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I'm trying to show the miles between an origin and destination. Problem is I'm having trouble writing the query to properly show the destination address. There is only one location table which holds the address of both origin and destination. What am I doing wrong here?
I thought I would get the proper address for the destination and/or location but it's not working.
select dist.DistanceId,
dist.OriginLocationId,
l.Address,
dist.DestinationLocationId,
l.Address,
dist.DistanceInMiles
from DistanceMatrixFromGoogleMapsApi as dist
join locations as l
on l.id = dist.OriginLocationId or l.id = dist.DestinationLocationId
where OriginLocationId in (30506,53097,30362,30505,30377,30378,30594,30379,30514,30518,30517,55055,30360,30515,30516,30616,30512,30511,30510,30513,30381,49129)
and DestinationLocationId in (53097,30362,30505,30377,30378,30594,30379,30514,30518,30517,55055,30360,30515,30516,30616,30512,30511,30510,30513,30381,49129,34690)
These are the results I get
As suggested by #Larnu -
SELECT
dist.DistanceId,
dist.OriginLocationId,
orig.Address,
dist.DestinationLocationId,
dest.Address,
dist.DistanceInMiles
FROM DistanceMatrixFromGoogleMapsApi as dist
JOIN locations as orig
ON dist.OriginLocationId = orig.id
JOIN locations as dest
ON dist.DestinationLocationId = dest.id
WHERE dist.OriginLocationId in (30506,53097,30362,30505,30377,30378,30594,30379,30514,30518,30517,55055,30360,30515,30516,30616,30512,30511,30510,30513,30381,49129)
AND dist.DestinationLocationId in (53097,30362,30505,30377,30378,30594,30379,30514,30518,30517,55055,30360,30515,30516,30616,30512,30511,30510,30513,30381,49129,34690)
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I have a variable with a list on it and I need to use its value for my find option. I get an error when I set my id_user to id_u.
Here is the list
id_u = user_key[0]
This is my SELECT and WHERE
find = ("SELECT * FROM hashtags WHERE id_user=id_u")
You have to concatenate SELECT string with variable value.
Try like this:
id_u = user_key[0]
find = ("SELECT * FROM hashtags WHERE id_user=" + id_u)
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I'm trying to understand a code from my teacher and he uses MonthBegin(1) from Pandas to calculate the distance from months on a data frame.
I already tried to read the documentation but its description is too simple and there are no examples :(
The code that I'm trying to understand is:
month_distance = int(((df['ResearchDate'][index + 1] + MonthBegin(1)) - (df['ResearchDate'][index] + MonthBegin(1))).days / 31)
Consider the following code:
import pandas as pd
from pandas.tseries.offsets import MonthBegin
data = pd.date_range(start='1/1/2021', periods=10, freq="8d")
df = pd.DataFrame(data)
df["mb1"] = df[0] + MonthBegin(1)
print(df)
Basically it is being used so your teacher can get the difference in number of months by rounding dates to the next month's beginning.
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I am having trouble creating a data frame with the following data:
Force (N) microstrain1 microstrain2 microstrain3 microstrain4 microstrain5
24.838 9.689 -20.299 19.785 15.601 -7.681
49.691 22.610 -40.797 41.304 32.200 -15.332
75.309 33.357 -61.678 62.512 48.726 -22.422
97.227 41.944 -80.524 81.011 62.266 -30.228
121.641 52.692 -100.775 100.703 77.248 -36.884
Every time I try to use a delimiter I get the following message:
/Users/macbookpro/PycharmProjects/Projects/Lab_3/Bending.py:5: ParserWarning: Falling back to the 'python' engine because the 'c' engine does not support regex separators (separators > 1 char and different from '\s+' are interpreted as regex); you can avoid this warning by specifying engine='python'.
df1 = pd.read_csv('MEE322-thurs_1040_group1_9.5cm.txt',delimiter=' ')
Did you try the python engine instead of the c engine?:
df1 = pd.read_csv('MEE322-thurs_1040_group1_9.5cm.txt', delimiter=' ', engine='python')
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I am using SQL server 2008. I have a database (table name :Data) where one column's name is title and another one is date.
One of the entry in the first column is :
WOLVERINE LE COMBAT DE L'IMMORTEL
However here what is not working :
select date from Data where title = 'WOLVERINE LE COMBAT DE L''IMMORTEL'
select date , title from Data where title LIKE '%WOLVERINE LE COMBAT DE L''IMMORTEL%'
select date , title from Data where title LIKE '%WOLVERINE LE%'
Here what is working :
select date , title from Data where title LIKE '%WOLVERINE%'
select date , title from Data where title LIKE '%LE COMBAT DE L''IMMORTEL%'
select date , title from Data where title LIKE '%WOLVERINE LE%'
Yes, it works for 'WOLVERINE LE' when there is two spaces, even though I am pretty sure there is only one space in the database ( that is the case when I do a request).
Does someone know how come there is this error ?
EDIT : Well sorry it seems like there was really two spaces between them, when I tried to display it in my aspx page, the two spaces are automatically replaced with one space, that is why I could not see it.
If you have any confusion about the no. of spaces then just remove all the white space form both the sides
select date
from Data
where REPLACE(title,' ','') = REPLACE('WOLVERINE LE COMBAT DE L''IMMORTEL',' ','')