I am trying to do a left join so that I get all of my rows from Table 1 even if there is no value corresponding to it in the second table.
My structures are:
Location Table:
ID LocName
1 Trk1
2 Trk2
3 Trk3
4 Unk
Quantity Table:
ID PartID Quantity LocationID
1 1 2 1
2 3 12 2
3 2 6 1
4 6 8 3
5 6 5 1
I am trying to join but also make a query on a specific PartID. My query is:
SELECT
INV_LOCATIONS.ID AS LocationID,
INV_LOCATIONS.NAME AS LocationName,
INV_QUANTITY.QUANTITY AS Quantity
FROM INV_LOCATIONS
LEFT JOIN INV_QUANTITY ON INV_LOCATIONS.ID = INV_QUANTITY.LOCATION_ID
WHERE INV_QUANTITY.PART_ID = 1;
My output right now would be:
ID LocName Quantity
1 Trk1 5
3 Trk3 8
The Desired output is:
ID LocName Quantity
1 Trk1 5
2 Trk2 NULL/0
3 Trk3 8
4 Unk NULL/0
I assume it is because I have the WHERE INV_QUANTITY.PART_ID = 1 and that is forcing it to be in the quantity table. I need to be able to verify it is on the right part but how do I also include it if it doesn't exist. I know I have done something very similar before but I cannot remember which project and so I cannot find the code anywhere.
You need to move the filtering logic to the ON clause:
SELECT il.ID AS LocationID, il.NAME AS LocationName,
iq.QUANTITY AS Quantity
FROM INV_LOCATIONS il LEFT JOIN
INV_QUANTITY iq
ON il.ID = iq.LOCATION_ID AND iq.PART_ID = 1;
Related
I have following tables.
Part
id
name
1
Part 1
2
Part 2
3
Part 3
Operation
id
name
part_id
order
1
Op 1
1
10
2
Op 2
1
20
3
Op 3
1
30
4
Op 1
2
10
5
Op 2
2
20
6
Op 1
3
10
Lot
id
part_id
Operation_id
10
1
2
11
2
5
12
3
6
I am selecting the results from Lot table and I want to select a column last_Op which is based on the order value of the operation_id. If value of order for the operation_id is the highest for the respective part_id, return 1 else return 0
SELECT
id,
part_id,
operation_id,
last_Op
FROM Lot
expected result set based on the tables above.
id
part_id
operation_id
last_op
10
1
2
0
11
2
5
1
12
3
6
1
In above example, first row returns last_op = 0 because operation_id = 2 is associated with part_id = 1 and it has the highest order = 30. Since operation_id for this part is not pointing towards the highest order value, 0 is returned.
The other two rows return 1 because operation_id 5 and 6 are associated with part_id 2 and 3 respectively and they are pointing towards the highest 'order' value.
If value of order for the operation_id is the highest for the respective part_id, return 1 else return 0
This sounds like window functions will help:
select l.*,
(case when o.order = o.max_order then 1 else 0 end) as last_op
from lot l left join
(select o.*,
max(o.order) over (partition by o.part_id) as max_order
from operations o
) o
on l.operation_id = o.id;
Note: order is a very poor name for a column because it is a SQL keyword.
I'm attempting to write a query that will list items from Table 2 in order of how many rows reference it in Table 1. The difficulty is that some rows in Table 2 are actually based on another row in Table 2, in which case the row it refers to should be counted instead.
My structure looks like this:
Table 1
itemID templateID
1 1
2 2
3 3
4 4
5 5
Table 2
templateName templateID basedOnTemplateID
Foo 1 null
Bar 2 null
Tree 3 1
Dog 4 2
Bird 5 null
Desired Results
templateName templateID itemCount
Foo 1 2
Bar 2 2
Bird 5 1
Tree 3 0
Dog 4 0
What I have so far:
SELECT TOP (5)
Max(table2.templateName) 'templateName',
Max(table2.templateID) 'templateID',
Count([itemID]) 'itemCount'
FROM table1
LEFT JOIN
table2 on table1.templateid = (
CASE
WHEN table2.basedOnTemplateID is not null
THEN table2.basedOnTemplateID
ELSE table2.templateID
END)
GROUP BY table2.templateid
ORDER BY Count(itemID) DESC
You can left join and aggregate as follows:
select
t2.templateName,
t2.templateID,
count(t1.templateID) itemCount
from table2 t2
left join table1 t1
on t1.templateID = t2.templateID
and t2.basedOnTemplateID is null
group by t2.templateName, t2.templateID
order by itemCount desc, t2.templateID
Is it possible a query with Group By to show null rows?
let's say that my table has [PlaceID] and [Times].
