I would like to join two tables into master table (on to many) but I keep getting an error
Incorrect syntax near C.showdepartmentinventory_id
My code:
CREATE VIEW view_transactionshowidea
AS
SELECT
A.showidea_id, A.showideaupdatetype_id, A.showidea_proposedtitle,
A.showidea_fixtitle,
B.showinventorycategory_id, B.showinventorycategory_name,
C.showinventorydepartment_id, C.showinventorydepartment_name,
A.shoidea_duration, A.showidea_segment, A.showidea_PIC,
A.showidea_concept, A.showidea_isdisabled
FROM
transaction_showidea AS A
LEFT OUTER JOIN
view_showideainventory AS B
LEFT OUTER JOIN
view_showideainventorydepartment AS C ON showinventorycategory_id = B.showinventorycategory_id
AND showinventorycategory_name = C.showinventorydepartment_id
What is the problem with my query?
Each JOIN should be followed by its ON clause. The sources of your JOIN keys are not clear, but something like this:
FROM transaction_showidea si LEFT OUTER JOIN
view_showideainventory sii
ON si.showinventorycategory_id = sii.showinventorycategory_id LEFT OUTER JOIN
view_showideainventorydepartment siid
ON sii.showinventorycategory_name = siid.showinventorydepartment_id
Note that this introduces meaninful table aliases -- abbreviations for the table names. And all column references are qualified.
You need to specify "ON" right after your join statement like this:
CREATE VIEW view_transactionshowidea AS
SELECT A.showidea_id, A.showideaupdatetype_id, A.showidea_proposedtitle,
A.showidea_fixtitle, B.showinventorycategory_id, B.showinventorycategory_name,
C.showinventorydepartment_id, C.showinventorydepartment_name,
A.shoidea_duration, A.showidea_segment, A.showidea_PIC, A.showidea_concept,
A.showidea_isdisabled
FROM transaction_showidea AS A
LEFT OUTER JOIN view_showideainventory AS B on showinventorycategory_id = B.showinventorycategory_id
LEFT OUTER JOIN view_showideainventorydepartment AS C ON showinventorycategory_name = C.showinventorydepartment_id
Related
I need to do a query with a left outer join just like below, however Access is showing a warning dialog "JOIN expression not supported".I understand that Access doesn't support INNER JOIN nested inside a LEFT JOIN but as I am a beginner in SQL I don't see any other way to get the same result.
The goal of the query is to get everything that is in the select even when InvoiceItems.Amount is null.
SELECT MainOrder.OrderNumber, OrderComponent.ArticleNumber, SupplierOrderMain.*, InvoiceItems.Amount
FROM InvoiceItems LEFT JOIN
((MainOrder INNER JOIN
OrderComponent
ON MainOrder.OrderNumber = OrderComponent.OrderNumber
) INNER JOIN
SupplierOrderMain
ON OrderComponent.ID = SupplierOrderMain.OrderComponentID
)
ON InvoiceItems.OrderComponent = OrderComponent.ID;
I'm not sure why you would want outer joins in this situation at all (you don't explain why). But just start with the table where you want to keep everything and work from there:
SELECT MainOrder.OrderNumber, OrderComponent.ArticleNumber, SupplierOrderMain.*, InvoiceItems.Amount
FROM ((InvoiceItems LEFT JOIN
OrderComponent
ON InvoiceItems.OrderComponent = OrderComponent.ID
) LEFT JOIN
MainOrder
ON MainOrder.OrderNumber = OrderComponent.OrderNumber
) LEFT JOIN
SupplierOrderMain
ON OrderComponent.ID = SupplierOrderMain.OrderComponentID
Write a query to show ALL building names, their metering company name and meter type for all buildings that do not have postpaid meters.
The image 1 is the result that I should get and image 2 is the results that i am getting:
USE Ultimate_DataBase
GO
SELECT [Bld_Name], [Elec_company_name], [Mtype_Name]
FROM [dbo].[Metering_Company] A
FULL OUTER JOIN [dbo].[Metering_Type] D
ON A.[MType_ID]= D.MType_ID
FULL OUTER JOIN [dbo].[Building_metering] B
ON A.[Elec_ID]= B.[Elec_ID]
FULL OUTER JOIN [dbo].[Building] C
ON C.[Bld_ID]= B.[Bld_ID]
WHERE [Mtype_Name] != 'POSTPAID'
Try moving the WHERE logic to the corresponding ON clause:
SELECT [Bld_Name], [Elec_company_name], [Mtype_Name]
FROM [dbo].[Metering_Company] A
FULL OUTER JOIN [dbo].[Metering_Type] D
ON A.[MType_ID]= D.MType_ID AND
[Mtype_Name] != 'POSTPAID' -- change is here
FULL OUTER JOIN [dbo].[Building_metering] B
ON A.[Elec_ID]= B.[Elec_ID]
FULL OUTER JOIN [dbo].[Building] C
ON C.[Bld_ID]= B.[Bld_ID];
Note: Please add aliases to your select clause. They are not mandatory, assuming no two tables ever have columns by the same name, but just having aliases would have made your question easier to answer.
