I have two datasets hosted in Snowflake with social media follower counts by day. The main table we will be using going forward (follower_counts) shows follower counts by day:
This table is live as of 4/4/2020 and will be updated daily. Unfortunately, I am unable to get historical data in this format. Instead, I have a table with historical data (follower_gains) that shows net follower gains by day for several accounts:
Ideally - I want to take the follower_count value from the minimum date in the current table (follower_counts) and subtract the sum of gains (organic + paid gains) for each day, until the minimum date of the follower_gains table, to fill in the follower_count historically. In addition, there are several accounts with data in these tables, so it would need to be grouped by account. It should look like this:
I've only gotten as far as unioning these two tables together, but don't even know where to start with looping through these rows:
WITH a AS (
SELECT
account_id,
date,
organizational_entity,
organizational_entity_type,
vanity_name,
localized_name,
localized_website,
organization_type,
total_followers_count,
null AS paid_follower_gain,
null AS organic_follower_gain,
account_name,
last_update
FROM follower_counts
UNION ALL
SELECT
account_id,
date,
organizational_entity,
organizational_entity_type,
vanity_name,
localized_name,
localized_website,
organization_type,
null AS total_followers_count,
organic_follower_gain,
paid_follower_gain,
account_name,
last_update
FROM follower_gains)
SELECT
a.account_id,
a.date,
a.organizational_entity,
a.organizational_entity_type,
a.vanity_name,
a.localized_name,
a.localized_website,
a.organization_type,
a.total_followers_count,
a.organic_follower_gain,
a.paid_follower_gain,
a.account_name,
a.last_update
FROM a
ORDER BY date desc LIMIT 100
UPDATE: Changed union to union all and added not exists to remove duplicates. Made changes per the comments.
NOTE: Please make sure you don't post images of the tables. It's difficult to recreate your scenario to write a correct query. Test this solution and update so that I can make modifications if necessary.
You don't loop through in SQL because its not a procedural language. The operation you define in the query is performed for all the rows in a table.
with cte as (SELECT a.account_id,
a.date,
a.organizational_entity,
a.organizational_entity_type,
a.vanity_name,
a.localized_name,
a.localized_website,
a.organization_type,
(a.follower_count - (b.organic_gain+b.paid_gain)) AS follower_count,
a.account_name,
a.last_update,
b.organic_gain,
b.paid_gain
FROM follower_counts a
JOIN follower_gains b ON a.account_id = b.account_id
AND b.date < (select min(date) from
follower_counts c where a.account.id = c.account_id)
)
SELECT b.account_id,
b.date,
b.organizational_entity,
b.organizational_entity_type,
b.vanity_name,
b.localized_name,
b.localized_website,
b.organization_type,
b.follower_count,
b.account_name,
b.last_update,
b.organic_gain,
b.paid_gain
FROM cte b
UNION ALL
SELECT a.account_id,
a.date,
a.organizational_entity,
a.organizational_entity_type,
a.vanity_name,
a.localized_name,
a.localized_website,
a.organization_type,
a.follower_count,
a.account_name,
a.last_update,
NULL as organic_gain,
NULL as paid_gain
FROM follower_counts a where not exists (select 1 from
follower_gains c where a.account_id = c.account_id AND a.date = c.date)
You could do something like this, instead of using the variable you can just wrap it another bracket and write at end ) AS FollowerGrowth
DECLARE #FollowerGrowth INT =
( SELECT total_followers_count
FROM follower_gains
WHERE AccountID = xx )
-
( SELECT TOP 1 follower_count
FROM follower_counts
WHERE AccountID = xx
ORDER BY date ASCENDING )
Related
I need to update the following query so that it only returns one child record (remittance) per parent (claim).
Table Remit_To_Activate contains exactly one date/timestamp per claim, which is what I wanted.
But when I join the full Remittance table to it, since some claims have multiple remittances with the same date/timestamps, the outermost query returns more than 1 row per claim for those claim IDs.
SELECT * FROM REMITTANCE
WHERE BILLED_AMOUNT>0 AND ACTIVE=0
AND REMITTANCE_UUID IN (
SELECT REMITTANCE_UUID FROM Claims_Group2 G2
INNER JOIN Remit_To_Activate t ON (
(t.ClaimID = G2.CLAIM_ID) AND
(t.DATE_OF_LATEST_REGULAR_REMIT = G2.CREATE_DATETIME)
)
where ACTIVE=0 and BILLED_AMOUNT>0
)
I believe the problem would be resolved if I included REMITTANCE_UUID as a column in Remit_To_Activate. That's the REAL issue. This is how I created the Remit_To_Activate table (trying to get the most recent remittance for a claim):
SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
MAX(claim_id) AS ClaimID,
INTO Latest_Remit_To_Activate
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID
Claims_Group2 contains these fields:
REMITTANCE_UUID,
CLAIM_ID,
BILLED_AMOUNT,
CREATE_DATETIME
Here are the 2 rows that are currently giving me the problem--they're both remitts for the SAME CLAIM, with the SAME TIMESTAMP. I only want one of them in the Remits_To_Activate table, so only ONE remittance will be "activated" per Claim:
enter image description here
You can change your query like this:
SELECT
p.*, latest_remit.DATE_OF_LATEST_REMIT
FROM
Remittance AS p inner join
(SELECT MAX(create_datetime) as DATE_OF_LATEST_REMIT,
claim_id,
FROM Claims_Group2
WHERE BILLED_AMOUNT>0
GROUP BY Claim_ID
ORDER BY Claim_ID) as latest_remit
on latest_remit.claim_id = p.claim_id;
This will give you only one row. Untested (so please run and make changes).
Without having more information on the structure of your database -- especially the structure of Claims_Group2 and REMITTANCE, and the relationship between them, it's not really possible to advise you on how to introduce a remittance UUID into DATE_OF_LATEST_REMIT.
Since you are using SQL Server, however, it is possible to use a window function to introduce a synthetic means to choose among remittances having the same timestamp. For example, it looks like you could approach the problem something like this:
select *
from (
select
r.*,
row_number() over (partition by cg2.claim_id order by cg2.create_datetime desc) as rn
from
remittance r
join claims_group2 cg2
on r.remittance_uuid = cg2.remittance_uuid
where
r.active = 0
and r.billed_amount > 0
and cg2.active = 0
and cg2.billed_amount > 0
) t
where t.rn = 1
Note that that that does not depend on your DATE_OF_LATEST_REMIT table at all, it having been subsumed into the inline view. Note also that this will introduce one extra column into your results, though you could avoid that by enumerating the columns of table remittance in the outer select clause.
It also seems odd to be filtering on two sets of active and billed_amount columns, but that appears to follow from what you were doing in your original queries. In that vein, I urge you to check the results carefully, as lifting the filter conditions on cg2 columns up to the level of the join to remittance yields a result that may return rows that the original query did not (but never more than one per claim_id).
A co-worker offered me this elegant demonstration of a solution. I'd never used "over" or "partition" before. Works great! Thank you John and Gaurasvsa for your input.
if OBJECT_ID('tempdb..#t') is not null
drop table #t
select *, ROW_NUMBER() over (partition by CLAIM_ID order by CLAIM_ID) as ROW_NUM
into #t
from
(
select '2018-08-15 13:07:50.933' as CREATE_DATE, 1 as CLAIM_ID, NEWID() as
REMIT_UUID
union select '2018-08-15 13:07:50.933', 1, NEWID()
union select '2017-12-31 10:00:00.000', 2, NEWID()
) x
select *
from #t
order by CLAIM_ID, ROW_NUM
select CREATE_DATE, MAX(CLAIM_ID), MAX(REMIT_UUID)
from #t
where ROW_NUM = 1
group by CREATE_DATE
I am using Terdata SQL Assistant connected to an enterprise DW. I have written the query below to show an inventory of outstanding items as of a specific point in time. The table referenced loads and stores new records as changes are made to their state by load date (and does not delete historical records). The output of my query is 1 row for the specified date. Can I create a stored procedure or recursive query of some sort to build a history of these summary rows (with 1 new row per day)? I have not used such functions in the past; links to pertinent previously answered questions or suggestions on how I could get on the right track in researching other possible solutions are totally fine if applicable; just trying to bridge this gap in my knowledge.
SELECT
'2017-10-02' as Dt
,COUNT(DISTINCT A.RECORD_NBR) as Pending_Records
,SUM(A.PAY_AMT) AS Total_Pending_Payments
FROM DB.RECORD_HISTORY A
INNER JOIN
(SELECT MAX(LOAD_DT) AS LOAD_DT
,RECORD_NBR
FROM DB.RECORD_HISTORY
WHERE LOAD_DT <= '2017-10-02'
GROUP BY RECORD_NBR
) B
ON A.RECORD_NBR = B.RECORD_NBR
AND A.LOAD_DT = B.LOAD_DT
WHERE
A.RECORD_ORDER =1 AND Final_DT Is Null
GROUP BY Dt
ORDER BY 1 desc
Here is my interpretation of your query:
For the most recent load_dt (up until 2017-10-02) for record_order #1,
return
1) the number of different pending records
2) the total amount of pending payments
Is this correct? If you're looking for this info, but one row for each "Load_Dt", you just need to remove that INNER JOIN:
SELECT
load_Dt,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE record_order = 1
AND final_Dt IS NULL
GROUP BY load_Dt
ORDER BY 1 DESC
If you want to get the summary info per record_order, just add record_order as a grouping column:
SELECT
load_Dt,
record_order,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE final_Dt IS NULL
GROUP BY load_Dt, record_order
ORDER BY 1,2 DESC
If you want to get one row per day (if there are calendar days with no corresponding "load_dt" days), then you can SELECT from the sys_calendar.calendar view and LEFT JOIN the query above on the "load_dt" field:
SELECT cal.calendar_date, src.Pending_Records, src.Total_Pending_Payments
FROM sys_calendar.calendar cal
LEFT JOIN (
SELECT
load_Dt,
COUNT(DISTINCT record_nbr) AS Pending_Records,
SUM(pay_amt) AS Total_Pending_Payments
FROM DB.record_history
WHERE record_order = 1
AND final_Dt IS NULL
GROUP BY load_Dt
) src ON cal.calendar_date = src.load_Dt
WHERE cal.calendar_date BETWEEN <start_date> AND <end_date>
ORDER BY 1 DESC
I don't have access to a TD system, so you may get syntax errors. Let me know if that works or you're looking for something else.
I am trying to get the TOP 20 DISTINCT address records from a query with a UNION...
The issue is that I want to order by date first - so the customer sees the most recent - but each date makes the row unique and leaves me with a ton of replica addresses (please see below).
SELECT
CB.CustomerGuid, CB.DisplayAddress, CB.LocatorId
FROM
(SELECT
B.CustomerGuid, CAST(B.PickupDateTime AS DATE) AS TravelDate,
B.PickupDisplayAddress AS DisplayAddress, B.PickupAddressId AS LocatorId
FROM
Bookings B
WHERE
CustomerGuid = '463a20f2-a874-4964-865d-70d71065a69b'
UNION
SELECT
B2.CustomerGuid, CAST(B2.PickupDateTime AS DATE) AS TravelDate,
B2.DestinationDisplayAddress AS DisplayAddress, B2.PickupAddressId AS LocatorId
FROM
Bookings B2
WHERE
CustomerGuid = '463a20f2-a874-4964-865d-70d71065a69b'
ORDER BY
TravelDate DESC) AS CB
I felt the approach would be make the union query a subquery and query that (without the date) as DISTINCT but I have since learned that the order of rows in the result set is ultimately controlled by the ORDER BY clause in the outer SELECT. This therefore gives me the error:
The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP, OFFSET or FOR XML is also specified.
How do I get around this please?
Something like this I think would work, assuming it doesn't matter which traveldate you sort by:
SELECT TOP 20 CB.CustomerGuid, CB.DisplayAddress, CB.LocatorId FROM
(SELECT B.CustomerGuid, CAST(B.PickupDateTime AS DATE) AS TravelDate,
B.PickupDisplayAddress AS DisplayAddress, B.PickupAddressId AS LocatorId
FROM Bookings B
WHERE CustomerGuid = '463a20f2-a874-4964-865d-70d71065a69b'
UNION
SELECT B2.CustomerGuid, CAST(B2.PickupDateTime AS DATE) AS TravelDate,
B2.DestinationDisplayAddress AS DisplayAddress, B2.PickupAddressId AS LocatorId
FROM Bookings B2
WHERE CustomerGuid = '463a20f2-a874-4964-865d-70d71065a69b'
) AS CB
GROUP BY CB.CustomerGuid, CB.DisplayAddress, CB.LocatorId
ORDER BY MAX(TravelDate) DESC
Hi guys, I am stuck with a stubborn problem which I am unable to solve. Am trying to compile a report wherein all the dates coming from different tables would need to come into a single date field in the report. Ofcourse, the max or the most recent date from all these date columns needs to be added to the single date column for the report. I have multiple users of multiple branches/courses for whom the report would be generated.
There are multiple blogs and the latest date w.r.t to the blogtitle needs to be grouped, i.e. max(date_value) from the six date columns should give the greatest or latest date for that blogtitle.
Expected Result:
select u.batch_uid as ext_person_key, u.user_id, cm.batch_uid as ext_crs_key, cm.crs_id, ir.role_id as
insti_role, (CASE when b.JOURNAL_IND = 'N' then
'BLOG' else 'JOURNAL' end) as item_type, gm.title as item_name, gm.disp_title as ITEM_DISP_NAME, be.blog_pk1 as be_blogPk1, bc.blog_entry_pk1 as bc_blog_entry_pk1,bc.pk1,
b.ENTRY_mod_DATE as b_ENTRY_mod_DATE ,b.CMT_mod_DATE as BlogCmtModDate, be.CMT_mod_DATE as be_cmnt_mod_Date,
b.UPDATE_DATE as BlogUpDate, be.UPDATE_DATE as be_UPDATE_DATE,
bc.creation_date as bc_creation_date,
be.CREATOR_USER_ID as be_CREATOR_USER_ID , bc.creator_user_id as bc_creator_user_id,
b.TITLE as BlogTitle, be.TITLE as be_TITLE,
be.DESCRIPTION as be_DESCRIPTION, bc.DESCRIPTION as bc_DESCRIPTION
FROM users u
INNER JOIN insti_roles ir on u.insti_roles_pk1 = ir.pk1
INNER JOIN crs_users cu ON u.pk1 = cu.users_pk1
INNER JOIN crs_mast cm on cu.crsmast_pk1 = cm.pk1
INNER JOIN blogs b on b.crsmast_pk1 = cm.pk1
INNER JOIN blog_entry be on b.pk1=be.blog_pk1 AND be.creator_user_id = cu.pk1
LEFT JOIN blog_CMT bc on be.pk1=bc.blog_entry_pk1 and bc.CREATOR_USER_ID=cu.pk1
JOIN gradeledger_mast gm ON gm.crsmast_pk1 = cm.pk1 and b.grade_handler = gm.linkId
WHERE cu.ROLE='S' AND BE.STATUS='2' AND B.ALLOW_GRADING='Y' AND u.row_status='0'
AND u.available_ind ='Y' and cm.row_status='0' and and u.batch_uid='userA_157'
I am getting a resultset for the above query with multiple date columns which I want > > to input into a single columnn. The dates have to be the most recent, i.e. max of the dates in the date columns.
I have successfully done the Unpivot by using a view to store the above
resultset and put all the dates in one column. However, I do not
want to use a view or a table to store the resultset and then do
Unipivot simply because I cannot keep creating views for every user
one would query for.
The max(date_value) from the date columns need to be put in one single column. They are as follows:
* 1) b.entry_mod_date, 2) b.cmt_mod_date ,3) be.cmt_mod_date , 4) b.update_Date ,5) be.update_date, 6) bc.creation_date *
Apologies that I could not provide the desc of all the tables and the
fields being used.
Any help to get the above mentioned max of the dates from these
multiple date columns into a single column without using a view or a
table would be greatly appreciated.*
It is not clear what results you want, but the easiest solution is to use greatest().
