SQL Oracle exctrac value from XML unordered Collection - sql

Question

I have a clob with XML like this:
<Data>
<Email_List>
<Email>
<EmailPrimaryFlag>Y</EmailPrimaryFlag>
<EmailAddress>test#test.it</EmailAddress>
</Email>
<Email>
<EmailPrimaryFlag>N</EmailPrimaryFlag>
<EmailAddress>test2#test2.it</EmailAddress>
</Email>
<Email>
<EmailPrimaryFlag>N</EmailPrimaryFlag>
<EmailAddress>test3#test3.it</EmailAddress>
</Email>
</Email_List>
<User>Name_User</User>
<City>City_test</City>
</Data>
I need to do an extract only for PrimaryFlag=Y
Usually i do something like this:
select
extract(xmltype(PAYLOAD),'//*:User/text()').getStringVal() as User,
extract(xmltype(PAYLOAD),'//*:City/text()').getStringVal() as City,
but i don't know how i can extract for mail with PrimaryFlag=Y
Special Thanks
Michel

Answer 1

Avoid using EXRACT() as it is deprecated.
with t (payload) as (
select to_clob('<Data>
<Email_List>
<Email>
<EmailPrimaryFlag>Y</EmailPrimaryFlag>
<EmailAddress>test#test.it</EmailAddress>
</Email>
<Email>
<EmailPrimaryFlag>N</EmailPrimaryFlag>
<EmailAddress>test2#test2.it</EmailAddress>
</Email>
<Email>
<EmailPrimaryFlag>N</EmailPrimaryFlag>
<EmailAddress>test3#test3.it</EmailAddress>
</Email>
</Email_List>
<User>Name_User</User>
<City>City_test</City>
</Data>') from dual)
select x.* from t, xmltable(
'/Data'
passing xmltype(payload)
columns
primary_email varchar2(60) path 'Email_List/Email/EmailAddress[../EmailPrimaryFlag = "Y"]',
username varchar2(60) path 'User',
city varchar2(60) path 'City'
)x;
PRIMARY_EMAIL USERNAME CITY
------------------------------------------------------------ ------------------------------------------------------------ ------------------------------------------------------------
test#test.it Name_User City_test