I would like to achieve the following:
In my SQL Server database I currently have this table (4 rows to show the records).
I would like to extrapolate the M_ID column, which currently only has 4 distinct values to distinct 200 values.
The values in the other columns can be the same or be a random value/data
What is the best way to approach this?
T1
P_M L_U U_D_T_P M_ID
4/9/2020 9:00:00 PM 4/9/2020 9:00:00 PM 2 105
5/9/2020 9:00:00 PM 4/9/2020 9:00:00 PM 2 111
7/9/2020 9:00:00 PM 4/9/2020 9:00:00 PM 2 112
5/9/2020 9:00:00 PM 4/9/2020 9:00:00 PM 2 113
You can use generate a random value, using:
rand(checksum(newid()))
This can then be incorporated in your logic. In an update:
update t
set m_id = floor(rand(checksum(newid())) * 200) + 1;
Related
I have a sql table like this
occ_val time
0 2/1/2022 3:35:08 pm
1 2/1/2022 3:59:08 pm
2 2/1/2022 4:55:08 pm
3 2/1/2022 5:32:08 pm
2 3/1/2022 4:43:08 pm
3 4/1/2022 2:15:08 pm
How to I sort by each hour to get this:
time occ_val
2:00:00 pm 3
3:00:00 pm 1
4:00:00 pm 4
5:00:00 pm 3
Your help is very much appreciated :D
Here is a MySQL solution:
select DATE_FORMAT(min(time), '%h:00'),sum(occ_val) from tbl group by hour(time)
See https://www.db-fiddle.com/f/czudbp5zug6HxX4TFV26GT/0
SELECT * from YourTableName
ORDER BY (timeCol - FLOOR(CAST(timeCol AS float)) ASC
What would be the best way to get datetime ranges between records in SQL Server? I think it would be easiest to explain with an example.
I have the following data - these records start and end datetime ranges would never overlap:
ID
Start
End
1
1/27/2021 06:00:00
1/27/2021 09:00:00
2
1/27/2021 10:00:00
1/27/2021 14:00:00
3
1/27/2021 21:00:00
1/28/2021 04:00:00
4
1/28/2021 06:00:00
1/28/2021 09:00:00
I need to get the date time range between records. So the resulting SQL query would return the following result set (ID doesn't matter):
ID
Start
End
1
1/27/2021 09:00:00
1/27/2021 10:00:00
2
1/27/2021 14:00:00
1/27/2021 21:00:00
3
1/28/2021 04:00:00
1/28/2021 06:00:00
Thanks for any help in advance.
Use lead():
select t.*
from (select id, end as start, lead(start) over (order by start) as end
from t
) t
where end is not null;
Note: end is a lousy name for a column, given that it is a SQL keyword. I assume it is for illustrative purposes only.
Here is a SQL Fiddle.
I have a timecard table like below. The HourType field represents whether the Employee entered the time ("0"), or whether their supervisor overrides or enters time ("1"). If a supervisor overrides time there is both a 0 record and a 1 record (4/8/2019). If a supervisor enters time the employee did not, then there is only a 1 record (4/12/2019). I need a query to find the total time for a given week. So in the below example the total hours for this week should be 39.5 hours.
RecordId EmployeeId StartDate EndDate StartTime EndTime HourCount HourType
1 100 4/8/2019 4/8/2019 9:00:00 AM 5:00:00 PM 8 0
2 100 4/8/2019 4/8/2019 9:00:00 AM 4:30:00 PM 7.5 1
3 100 4/9/2019 4/9/2019 9:00:00 AM 5:00:00 PM 8 0
4 100 4/10/2019 4/10/2019 9:00:00 AM 5:00:00 PM 8 0
5 100 4/11/2019 4/11/2019 9:00:00 AM 5:00:00 PM 8 0
6 100 4/12/2019 4/12/2019 9:00:00 AM 5:00:00 PM 8 1
Added 2nd data set that would include multiple records per day to account for lunch hours (4/11/2019). Total Hours for this dataset should be 37.5.
RecordId EmployeeId StartDate EndDate StartTime EndTime HourCount HourType
1 100 4/8/2019 4/8/2019 9:00:00 AM 5:00:00 PM 8 0
2 100 4/8/2019 4/8/2019 9:00:00 AM 4:30:00 PM 7.5 1
3 100 4/9/2019 4/9/2019 9:00:00 AM 5:00:00 PM 8 0
4 100 4/10/2019 4/10/2019 9:00:00 AM 5:00:00 PM 8 0
5 100 4/11/2019 4/11/2019 9:00:00 AM 12:00:00 PM 3 0
6 100 4/11/2019 4/11/2019 9:30:00 AM 12:00:00 PM 2.5 1
7 100 4/11/2019 4/11/2019 1:00:00 PM 5:00:00 PM 4 0
8 100 4/12/2019 4/12/2019 9:00:00 AM 5:00:00 PM 8 1
You seem to want:
select employeeId, sum(hourcount)
from (select t.*,
row_number() over (partition by employeeid, startdate, enddate order by hourtype desc) as seqnum
from t
) t
where seqnum = 1;
That is, if multiple records match emplyeeid, startdate, and enddate, then choose the override one.
How to query in oracle SQL for the AND condition from the below table.
I want to query like where Start_date =something AND End_date=something
ID Start_date End_date STATUS USER
21 4/16/2010 11:00:00 PM 4/16/2010 11:59:00 PM PENDING TOM
22 4/18/2010 11:00:00 AM 4/18/2010 11:59:00 PM COMPLETED JACK
23 4/20/2010 11:00:00 PM 4/20/2010 11:59:00 PM PENDING JEFF
24 5/16/2010 11:00:00 PM 5/16/2010 11:59:00 PM STARTED MIKE
where start_date = '4/16/2010 11:00:00 PM' and end_date = '4/16/2010 11:59:00 PM'
I have a table which looks like you can see below:
Id Date ScheduledTimeFrom ScheduledTimeTo ActualTimeFrom ActualTimeTo
1 2013-01-01 1899-12-30 07:00:00 1899-12-30 18:00:00 1899-12-30 07:23:00 1899-12-30 17:15:00
I need to calculate per half hour how many records exists, the output should be like:
Time Actual Count:
7:00 4
7:30 4
8:00 4
8:30 4
9:00 4
9:30 5
10:00 5
10:30 6
11:00 7
11:30 8
12:00 8
12:30 8
13:00 8
13:30 8
14:00 8
14:30 8
15:00 7
15:30 7
16:00 7
16:30 6
17:00 5
17:30 4
18:00 4
I already tried to make a helper table which should hold the times per halfhour. I have joined this helpertable with the table that contains the data and after that I tried to use a group by function but it was not working.
My query was like:
Create table period (timefrom datetime, timeto datetime)
insert into period
select '1899-12-30 07:00:00.000', '1899-12-30 07:30:00.000'
Union all
select '1899-12-30 07:30:00.000', '1899-12-30 08:00:00.000'
select *
from period p left join table1 t on t.ActualTimeFrom < p.timeto and t.ActualTimeTo >=p.timefrom
Grouping this give me no desired result....
Anyone an idea how to come to the result?
P.s. I am using sql server 2005.
After snooping around and testing it on my side, looks like this date function could be the answer:
DATEADD(mi,DATEDIFF(mi,0,YOUR_DATE_COLUMN)/30*30,0)