FULL JOIN isn't seem necessary -- in fact FULL JOIN is almost never needed, and especially not for routine JOINs in a well-structured database.
The structure of the question suggests NOT EXISTS:
SELECT b.*
FROM dbo.Building b
WHERE NOT EXISTS (SELECT 1
FROM dbo.Building_metering bm JOIN
dbo.Metering_Company mc
ON bm.Elec_ID = mc.Elec_ID JOIN
dbo.Metering_Type mt
ON mt.MType_ID = mc.MType_ID
WHERE bm.Bld_ID = b.Bld_ID AND mt.Mtype_Name = 'POSTPAID'
);
You can also express this as a LEFT JOIN and filtering:
SELECT b.*
FROM dbo.Building b LEFT JOIN
dbo.Building_metering bm
ON bm.Bld_ID = b.Bld_ID LEFT JOIN
dbo.Metering_Company mc
ON bm.Elec_ID = mc.Elec_ID LEFT JOIN
dbo.Metering_Type mt
ON mt.MType_ID = mc.MType_ID AND
mt.Mtype_Name = 'POSTPAID'
WHERE mt.MType_ID IS NULL;
This allows you to select columns from any of the tables.
Notes:
FULL JOIN is almost never needed.
Use meaningful table aliases! Arbitrary letters mean nothing. Use table abbreviations.
Escaping column and table names with square braces just makes code harder to write and to read.
USE Ultimate_DataBase
GO
SELECT [Bld_Name], [Elec_company_name], [Mtype_Name]
FROM [dbo].[Metering_Company] A
LEFT JOIN [dbo].[Metering_Type] D
ON A.[MType_ID]= D.MType_ID
LEFT JOIN [dbo].[Building_metering] B
ON A.[Elec_ID]= B.[Elec_ID]
LEFT JOIN [dbo].[Building] C
ON C.[Bld_ID]= B.[Bld_ID]
Use this
My current query show the data from the table called "Buque" and has some references from another tables. The problem is when i execute the query it never shows the result because it consumes too much memory i guess.
The current query i have
select buq.buq_codigo, tbu.tbu_codigo, tbu.tbu_nombre, pai.pai_codigo, pai.pai_nombre,
pue.pto_codigo, pue.pto_nombre, lin.lin_codigo, lin.lin_nombre, tra.tra_codigo,
tra.tra_nombre, buq.buq_nombre, buq.buq_des, buq.num_trb, buq.num_eslora,
buq.max_tons, buq.reg_lloyd, buq.buq_codigo1, buq.codigo_omi,
case buq.buq_estado when 'A' then 'Activo' else 'Inactivo' end as buq_estado
from publico.mae_buque as buq, publico.mae_tipbuque as tbu, publico.mae_pais as pai,
publico.mae_puerto as pue, publico.mae_linea as lin, publico.mae_trafico as tra
where buq.tbu_codigo = tbu.tbu_codigo or
buq.pai_codigo = pai.pai_codigo or
buq.pto_codigo = pue.pto_codigo or
buq.lin_codigo = lin.lin_codigo or
buq.tra_codigo = tra.tra_codigo
I also tried with inner joins but the problem is it returns me the data that meets the conditions of the joins. In other words, if the join has data to compare, returns the name, if not, show the null data.
The query must return me 611 records, with inner joins returns 68 records.
Concerning your desired result, use left outer joins, which fill up any non-existing rows of the right hand side table with null-values;
Concerning the out of memory issue, note that you used or to connect your tables; this actually leads to the fact that almost every record of the involved tables is connected to almost every other record (almost a cross join / cartesian product); This can get very large if you connect 6 tables...
select buq.buq_codigo, tbu.tbu_codigo, tbu.tbu_nombre, pai.pai_codigo, pai.pai_nombre,
pue.pto_codigo, pue.pto_nombre, lin.lin_codigo, lin.lin_nombre, tra.tra_codigo,
tra.tra_nombre, buq.buq_nombre, buq.buq_des, buq.num_trb, buq.num_eslora,
buq.max_tons, buq.reg_lloyd, buq.buq_codigo1, buq.codigo_omi,
case buq.buq_estado when 'A' then 'Activo' else 'Inactivo' end as buq_estado
from publico.mae_buque as buq
left outer join publico.mae_tipbuque as tbu on buq.tbu_codigo = tbu.tbu_codigo
left outer join publico.mae_pais as pai on (buq.pai_codigo = pai.pai_codigo)
left outer join publico.mae_puerto as pue on (buq.pto_codigo = pue.pto_codigo)
left outer join publico.mae_linea as lin on (buq.lin_codigo = lin.lin_codigo)
left outer join publico.mae_trafico as tra on (buq.tra_codigo = tra.tra_codigo)
You have to use left outer join:
select *
from
publico.mae_buque as buq
left outer join publico.mae_tipbuque as tbu on (buq.tbu_codigo = tbu.tbu_codigo)
left outer join publico.mae_pais as pai on (buq.pai_codigo = pai.pai_codigo)
left outer join publico.mae_puerto as pue on (buq.pto_codigo = pue.pto_codigo )
left outer join publico.mae_linea as lin on (buq.lin_codigo = lin.lin_codigo)
left outer join publico.mae_trafico as tra on (buq.tra_codigo = tra.tra_codigo);
I'm trying to pass this query to inner join, but it does not know how?
