The following query when I that execute
SELECT CASE
WHEN spd.IS_MAIN_DEFECT='Y'
THEN spd.piece_Defect_num_id
ELSE min(spd.PIECE_DEFECT_NUM_ID)
END AS defect
FROM piece P,
STY_PIECE_DEFECT spd,
STY_DEFECT_CATALOGUE sdc,
piece_history ph,
piece_history_out pho,
PLANT_CONFIG pc
(...inner join and where clause)
GROUP BY p.PIECE_ID,
CASE
WHEN spd.IS_MAIN_DEFECT='Y'
THEN spd.piece_Defect_num_id
ELSE min(spd.PIECE_DEFECT_NUM_ID)
end
It seems error
ORA-00934: group function is not allowed here
I guess , there is error min() in group by.
How can I solve this problem?
You have to use analytical MIN() function like the below without group by
SELECT distinct CASE WHEN spd.IS_MAIN_DEFECT='Y'
THEN spd.piece_Defect_num_id
ELSE min(spd.PIECE_DEFECT_NUM_ID) over () END AS defect
FROM piece P , STY_PIECE_DEFECT spd ,STY_DEFECT_CATALOGUE sdc ,piece_history ph
, piece_history_out pho, PLANT_CONFIG pc
(...inner join and where clause)
I understood you want to preserve the PIECE_DEFECT_NUM_ID in rows with IS_MAIN_DEFECT = 'Y' and get the MIN value for the non-main defect lines.
The simplest solution for the case there is only one row per PIECE_ID with IS_MAIN_DEFECT = 'Y' - you group on PIECE_ID, IS_MAIN_DEFECTand calculates min(PIECE_DEFECT_NUM_ID)
which is fine a MIN for one row group is equal to the original value
select PIECE_ID,IS_MAIN_DEFECT,
min(PIECE_DEFECT_NUM_ID) PIECE_DEFECT_NUM_ID
from tab
group by PIECE_ID, IS_MAIN_DEFECT
order by 1,2 desc;
In case you can have more rows (same PIECE_ID) with the main flag, simple select them ungrouped and add the grouped non-main part using UNION ALL
select PIECE_ID,IS_MAIN_DEFECT,PIECE_DEFECT_NUM_ID
from tab
where IS_MAIN_DEFECT = 'Y'
UNION ALL
select PIECE_ID,IS_MAIN_DEFECT,
min(PIECE_DEFECT_NUM_ID) PIECE_DEFECT_NUM_ID
from tab
where nvl(IS_MAIN_DEFECT,'N') != 'Y'
group by PIECE_ID, IS_MAIN_DEFECT
Related
I have a query like:
select nvl(nvl(sum(a.quantity),0)-nvl(cc.quantityCor,0),0)
from RCV_TRANSACTIONS a
LEFT JOIN (select c.shipment_line_id,c.oe_order_line_id,nvl(sum(c.quantity),0) quantityCor
from RCV_TRANSACTIONS c
where c.TRANSACTION_TYPE='CORRECT'
group by c.shipment_line_id,c.oe_order_line_id) cc on (a.shipment_line_id=cc.shipment_line_id and a.shipment_line_id=7085740)
where a.transaction_type='DELIVER'
and a.shipment_line_id=7085740
group by nvl(cc.quantityCor,0);
The query runs OK, but returns no value. I want it to return 0 if there is no quantity found. Where have I gone wrong?
An aggregation query with a GROUP BY returns no rows if all rows are filtered out.
An aggregation query with no GROUP BY always returns one row, even if all rows are filtered out.
So, just remove the GROUP BY. And change the SELECT to:
select coalesce(sum(a.quantity), 0) - coalesce(max(cc.quantityCor), 0)
I may be wrong, but it seems you merely want to subtract CORRECT quantity from DELIVER quantity for shipment 7085740. You don't need a complicated query for that. Especially your GROUP BY clauses make no sense if that is what you are after.
One way to write this query would be:
select
sum(case when transaction_type = 'DELIVER' then quantity else 0 end) -
sum(case when transaction_type = 'CORRECT' then quantity else 0 end) as diff
from rcv_transactions
where shipment_line_id = 7085740;
I had a query like this and was trying to return 'X' when the item is not valid.
SELECT case when segment1 is not null then segment1 else 'X' end
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;
..but it was returning NULL.
Changed to use aggregation with no group by and now it returns 'X' when the item is not valid.
SELECT case when max(segment1) is not null then max(segment1) else 'X' end valid
--INTO v_orgValidItem
FROM mtl_system_items_b
WHERE segment1='1676001000'--'Jul-00'--l_item
and organization_id=168;--l_ship_to_organization_id_pb;
Here is another example, proving the order of operations really matters.
When there is no match for this quote number, this query returns NULL:
SELECT MAX(NVL(QUOTE_VENDOR_QUOTE_NUMBER,0))
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
..reversing the order of MAX and NVL makes all the difference. This query returns the NULL value condition:
SELECT NVL(MAX(QUOTE_VENDOR_QUOTE_NUMBER),0)
FROM PO_HEADERS_ALL
WHERE QUOTE_VENDOR_QUOTE_NUMBER='foo.bar';
My table has columns such as ID,Perdium and Location so I want to calculate all the perdiums given to an employee and the perdium share given in NY. The issue which I am facing is that SQL Server engine is throwing as error stating that location column isnt present in the GROUP BY clause(as needed in my use-case).If I include the location in the Group By clause I always get NYPerdiumShare as 1 which is not what I am expecting. Is there any workaround to this?