PlaceID I Times
--------I-------
1 I 2
3 I 1
1 I 1
3 I 2
3 I 4
1 I 2
If I make the following SQL, [PlaceID] will not be visible because there is no data.
SELECT PlaceID, Sum(Times) As SumTimes
FROM tblOrder
GROUP BY PlaceID;
PlaceID I SumTimes
--------I-------
1 I 5
3 I 7
Is it possible to force it and have this output
PlaceID I SumTimes
--------I-------
1 I 5
2 I 0
3 I 7
You need a list of places . . . which I would guess is in the places table.
Then:
select p.placeId, nz(sum(times), 0)
from places as p left join
tblOrder as o
on p.placeId = o.placeId
group by p.placeId;
If there are more than three places, you can add where p.placeId in (1, 2, 3).
I have the following tables:
Table I:
etu | nr |
1 2
2 2
2 3
2 1
3 4
3 9
Table A:
etu | rsp | nr
2 8 2
2 7 3
2 3 1
3 2 4
3 6 9
Now what I want to have as a result table is
etu | nr | rsp
2.. 3 7
3.. 9 6
So etu and nr are linked together and if multiple equal etu entries are available only the one with the highest nr is taken and the rsp value is added in the result table. in addition if more etu entries are available in the table I there are .. added to the etu value.
Explain: For the 3 9 6 row: The last row on table I is 3 9 so 3 is the number that is looked for and 9 is the highest number for the 3 rows. So we take that and add the rsp value for that ( 6 ) and we add that to the result table. For the 2 row it is the same 2 3 being the highest 2 row in table I.
I got something like:
select x.etu, x.rsp, y.nr from(
select i.etu etu, max(i.nr) maxnr, a.rsp from i left join a on
i.etu=a.etu and i.nr=a.nr group by etu)t
inner join a x on x.etu=t.etu and x.nr=t.nr inner join y on y.etu=t.etu
and y.nr=t.nr
or
select i.etu, max(i.nr) a.rsp from i left join a on i.etu=a.etu and
i.nr=a.nr grounp by
None even get me close to get the results that I want less add the .. after the etu when having the right result.
The system is DB10.5 Windows.
Thank you for all your help in advance.
Viking
I would use a CTE here like this:
with tmp as (
select i.etu, max(i.nr) as nt, count(*) as cnt
from i
group by i.etu)
select case
when tmp.cnt = 1 then char(a.etu)
else concat(rtrim(char(a.etu)), '..')
end as etu,
a.nr,
a.rsp
from tmp
left outer join a
on a.etu = tmp.etu
and a.nr = tmp.nr
The CTE provides the information necessary to join with a to get the correct response, and append the .. as necessary.
I have 2 tables named user and statistics
user table has 3 columns: id, name and category
statistics table has 3 columns: id, idUser (relational), cal
something like this:
user
Id name category
1 name1 1
2 name2 2
3 name3 3
statistics
Id idUser cal
1 1 1
2 1 1
3 1 1
4 2 1
5 2 1
How can I apply a query that sum the cal column by each category of users and give me something like this:
category totalcal
1 3
2 2
3 0
You want to do a left join to keep all the categories. The rest is just aggregation:
select u.category, coalesce(sum(s.cal), 0) as cal
from users u left join
statistics s
on u.id = s.idUser
group by u.category;
Use LEFT JOIN to get 0 sum for the category=3:
SELECT
user.category
,SUM(statistics.cal) AS totalcal
FROM
user
LEFT JOIN statistics ON statistics.idUser = user.Id
GROUP BY
user.category
Here SUM would return NULL for category=3. To get 0 instead of NULL you can use COALESCE(SUM(statistics.cal), 0).