This is the query I want to use InnerJoin with these values where
SELECT
ticket.id_ticket,
ticket.id_rede,
historico.id_historico,
historico.id_ticket,
centro.id_centro,
eqpto.id_eqpto,
eqpto.nome,
centro.sigla_centro,
interface.id_interface,
interface.id_eqpto,
interface.desig,
tecnologia.descricao,
interface.id_tecnologia,
tecnologia.id_tecnologia,
eqpto.id_centro,
eqpto.id_rede
FROM
app_gpa_ticket.ticket,
app_gpa_ticket.historico,
dados_v3.centro,
dados_v3.eqpto,
dados_v3.interface,
dados_v3.tecnologia
WHERE
ticket.id_ticket = historico.id_ticket AND
centro.id_centro = eqpto.id_centro AND
eqpto.id_eqpto = interface.id_eqpto AND
eqpto.id_rede = ticket.id_rede AND
tecnologia.id_tecnologia = interface.id_tecnologia;
Thank you!
I think you are trying to go to the standard (explicit) syntax. What you need to do is take what would be your JOIN operators in the WHERE clause and move them near the table itself. What you need to know is what tables on the left (Before the INNER JOIN operator you are joining to the right (After the INNER JOIN operator)
SELECT
ticket.id_ticket,
ticket.id_rede,
historico.id_historico,
historico.id_ticket,
centro.id_centro,
eqpto.id_eqpto,
eqpto.nome,
centro.sigla_centro,
interface.id_interface,
interface.id_eqpto,
interface.desig,
tecnologia.descricao,
interface.id_tecnologia,
tecnologia.id_tecnologia,
eqpto.id_centro,
eqpto.id_rede
FROM app_gpa_ticket.ticket
INNER JOIN app_gpa_ticket.historico ON ticket.id_ticket = historico.id_ticket
INNER JOIN dados_v3.eqpto ON eqpto.id_rede = ticket.id_rede
INNER JOIN dados_v3.interface ON eqpto.id_eqpto = interface.id_eqpto
INNER JOIN dados_v3.centro ON centro.id_centro = eqpto.id_centro
INNER JOIN dados_v3.tecnologia ON tecnologia.id_tecnologia = interface.id_tecnologia
I can't understand the usage of the using word. Can you explain me?
SELECT 1
FROM CONF_RAGGR_OPZTAR ropt
JOIN TAR_OPZIONI_TARIFFARIE OPT using (OPT_OPZIONE_TARIFFARIA_ID)
JOIN CONF_RAGGRUPPAMENTI_FORN rgf using (RGF_RAGGRUPPAMENTO_FORN_ID)
JOIN CONF_FORNITURE_REL_RAGG forg using (RGF_RAGGRUPPAMENTO_FORN_ID)
JOIN CONF_FORNITURE forn using (FORN_FORNITURA_ID)
LEFT JOIN (
select *
from CONF_ELEMENTI_FATTURABILI
where ELF_FLAG_ANN = 'N'
AND ELF_DATA_VER_FIN = TO_DATE('31/12/9999','DD/MM/YYYY')
) elf **using** (ROPT_RAGGR_OPZTAR_ID,COID_CONTRATTUARIO_ID,ROPT_DATA_INI,EDW_PARTITION)
-- LEFT OUTER JOIN TAR_VOCI_FATTURABILI vof
-- ON (elf.VOF_VOCE_FATTURABILE_ID = vof.VOF_VOCE_FATTURABILE_ID)
-- LEFT OUTER JOIN BASE_FASCE_ORARIE fas
-- ON (fas.FAS_FASCIA_ORARIA_ID = elf.FAS_FASCIA_ORARIA_ID)
WHERE FORN_FORNITURA_ID = 'QJlXmOFZPF3eAlAG'
ORDER BY elf.ELF_VERSIONE DESC;
The using keyword indicates that this is a natural join. This means that the column names on both side of the join are identical.
In your case this means that you will join both sides on ROPT_RAGGR_OPZTAR_ID, COID_CONTRATTUARIO_ID, ROPT_DATA_INI and EDW_PARTITION.