How do you set the color of a disabled button using a react-native-paper theme? - react-native

Question

The react-native-paper docs suggest you can set the color of a disabled button using a theme, but this code does not work:
export const buttonTheme = {
colors: {
primary: COL_BASE_YELLOW,
disabled: COL_DARK_HIGHLIGHT,
},
}
<Button
loading={submittedPhoneNumber ? true : false}
mode="contained"
onPress={() => handleSubmitPhoneNumber(phoneNumber)}
theme={buttonTheme}
disabled={phoneNumber.length < 5 ? true : false}>
Continue
</Button>
The primary color works however.
How do I change the color of the button when it is disabled?

Answer 1

Don't use disabled props, it will always make your button grey, if you want to use your desired colour for disabled mode, do it like this :
<Button
loading={submittedPhoneNumber ? true : false}
mode="contained"
onPress={phoneNumber.length < 5 ? () => {} : () => handleSubmitPhoneNumber(phoneNumber)}
color={phoneNumber.length < 5 ? 'darkerColor' : 'fadedColor'}>
Continue
</Button>

Answer 2

From this Github issue:
The text if the contained button depends on the background color of
the button, which is automatically determined based on of the
background color is light it dark. Wherever theme is dark or not
doesn't affect it.
This is the desired behavior. We don't want to show white text on a
light background because you have a dark theme, otherwise the text
won't have enough contrast and will be illegible.
Changing the theme to dark changes the disabled button color, as I tested. Apart from this, I don't think its possible if you use react-native-paper. The author has decided to automatically set the color & background color of the button based on something, but his language is unclear.
However, you can give a labelStyle prop the button directly, and you could have a conditional in that style.
<Button labelStyle={{ color: phoneNumber.length < 5 ? 'red' : 'green' }}>
or,
[buttonDisabled, setButtonDisabled] = useState(false); // put this outside the render function.
<Button disabled={disabled} labelStyle={{ color: disabled ? 'red' : 'green' }}>

Answer 3

I'm may be late but here's my solution:
<Button
id="save-phonenumber"
color="darkColor">
onClick={doSomething}
disabled={phoneNumber.length < 5 ? true : false}>
<Button/>
In you Css file you can add
Button#save-phonenumber[disabled] {
background: "fadedColor"
}
Benefit of using this approach is that you don't additionally need to disable the clicking effect when the button is disabled.

Answer 4

If you're caring about light and dark themes at the moment, then you can achieve your goal like this -
I would suggest creating your own Button Component on the top of Paper Button.
// extending default Paper Button Component
<PaperButton style={[ props.disabled && { backgroundColor: 'cccccc' } ]}>
{children}
</PaperButton>
// Using component...
<MyButton disabled={disabled}>
Click Me!
</MyButton>