I have two tables which I receive from function:
SELECT val FROM dbo.StringSeparatorParser('1,2,3', ','):
Table
---
1
2
3
SELECT val FROM dbo.StringSeparatorParser('2,3,4', ',')
Table
--------
2
3
4
I need to combine them, or insert into new table like this:
Column1 Column2
-----------------
1 2
2 3
3 4
How can I do that?:)
You need a column to join them on. You can generate one using row_nmber():
select i.id, c.capacity
from (select id, row_number() over (order by id) as seqnum
from ids
) i join
(select capacity, row_number() over (order by capacity) as seqnum
from capacities
) c
on i.seqnum = c.seqnum;
Related
I have a table like this:
D
S
2
1
2
3
4
2
4
3
4
5
6
1
in which the code of symptoms(S) of three diseases(D) are shown. I want to rearrange this table (D-S) such that the diseases with more symptoms come up i.e. order it by decreasing the numbers of symptoms as below:
D
S
4
2
4
3
4
5
2
1
2
3
6
1
Can anyone help me to write a SQL code for it in SQL server?
I had tried to do this as the following but this doesn't work:
SELECT *
FROM (
select D, Count(S) cnt
from [D-S]
group by D
) Q
order by Q.cnt desc
select
D,
S
from
D-S
order by
count(*) over(partition by D) desc,
D,
S;
Two easy ways to approach this:
--==== Sample Data
DECLARE #t TABLE (D INT, S INT);
INSERT #t VALUES(2,1),(2,3),(4,2),(4,3),(4,5),(6,1);
--==== Using Window Function
SELECT t.D, t.S
FROM (SELECT t.*, Rnk = COUNT(*) OVER (PARTITION BY t.D) FROM #t AS t) AS t
ORDER BY t.Rnk DESC;
--==== Using standard GROUP BY
SELECT t.*
FROM #t AS t
JOIN
(
SELECT t2.D, Cnt = COUNT(*)
FROM #t AS t2
GROUP BY t2.D
) AS t2 ON t.D = t2.D
ORDER BY t2.Cnt DESC;
Results:
D S
----------- -----------
4 2
4 3
4 5
2 1
2 3
6 1
Below is my table
a 1
a 2
a 1
b 1
a 2
a 2
b 3
b 2
a 1
My Expected output is
a 4
b 1
a 4
b 5
a 1
I want them to be grouped if they are in sequence.
If your dbms supports window functions, you can use the row_number difference to assign the same group to consecutive values (which are the same) in one column. After assigning the groups, it is easy to sum the values for each group.
select col1,sum(col2)
from (select t.*,
row_number() over(order by someid)
- row_number() over(partition by col1 order by someid) as grp
from tablename t
) x
group by col1,grp
Replace tablename, col1,col2,someid with the appropriate column names. someid should be the column to be ordered by.
My table
id name num
1 a 3
2 b 4
I need to return every row num number of times. I do it this way.
select DB.BAN_KEY as BAN_KEY, DB.CUST_FULLNAME as CUST_FULLNAME
from TST_DIM_BAN_SELECTED DB
inner join (select rownum rn from dual connect by level < 10) a
on a.rn <= DB.N
There resulting table looks like this.
id name
1 a
1 a
1 a
2 b
2 b
2 b
2 b
But I also need every row in the group to be numbered like this.
id name row_num
1 a 1
1 a 2
1 a 3
2 b 1
2 b 2
2 b 3
2 b 4
How can I do it?