WITH CTE_Employee AS
(
SELECT ID,
SUM(Perdium) AS TotalPerdium,
CASE WHEN Location='NY' THEN SUM(Perdium) ELSE NULL END AS NYPerdium FROM EmployeePerdium
GROUP BY ID
)
SELECT ID,
TotalPerdium,
NYPerdium/TotalPerdium AS NYPerdiumShare
FROM CTE_Employee
You can eliminate the need to group by on anything other than ID by rewriting your query as follows to hide CASE inside an aggregate function:
WITH CTE_Employee AS (
SELECT
ID
, SUM(Perdium) AS TotalPerdium
, SUM(CASE WHEN Location='NY' THEN Perdium ELSE 0 END) AS NYPerdium
FROM EmployeePerdium
GROUP BY ID
)
SELECT
ID
, TotalPerdium
, NYPerdium/TotalPerdium AS NYPerdiumShare
FROM CTE_Employee
You don't need a cte here. Just use the sum window function.
SELECT DISTINCT
ID,
SUM(Perdium) OVER() as TotalPerdium
SUM(CASE WHEN Location='NY' THEN 1.0*Perdium ELSE 0 END) OVER(PARTITION BY ID)
/SUM(Perdium) OVER() AS NYPerdium
FROM EmployeePerdium
I have a table that has some duplicates. I can count the distinct records to get the Total Volume. When I try to Sum when the CompTia Code is B92 and run distinct is still counts the dupes.
Here is the query:
select
a.repair_week_period,
count(distinct a.notif_id) as Total_Volume,
sum(distinct case when a.header_comptia_cd = 'B92' then 1 else 0 end) as B92_Sum
FROM artemis_biz_app.aca_service_event a
where a.Sales_Org_Cd = '8210'
and a.notif_creation_dt >= current_date - 180
group by 1
order by 1
;
Is There a way to only SUM the distinct records for B92?
I also tried inner joining the table on itself by selecting the distinct notification id and joining on that notification id, but still getting wrong sum counts.
Thanks!
Your B92_Sum currently returns either NULL, 1 or 2, this is definitely no sum.
To sum distinct values you need something like
sum(distinct case when a.header_comptia_cd = 'B92' then column_to_sum else 0 end)
If this column_to_sum is actually the notif_id you get a conditional count but not a sum.
Otherwise the distinct might remove too many vales and then you probably need a Derived Table where you remove duplicates before aggregation:
select
repair_week_period,
--no more distinct needed
count(a.notif_id) as Total_Volume,
sum(case when a.header_comptia_cd = 'B92' then column_to_sum else 0 end) as B92_Sum
FROM
(
select repair_week_period,
notif_id
header_comptia_cd,
column_to_sum
from artemis_biz_app.aca_service_event
where a.Sales_Org_Cd = '8210'
and a.notif_creation_dt >= current_date - 180
-- only onw row per notif_id
qualify row_number() over (partition by notif_id order by ???) = 1
) a
group by 1
order by 1
;
#dnoeth It seems the solution to my problem was not to SUM the data, but to count distinct it.
This is how I resolved my problem:
count(distinct case when a.header_comptia_cd = 'B92' then a.notif_id else NULL end) as B92_Sum
I was using a simple sql query and getting an ordered list, but when I changed some of the values in the column I'm sorting by, those rows were no longer being sorted correctly.
select distinct u.Email,
case
when l.region_id is null then 'EU'
else l.region_id
end
as Location
from TB_User u
left join cat..location l on l.location=u.Location
where u.Username in (....)
order by l.region_id
I have about 5 rows that returned null for their region_id so they would be at the top of the result set. When I added the case and replaced their value, they still remain at the top. Is there anyway to make these rows sort according to their given value?
You can use CASE also in the ORDER BY. But in this case it seems that you instead want to order by the column which uses the CASE.
ORDER BY Location
If you instead want the null-regions at the bottom:
ORDER BY CASE WHEN l.region_id is null THEN 0 ELSE 1 END DESC,
Location ASC
If your rdbms doesn't support this (like SQL-Server does) you have to repeat it:
ORDER BY CASE WHEN l.region_id IS NULL THEN 'EU' ELSE l.region_id END ASC
You just order by the column value, which is null.
If you want to order by the case statement, just copy it in the order by clause:
order by
case
when l.region_id is null then 'EU'
else l.region_id end
If you are using SQL, try within the SELECT statement, use:
ISNULL(l.region_id, 'EU') AS Location
and then
ORDER BY 2
This will make your query:
SELECT DISTINCT u.Email, ISNULL(l.region_id, 'EU') AS Location
FROM TB_User u
LEFT JOIN cat..location l ON l.location=u.Location
WHERE u.Username in (....)
ORDER BY 2
I don't understand the purpose of using syntax code "CASE GROUPING"?
Unfortunately, I don't have the database to review the sourcecode below.
SELECT
CASE GROUPING(st.stor_name) WHEN 0 THEN st.stor_name ELSE 'ALL' END AS Store,
CASE GROUPING(s.type) WHEN 0 THEN s.type ELSE 'ALL TYPES' END AS Type,
SUM(s.qty) AS TotalSold
FROM
(SELECT DISTINCT st.stor_id, t.type, 0 AS qty
FROM stores st CROSS JOIN titles t
UNION ALL
SELECT
s.stor_id,
t.type, s.qty
FROM sales s JOIN titles t ON s.title_id=t.title_id) s
JOIN stores st ON (s.stor_id=st.stor_id)
GROUP BY st.stor_name, s.type WITH CUBE
CASE is a conditional expression, like an if statement.
GROUPING is a function that:
Indicates whether a specified column expression in a GROUP BY list is aggregated or not. GROUPING returns 1 for aggregated or 0 for not aggregated in the result set. GROUPING can be used only in the SELECT list, HAVING, and ORDER BY clauses when GROUP BY is specified.