bs4 img crawler donload img pile in python - beautifulsoup

Question

import requests
import urllib
from bs4 import BeautifulSoup
headers = {
"User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.163 Safari/537.36"
}
for idx in range(1, 17):
url = "https://www.coupang.com/np/categories/311357?page=" + str(idx)
print(url)
result = requests.get(url, headers=headers)
soup_obj = BeautifulSoup(result.content, "html.parser")
div = soup_obj.findAll("div", {"class": "name"})
lis = soup_obj.find("ul", {"id": "productList"}).findAll("li")
for li in lis:
name = li.find("div", {"class": "name"})
img = li.find("dt", {"class": "image"}).find("img", {"src": ""})
print("name: " + name.text.strip())
urllib.request.urlretrieve(img, "./imagepile")
// urllib.request.urlretrieve(img, "./imagepile") how to fix this code line? ple

Answer 1

import requests
from bs4 import BeautifulSoup
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:75.0) Gecko/20100101 Firefox/75.0'}
def main(url):
with requests.Session() as req:
for item in range(1, 18):
print(f"Extracting Page# {item}")
r = req.get(url.format(item), headers=headers)
soup = BeautifulSoup(r.content, 'html.parser')
for item in soup.select("dt.image"):
print(item.img['alt'], f"https:{item.img['src']}")
main("https://www.coupang.com/np/categories/311357?page={}")
Download Version:
import requests
from bs4 import BeautifulSoup
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:75.0) Gecko/20100101 Firefox/75.0'}
def main(url):
with requests.Session() as req:
for item in range(1, 3):
print(f"Extracting Page# {item}")
r = req.get(url.format(item), headers=headers)
soup = BeautifulSoup(r.content, 'html.parser')
target = [[item.img['alt'], f'https:{item.img["src"]}']
for item in soup.select("dt.image")]
for el in target:
print(f"Saving {el[0]}.jpg")
r = req.get(el[1])
with open(f"{el[0]}.jpg", 'wb') as f:
f.write(r.content)
main("https://www.coupang.com/np/categories/311357?page={}")