Left Outer Join Without Duplicate Rows - sql

Question

After a lot of searching I could not solve my problem. I have the following tables:
I want to select all records from my 'product' table. but I have a problem. I got multiple rows from 'product' table when I execute the following query:
SELECT dbo.product.id, dbo.product.name, dbo.product_price.value
dbo.product_barcode.barcode
FROM dbo.product LEFT OUTER JOIN
dbo.product_price ON dbo.product.id = dbo.product_price.product_id LEFT OUTER JOIN
dbo.product_barcode ON dbo.product.id = dbo.product_barcode.product_id
My problem was solved with the following query:
SELECT dbo.product.id, dbo.product.name, dbo.product_price.value
dbo.product_barcode.barcode
FROM dbo.product LEFT OUTER JOIN
dbo.product_price ON dbo.product.id = dbo.product_price.product_id LEFT OUTER JOIN
dbo.product_barcode ON dbo.product.id = dbo.product_barcode.product_id
WHERE (dbo.product_price.id IN
(SELECT MIN(id) AS minPriceID
FROM dbo.product_price AS product_price_1
GROUP BY product_id)) AND (dbo.product_barcode.id IN
(SELECT MIN(id) AS Expr1
FROM dbo.product_barcode AS product_barcode_1
GROUP BY product_id))
Now I have just one problem. if the 'product_price' table or 'product_barcode' table does not have any record, No records will be returned. I mean if no similar record is found in 'product_price' or 'product_barcode' table, we will not have any record. while we should have records from the 'product' table with null columns of other tables.
Please help me Thanks.

Answer 1

I think the problem is that the conditions are in the WHERE clause - try moving the conditions from the WHERE clause and into each join:
SELECT dbo.product.id, dbo.product.name, dbo.product_price.value,
dbo.product_barcode.barcode
FROM dbo.product
LEFT OUTER JOIN dbo.product_price ON dbo.product.id = dbo.product_price.product_id
--moved from WHERE clause
AND dbo.product_price.id IN (SELECT MIN(id) AS minPriceID FROM dbo.product_price AS product_price_1 GROUP BY product_id)
LEFT OUTER JOIN dbo.product_barcode ON dbo.product.id = dbo.product_barcode.product_id
--moved from WHERE clause
AND dbo.product_barcode.id IN (SELECT MIN(id) AS Expr1 FROM dbo.product_barcode AS product_barcode_1 GROUP BY product_id)

Answer 2

SELECT dbo.product.id, dbo.product.name, MIN(dbo.product_price.value),MIN( dbo.product_barcode.barcode)
FROM dbo.product
LEFT OUTER JOIN dbo.product_price ON dbo.product.id = dbo.product_price.product_id
LEFT OUTER JOIN dbo.product_barcode ON dbo.product.id = dbo.product_barcode.product_id
GROUP BY dbo.product.id, dbo.product.name
While the above query should achieve your desired results - one entry for product with the minimun product_price (if one exist) and minimum product_barcode (if one exist).
I only assumed you wanted this based on the query you were writing. You need to spend more time thinking about the question you are trying to answer.
Joining will multiply your results if more than one entry per join key is present in one of the tables.

Answer 3

Just remember this diagram:
When you are calling LEFT JOIN and applying filtering like in the second picture from the top left, you will get only items belonging to the A table.
I want to select all records from my 'product' table. but I have a problem. I got multiple rows from 'product' table when I execute the following query:
Can you try calling DISTINCT after SELECT, like this:
SELECT DISTINCT dbo.product.id, dbo.product.name, dbo.product_price.value
dbo.product_barcode.barcode
...