This question already has answers here:
SQL How to Update SUM of column over group in same table
(3 answers)
Closed 2 years ago.
I have a table in SQL which I want to update
NAME Emp_ID Points TotalPoints
ABC 1 50 0
ABC 1 40 0
XYZ 2 20 0
LMN 3 30 0
LMN 3 50 0
XYZ 2 10 0
LMN 3 5 0
Please help me to update the same table as shown below by summing up the points
NAME Emp_ID Points TotalPoints
ABC 1 50 90
ABC 1 40 90
XYZ 2 20 30
LMN 3 30 85
LMN 3 50 85
XYZ 2 10 30
LMN 3 5 85
I only tried the below SQL on Oracle 18c database, but I believe it is fairly standard SQL and so should work with all the major DBMS
update EMPS E1
set E1.TOTAL_POINTS = (select sum(E2.POINTS)
from EMPS E2
where E2.EMP_ID = E1.EMP_ID)
Try the following, here is the DEMO. This code work for MySQL 8.0, SQL Server and PostgreSQL.
select
name,
emp_id,
points,
sum(points) over (partition by emp_id) as total_points
from yourTable
order by
name
Related
I wish to use some sort of SQL array to subtract values from a certain row (QTYOnHand) that decreases that row value every time and throws it into a rolling calculation for the other rows. I've been thinking of some sort of Self Join/Temp Table solution, but not sure how to formulate. Also, All the results will be partitioned by the ItemID below. Help would be appreciated.
Here's some data, If I do a simple row by row subtraction I will get this: 17-3 = 14, 17-5 = 12 and so on.
(Item_ID) (ItemQty) (QTYOnHand) (QtyOnHand - ItemQty)
123 3 17 14
123 5 17 12
123 4 17 13
456 7 12 5
456 8 12 4
456 2 12 10
456 3 12 9
789 2 6 4
789 2 6 4
789 2 6 4
These are the results that I want, where I subtract every next value from the new QTYOnHand-ItemQty column value. Looks like 17-3 then 14 -5 then 9 -4 for Item_ID (123):
(Item_ID) (ItemQty) (QTYOnHand) (QtyOnHand - ItemQty)
123 3 17 14
123 5 17 9
123 4 17 5
456 7 12 5
456 8 12 -3
456 2 12 -5
456 3 12 -8
789 2 6 4
789 2 6 2
789 2 6 0
try the following:
;with cte as
(
select *, ROW_NUMBER() over (partition by Item_ID order by Item_ID) rn
from YourTable
)
, cte2 as
(
select Item_ID, ItemQty, QTYOnHand, Case when rn = 1 then QTYOnHand else 0 end - ItemQty as calc, rn
from cte
)
select Item_ID, ItemQty, QTYOnHand, sum(calc) over (partition by Item_ID order by rn) as [QtyOnHand - ItemQty]
from cte2 t1
Please find the db<>fiddle here.
Consider the table Property.
KeyIdNum|Property|IdNum
1 12 1234
1 12 1234
1 44 1234
1 12 1234
1 56 1234
2 12 4567
3 12 6789
3 56 6789
3 12 6789
4 44 3434
5 12 4444
6 44 9999
6 44 9999
It contains property num associated with each id num.But it contains duplicates.
I applied distinct to avoid duplicates.
select distinct KeyIdNum,Property,IdNum from Property.
So i got the result as :
KeyIdNum |Property |IdNum
1 12 1234
1 44 1234
1 56 1234
2 12 4567
3 12 6789
3 56 6789
4 44 3434
5 12 4444
6 44 9999
But now I want to `select( after applying distinct) ,the KeyIdNum (or IdNum) which are coming more than one time in the distinct result set shown above.
Please help me on this.I am not able to find a way to get the count of a column in the distinct result set using a single query.
Below query will result of KeyidNum , its number of row count.
select KeyIdNum,count(KeyIdNum)
From (
select distinct KeyIdNum,Property,IdNum from Property )
group by KeyIdNum
select KeyIdNum,count(KeyIdNum) as count
From (
select distinct KeyIdNum,Property,IdNum from Table19 )A
group by KeyIdNum
output
KeyIdNum count
1 3
2 1
3 2
4 1
5 1
6 1
This answer uses t-sql:
SELECT x
FROM ( SELECT * ,
rn = rownumber() OVER ( PARTITION BY keyidnum, idnum
ORDER BY keyidnum, idnum )
FROM tblProperty
) x
WHERE rn > 1
This question already has answers here:
How to delete duplicate entries?
(16 answers)
Closed 6 years ago.
I have a table as :
id product id merchant id price upc
1 124 2 2000000 1234XDE
2 124 2 200000 1234XDE
3 124 2 200000 1234XDE
4 124 2 200000 1234XDE
5 124 2 200000 ASDER36
6 134 1 300 ASERT56
7 134 2 300 ASERT56
I want to delete all the multiple entries from the table.
Delete from
table where id not in (Select min(id) from table group by(merchant id))
but no success. I want resulting table as:
id product id merchant id price upc
1 124 2 2000000 1234XDE
5 124 2 2000000 ASDER36
6 134 1 300 ASERT56
7 134 2 300 ASERT56
Can someone help me in writing a query for this.
This should do it:
delete from flash
where id not in (select min(id)
from flash
group by product_id, merchant_id, upc);
SQLFiddle example: http://sqlfiddle.com/#!15/9edef/1
I have table with productcode and mrp like
Pcode MRP
1 30
2 30
2 35
3 100
4 150
4 150
5 45
6 120
6 122
6 125
I want to find which productcodes have more than two mrp.
Thanks in advance.
If you get the count and use the having clause, you should get what you are looking for.
select pcode, count(pcode)
From tab
group by pcode
having count(pcode) > 1
I have a table with an ID and multiple informative columns. Sometimes however, I can have multiple data for an ID, so I added a column called "Sequence". Here is a shortened example:
ID Sequence Name Tel Date Amount
124 1 Bob 873-4356 2001-02-03 10
124 2 Bob 873-4356 2002-03-12 7
124 3 Bob 873-4351 2006-07-08 24
125 1 John 983-4568 2007-02-01 3
125 2 John 983-4568 2008-02-08 13
126 1 Eric 345-9845 2010-01-01 18
So, I would like to obtain only these lines:
124 3 Bob 873-4351 2006-07-08 24
125 2 John 983-4568 2008-02-08 13
126 1 Eric 345-9845 2010-01-01 18
Anyone could give me a hand on how I could build a SQL query to do this ?
Thanks !
You can calculate the maximum sequence using group by. Then you can use join to get only the maximum in the original data.
Assuming your table is called t:
select t.*
from t join
(select id, MAX(sequence) as maxs
from t
group by id
) tmax
on t.id = tmax.id and
t.sequence = tmax.maxs