol
.Forward = True
.Format = True
.MatchCase = False
.Replacement.Text = ReplaceString
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
.Replacement.ClearFormatting
.Wrap = wdFindContinue
End With
Selection.Find.Execute Replace:=wdReplaceAll
Try:
With ActiveDocument.Range.Find
.ClearFormatting
.Text = ChrW(-3919) 'plus/minus symbol
With .Replacement
.ClearFormatting
.Highlight = True
.Text = " ^& "
End With
.Format = True
.Forward = True
.Wrap = wdFindContinue
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
.Execute Replace:=wdReplaceAll
End With
Is there a better way to take a list of addresses on word and separate them down to single line.
I have about 200 addresses to work through and they have to go from this
To this
So it can end up being copied like this into excel
The code I am currently Using is as follows but all that does is uses the replace function to change special formatting characters.
It isn't the cleanest method and if for instance some hasnt used a paragragh break but just a new line then it won't work.
Sub AddressMacro()
'
' AddressMacro Macro
'
'
ActiveWindow.ActivePane.View.ShowAll = Not ActiveWindow.ActivePane.View. _
ShowAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "^p^p"
.Replacement.Text = "^l"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
Selection.Find.Execute Replace:=wdReplaceAll
End With
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "^p"
.Replacement.Text = "^t"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
Selection.Find.Execute Replace:=wdReplaceAll
End With
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "^i"
.Replacement.Text = "^p"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
Selection.Find.Execute Replace:=wdReplaceAll
End With
ActiveWindow.ActivePane.View.ShowAll = Not ActiveWindow.ActivePane.View. _
ShowAll
End Sub
How about: (replaces)
'1) Chr$(9) to Chr$(32)
'2) Chr$(10) to Chr$(13)
'3) Chr$(11) to Chr$(13)
'4) Chr$(13) & Chr$(13) to Chr$(13)
'5) repeat 4 until there are none
'6) Chr$(13) to Chr$(9)
'7) Chr$(133) to Chr$(13)
EDIT: Here's what I had in mind: (It's a lot -- there's a bottomless pit of information on Word VBA -- http://word.mvps.org/faqs/MacrosVBA/index.htm -- good luck.)
Option Explicit
Sub main()
Call doReplace(Chr$(9), Chr$(32))
Call doReplace(Chr$(10), Chr$(13))
Call doReplace(Chr$(11), Chr$(13))
Do While doReplace(Chr$(13) & Chr$(13), Chr$(13))
Loop
Call doReplace(Chr$(13), Chr$(9))
Call doReplace(Chr$(133), Chr$(13))
End Sub
Function doReplace(OldText$, NewText$) As Boolean
With ThisDocument.Content.Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = OldText
.Replacement.Text = NewText
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchWildcards = False
.MatchSoundsLike = False
.MatchAllWordForms = False
doReplace = .Execute(Replace:=wdReplaceAll)
End With
End Function
I have a dictionary in MS Word format which I'd like to have cleaned from any paragraph breaks within dictionary entries, and keep only paragraph breaks that separate any two dictionary entries. This is how the layout of the dictionary looks now:
First picture http://img43.imageshack.us/img43/6476/snapshotpr.jpg
I'd need a macro or a regular expression that would first remove all the paragraph breaks, from the document, which would produce this layout:
Second picture http://img824.imageshack.us/img824/5219/snapshot1i.jpg
and then in the next step would add paragraph breaks only before the dictionary entries, which means only before bold phrases followed by the phonetic transcription in square brackets, to get this layout:
Third picture http://img849.imageshack.us/img849/2003/snapshot2qf.jpg
I used this site to help me with the paragraph markers.
Again, I recorded a macro with something did manually with 4 find/replace (two steps were used to make sure that a word followed by a square bracket was matched). Here's the macro:
Sub Separator()
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "^13"
.Replacement.Text = ""
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
.MatchFuzzy = False
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Font.Bold = True
With Selection.Find
.Text = "\["
.Replacement.Text = "^&"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Font.Bold = True
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "[a-z\-]# \["
.Replacement.Text = "^p^&"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Font.Bold = True
Selection.Find.Replacement.ClearFormatting
With Selection.Find.Replacement.Font
.Bold = False
.Italic = False
End With
With Selection.Find
.Text = "\["
.Replacement.Text = "["
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchByte = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchFuzzy = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Let me know if there's anything to tweak and I'll try to change it :)
EDIT: Part added for hyphens.
The following code works, but it performs everything on the entire document. I'd like to highlight a block of text, then when I run the macro only have it work on the highlighted text. How do I do that? Thanks...
Sub DoCodeNumberStyle(numchars As String)
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "(^13)([0-9]{" + numchars + "}) "
.Replacement.Text = "\1###\2$$$ "
.Forward = True
.Wrap = wdFindAsk
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Style = ActiveDocument.Styles("CodeNumber")
With Selection.Find
.Text = "###([0-9]{" + numchars + "})$$$"
.Replacement.Text = "\1"
.Forward = True
.Wrap = wdFindAsk
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
Sub CodeNumberStyle()
DoCodeNumberStyle ("1")
DoCodeNumberStyle ("2")
End Sub
PostScript:
One additional thing I've discovered: if you do more than one find on a Selection, the first find loses/changes the Selection, so the others are no longer bounded by the original Selection (and a wdReplaceAll will continue to the end of the document). To fix this, capture the Selection into a Range. Here's the final version of my method, which now does everything I need, is restricted to the original highlighted selection (even with 3 find-and-replacements), and has also been minimized, code-wise:
Sub AAACodeNumberStyleHighlightedSelection()
With Selection.Range.Find
.ClearFormatting
.Style = ActiveDocument.Styles("Code")
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
' First line:
.Text = "1 //"
.Replacement.Text = "###1$$$ //"
.MatchWildcards = False
.Execute Replace:=wdReplaceAll
' Rest of lines:
.Text = "(^13)([0-9]{1,2}) "
.Replacement.Text = "\1###\2$$$ "
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
' Now style the line numbers:
.Text = "###([0-9]{1,2})$$$"
.Replacement.Text = "\1"
.Replacement.Style = ActiveDocument.Styles("CodeNumber")
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
End With
End Sub
Change .Wrap to wdFindStop and this should work for you. I think this might be a minor Word bug; the documentation says that the Wrap value
sets what happens if the search begins at a point other than the beginning of the document and the end of the document is reached (or vice versa if Forward is set to False) or if the search text isn't found in the specified selection or range.
But it seems like it forces the Find to go to the end of the document rather than taking the selection into account. Anyway, there's no need for wdFindAsk if you only plan to run this on selections.
I, too, found that even when beginning a FIND loop on a range, the range is redefined by FIND, and so continuous loop on .execute goes beyond the original range to the end of the document. wdFindStop stops only at the end of the document, not at the end of the original range.
So, I inserted an IF statement:
do while .find.found
...
If .find.parent.InRange(doc.Bookmarks("BODY").Range) = False Then Exit Do
...
.execute
loop
Set myRange = Selection.Range
myRange.Select
With Selection.Find
.Text = "Apple"
.Replacement.Text = "Banana"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
myRange.Select
With Selection.Find
.Text = "red"
.Replacement.Text = "yellow"
.Forward = True
.Wrap = wdFindStop
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
'.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll