If I enter a phone number as (238)654-2332 into a phone field, it should be displayed in 0123456789 format and automatically remove the braces, unneeded spaces and special characters.
You can see on the below screenshot that there is a phone number with braces, but my requirement is to automatically remove braces and display the phone in 0123456789 format:
Could you please advise me on the best approach for my requirements?
Configuration options would be Workflow, Flow or Process Builder (check help resources or maybe some self-paced training at https://trailhead.salesforce.com/en/home)
Workflows don't do regular expressions for search-replace but they do have a SUBSTITUTE function so maybe something like this would be a good start: SUBSTITUTE(SUBSTITUTE(SUBSTITUTE(Phone, '(', ''), ')', ''), '-', '').
Or with a bit of code (Apex trigger that'd run "before insert, before update") you could fairly easily strip all non-digit characters. Again - if you've never written SF code before you might have to attack some training first.
String x = '(238)654-2332';
String cleaned = x.replaceAll('[^0-9]', '');
System.debug(cleaned); // 2386542332
Related
I've looked at lots of examples for TRIM and REPLACE on the internet and for some reason I keep getting errors when I try.
I need to strip suffixes from my Netsuite item record names in a saved item search. There are three possible suffixes: -T, -D, -S. So I need to turn 24335-D into 24335, and 24335-S into 24335, and 24335-T into 24335.
Here's what I've tried and the errors I get:
Can you help me please? Note: I can't assume a specific character length of the starting string.
Use case: We already have a field on item records called Nickname with the suffixes stripped. But I've ran into cases where Nickname is incorrect compared to Name. Ex: Name is 24335-D but Nickname is 24331-D. I'm trying to build a saved search alert that tells me any time the Nickname does not equal suffix-stripped Name.
PS: is there anywhere I can pay for quick a la carte Netsuite saved search questions like this? I feel bad relying on free technical internet advice but I greatly appreciate any help you can give me!
You are including too much SQL - a formulae is like a single result field expression not a full statement so no FROM or AS. There is another place to set the result column/field name. One option here is Regex_replace().
REGEXP_REPLACE({name},'\-[TDS]$', '')
Regex meaning:
\- : a literal -
[TDS] : one of T D or S
$ : end of line/string
To compare fields a Formulae (Numeric) using a CASE statement can be useful as it makes it easy to compare the result to a number in a filter. A simple equal to 1 for example.
CASE WHEN {custitem_nickname} <> REGEXP_REPLACE({name},'\-[TDS]$', '') then 1 else 0 end
You are getting an error because TRIM can trim only one character : see oracle doc
https://docs.oracle.com/javadb/10.8.3.0/ref/rreftrimfunc.html (last example).
So try using something like this
TRIM(TRAILING '-' FROM TRIM(TRAILING 'D' FROM {entityid}))
And always keep in mind that saved searches are running as Oracle SQL queries so Oracle SQL documentation can help you understand how to use the available functions.
The IBM i implementation of regex uses apostrophes (instead of e.g. slashes) to delimit a regex string, i.e.:
... where REGEXP_SUBSTR(MYFIELD,'myregex_expression')
If I try to use an apostrophe inside a [group] within the expression, it always errors - presumably thinking I am giving a closing quote. I have tried:
- escaping it: \'
- doubling it: '' (and tripling)
No joy. I cannot find anything relevant in the IBM SQL manual or by google search.
I really need this to, for instance, allow names like O'Leary.
Thanks to Wiktor Stribizew for the answer in his comment.
There are a couple of "gotchas" for anyone who might land on this question with the same problem. The first is that you have to give the (presumably Unicode) hex value rather than the EBCDIC value that you would use, e.g. in ordinary interactive SQL on the IBM i. So in this case it really is \x27 and not \x7D for an apostrophe. Presumably this is because the REGEXP_ ... functions are working through Unicode even for EBCDIC data.
The second thing is that it would seem that the hex value cannot be the last one in the set. So this works:
^[A-Z0-9_\+\x27-]+ ... etc.
But this doesn't
^[A-Z0-9_\+-\x27]+ ... etc.
I don't know how to highlight text within a code sample, so I draw your attention to the fact that the hyphen is last in the first sample and second-to-last in the second sample.
If anyone knows why it has to not be last, I'd be interested to know. [edit: see Wiktor's answer for the reason]
btw, using double quotes as the string delimiter with an apostrophe in the set didn't work in this context.
A single quote can be defined with the \x27 notation:
^[A-Z0-9_+\x27-]+
^^^^
Note that when you use a hyphen in the character class/bracket expression, when used in between some chars it forms a range between those symbols. When you used ^[A-Z0-9_\+-\x27]+ you defined a range between + and ', which is an invalid range as the + comes after ' in the Unicode table.
I'm trying to parse an XML file where the users (in their infinite wisdom) type a key value into a free-form field, <Description>. The values are normally typed in with returns (BR's?) between them. For instance:
<Description>
% Increase: 27%
Completion Date: 10-Aug-2015
</Description>
I need to look for an extract the date following the string "Completion Date:" Looking around here on SO I found something similar and adapted it to:
compdate = deal.SelectSingleNode("./Terms/Description[substring-before(substring-after(.,'Completion Date:'),'/')]")
The problem is that in the original question there was a trailing character that could be used to delimit the text, a /. In my case, there might be a BR of some sort, or it might be the last (as in this case) or only item on the line and thus there's no delimiter.
So... suggestions on how to extract the date? I can do it on the VB side, but I'd like to remain in the XPath world for code clarity - unless of course the resulting XPath is unreadable.
If XPath 2.0 solution is acceptable, try
./Terms/Description/tokenize(substring-after(.,'Completion Date: '), '\n')[1]
If not and date format is always DD-mon-YYYY (e.g. 01-Dec-2018), try
./Terms/Description/substring(substring-after(.,'Completion Date: '), 1, 11)
So I have a field that's basically storing an entire XML file per row, complete with line breaks, and I need to remove some text from close to three hundred rows. The replace() function doesn't find the offending text no matter what I do, and all I can find by searching is a bunchy of people trying to remove the line breaks themselves. I don't see any reason that replace() just wouldn't work, so I must just be formatting it wrong somehow. Help?
Edit: Here's an example of what I mean in broad terms:
<script>...</script><dependencies>...</dependencies><bunch of other stuff></bunch of other stuff><labels><label description="Field2" languagecode="1033" /></labels><events><event name="onchange" application="false" active="true"><script><![field2.DataValue = (some equation);
</script><dependencies /></event></events><a bunch more stuff></a bunch more stuff>
I need to just remove everything between the events tags. So my sql code is this:
replace(fieldname, '<events><event name="onchange" application="false" active="true"><script><![field2.DataValue = (some equation);
</script><dependencies /></event></events>', '')
I've tried it like that, and I've tried it all on one line, and I've tried using char(10) where the line breaks are supposed to be, and nothing.
Nathan's answer was close. Since this question is the first thing that came up from a search I wanted to add a solution for my problem.
select replace(field,CHAR(13)+CHAR(10),' ')
I replaced the line break with a space incase there was no break. It may be that you want to always replace it with nothing in which case '' should be used instead of ' '.
Hope this helps someone else and they don't have to click the second link in the results from the search engine.
Worked for me on SQL2012-
UPDATE YourTable
SET YourCol = REPLACE(YourCol, CHAR(13) + CHAR(10), '')
If your column is an xml typed column, you can use the delete method on the column to remove the events nodes. See http://msdn.microsoft.com/en-us/library/ms190254(v=SQL.90).aspx for more info.
try two simple tests.
try the replace on an xml string that has no double quotes (or single quotes) but does have CRLFs. Does it work? If yes, you need to escape the quote marks.
try the replace on an xml string that has no CRLFs. Does it work? Great. If yes use two nested replace() one for the CRLFs only, then a second outter replace for the string in question.
A lot of people do not remember that line breaks are two characters
(Char 10 \n, and Char 13 \r)
replace both, and you should be good.
SELECT
REPLACE(field , CHR(10)+CHR(13), '' )
FROM Blah..
I need to pad numbers with leading zeros (total 8 digits) for display. I'm using oracle.
select to_char(1011,'00000000') OPE_NO from dual;
select length(to_char(1011,'00000000')) OPE_NO from dual;
Instead of '00001011' I get ' 00001011'.
Why do I get an extra leading blank space? What is the correct number formatting string to accomplish this?
P.S. I realise I can just use trim(), but I want to understand number formatting better.
#Eddie: I already read the documentation. And yet I still don't understand how to get rid of the leading whitespace.
#David: So does that mean there's no way but to use trim()?
Use FM (Fill Mode), e.g.
select to_char(1011,'FM00000000') OPE_NO from dual;
From that same documentation mentioned by EddieAwad:
Negative return values automatically
contain a leading negative sign and
positive values automatically contain
a leading space unless the format
model contains the MI, S, or PR format
element.
EDIT: The right way is to use the FM modifier, as answered by Steve Bosman. Read the section about Format Model Modifiers for more info.