with t as (
YOURQUERYHERE
)
select t.*,
greatest(entry_mod_date, cmt_mod_date, cmt_mod_date, update_Date,
update_date, bc.creation_date
) as greatestdate
from t;
select <columns>,
case
when greatest (b_ENTRY_mod_DATE) >= greatest (BlogCmtModDate) and greatest(b_ENTRY_mod_DATE) >= greatest(BlogUpDate)
then greatest( b_ENTRY_mod_DATE )
--<same implementation to compare each time BlogCmtModDate and BlogUpDate separately to get the greatest then 'date'>
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
case
when greatest (be_cmnt_mod_Date) >= greatest (be_UPDATE_DATE)
then greatest( be_cmnt_mod_Date )
when greatest (be_UPDATE_DATE) >= greatest (be_cmnt_mod_Date)
then greatest( be_UPDATE_DATE )
,<columns>
FROM table
<rest of the query>
UNION ALL
Select <columns>,
GREATEST(bc_creation_date)
,<columns>
FROM table
<rest of the query>
I have those two tables
1-Add to queue table
TransID , ADD date
10 , 10/10/2012
11 , 14/10/2012
11 , 18/11/2012
11 , 25/12/2012
12 , 1/1/2013
2-Removed from queue table
TransID , Removed Date
10 , 15/1/2013
11 , 12/12/2012
11 , 13/1/2013
11 , 20/1/2013
The TansID is the key between the two tables , and I can't modify those tables, what I want is to query the amount of time each transaction spent in the queue
It's easy when there is one item in each table , but when the item get queued more than once how do I calculate that?
Assuming the order TransIDs are entered into the Add table is the same order they are removed, you can use the following:
WITH OrderedAdds AS
( SELECT TransID,
AddDate,
[RowNumber] = ROW_NUMBER() OVER(PARTITION BY TransID ORDER BY AddDate)
FROM AddTable
), OrderedRemoves AS
( SELECT TransID,
RemovedDate,
[RowNumber] = ROW_NUMBER() OVER(PARTITION BY TransID ORDER BY RemovedDate)
FROM RemoveTable
)
SELECT OrderedAdds.TransID,
OrderedAdds.AddDate,
OrderedRemoves.RemovedDate,
[DaysInQueue] = DATEDIFF(DAY, OrderedAdds.AddDate, ISNULL(OrderedRemoves.RemovedDate, CURRENT_TIMESTAMP))
FROM OrderedAdds
LEFT JOIN OrderedRemoves
ON OrderedAdds.TransID = OrderedRemoves.TransID
AND OrderedAdds.RowNumber = OrderedRemoves.RowNumber;
The key part is that each record gets a rownumber based on the transaction id and the date it was entered, you can then join on both rownumber and transID to stop any cross joining.
Example on SQL Fiddle
DISCLAIMER: There is probably problem with this, but i hope to send you in one possible direction. Make sure to expect problems.
You can try in the following direction (which might work in some way depending on your system, version, etc) :
SELECT transId, (sum(add_date_sum) - sum(remove_date_sum)) / (1000*60*60*24)
FROM
(
SELECT transId, (SUM(UNIX_TIMESTAMP(add_date)) as add_date_sum, 0 as remove_date_sum
FROM add_to_queue
GROUP BY transId
UNION ALL
SELECT transId, 0 as add_date_sum, (SUM(UNIX_TIMESTAMP(remove_date)) as remove_date_sum
FROM remove_from_queue
GROUP BY transId
)
GROUP BY transId;
A bit of explanation: as far as I know, you cannot sum dates, but you can convert them to some sort of timestamps. Check if UNIX_TIMESTAMPS works for you, or figure out something else. Then you can sum in each table, create union by conveniently leaving the other one as zeto and then subtracting the union query.
As for that devision in the end of first SELECT, UNIT_TIMESTAMP throws out miliseconds, you devide to get days - or whatever it is that you want.
This all said - I would probably solve this using a stored procedure or some client script. SQL is not a weapon for every battle. Making two separate queries can be much simpler.
Answer 2: after your comments. (As a side note, some of your dates 15/1/2013,13/1/2013 do not represent proper date formats )
select transId, sum(numberOfDays) totalQueueTime
from (
select a.transId,
datediff(day,a.addDate,isnull(r.removeDate,a.addDate)) numberOfDays
from AddTable a left join RemoveTable r on a.transId = r.transId
order by a.transId, a.addDate, r.removeDate
) X
group by transId
Answer 1: before your comments
Assuming that there won't be a new record added unless it is being removed. Also note following query will bring numberOfDays as zero for unremoved records;
select a.transId, a.addDate, r.removeDate,
datediff(day,a.addDate,isnull(r.removeDate,a.addDate)) numberOfDays
from AddTable a left join RemoveTable r on a.transId = r.transId
order by a.transId, a.addDate, r.removeDate