You don't need an inner join to a dummy table or an analytic function to generate the row numbers; you could just use connect by (and its corresponding level function) on the table itself, like so:
WITH tst_dim_ban_selected AS (SELECT 1 ban_key, 'a' cust_fullname, 3 n FROM dual UNION ALL
SELECT 2 ban_key, 'b' cust_fullname, 4 n FROM dual)
-- end of mimicking your table with data in it. See SQL below
SELECT db.ban_key,
db.cust_fullname,
LEVEL row_num
FROM tst_dim_ban_selected db
CONNECT BY LEVEL <= db.n
AND PRIOR db.ban_key = db.ban_key -- assuming this is the primary key
AND PRIOR sys_guid() IS NOT NULL;
BAN_KEY CUST_FULLNAME ROW_NUM
---------- ------------- ----------
1 a 1
1 a 2
1 a 3
2 b 1
2 b 2
2 b 3
2 b 4
If you have other columns than ban_key in the table's primary key, you need to make sure they are included in the connect by clause's list of prior <column> = <column>s. This is so the connect by can identify each row uniquely, meaning that it's looping just over that row and no others. The PRIOR sys_guid() IS NOT NULL is required to prevent connect by loops from occurring.
You can use analytic function for this:
Select id, name,
row_number() over (partition by id, name order by id, name)
From(/* your query */) t;
This can be done without subquery:
Select id, name,
row_number() over (partition by id, name order by id, name)
From /* joins */
You could use this:
SELECT db.ban_key AS ban_key, db.cust_fullname AS cust_fullname,
ROW_NUMBER() OVER (PARTITION BY db.n ORDER BY db.ban_key) AS row_num
FROM tst_dim_ban_selected db
INNER JOIN (SELECT rownum rn FROM dual CONNECT BY level < 10) a
ON a.rn <= db.n;
Use a recursive sub-query factoring clause:
WITH split ( id, name, rn, n ) AS (
SELECT BAN_KEY, CUST_FULLNAME, 1, N
FROM TST_DIM_BAN_SELECTED
UNION ALL
SELECT id, name, rn + 1, n
FROM split
WHERE rn < n
)
SELECT id, name, rn
FROM split;
If I have a table like this:
Id StateId Name
1 1 a
2 2 b
3 1 c
4 1 d
5 3 e
6 2 f
I want to select like below:
Id StateId Name
4 1 d
5 3 e
6 2 f
For example, Ids 1,3,4 have stateid 1. So select row with max Id, i.e, 4.
; WITH CTE AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY STATEID ORDER BY ID DESC) AS RN
)SELECT ID, STATEID, NAME FROM CTE WHERE RN = 1
You can use ROW_NUMBER() + TOP 1 WITH TIES:
SELECT TOP 1 WITH TIES
Id,
StateId,
[Name]
FROM YourTable
ORDER BY ROW_NUMBER() OVER (PARTITION BY StateId ORDER BY Id DESC)
Output:
Id StateId Name
4 1 d
6 2 f
5 3 e
Disclaimer: I gave this answer before the OP had specified an actual database, and hence avoided using window functions. For a possibly more appropriate answer, see the reply by #Tanjim above.
Here is an option using joins which should work across most RDBMS.
SELECT t1.*
FROM yourTable t1
INNER JOIN
(
SELECT StateId, MAX(Id) AS Id
FROM yourTable
GROUP BY StateId
) t2
ON t1.StateId = t2.StateId AND
t1.Id = t2.Id
The following using a subquery, to find the maximum Id for each of the states. The WHERE clause then only includes rows with ids from that subquery.
SELECT
[Id], [StateID], [Name]
FROM
TABLENAME S1
WHERE
Id IN (SELECT MAX(Id) FROM TABLENAME S2 WHERE S2.StateID = S1.StateID)
I have a table_1:
id custno
1 1
2 2
3 3
and a table_2:
id custno qty descr
1 1 10 a
2 1 7 b
3 2 4 c
4 3 7 d
5 1 5 e
6 1 5 f
When I run this query to show the minimum order quantities from every customer:
SELECT DISTINCT table_1.custno,table_2.qty,table_2.descr
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno AND qty = (SELECT MIN(qty) FROM table_2
WHERE table_2.custno = table_1.custno )
Then I get this result:
custno qty descr
1 5 e
1 5 f
2 4 c
3 7 d
Customer 1 appears twice each time with the same minimum qty (& a different description) but I only want to see customer 1 appear once. I don't care if that is the record with 'e' as a description or 'f' as a description.
First of all... I'm not sure why you need to include table_1 in the queries to begin with:
select custno, min(qty) as min_qty
from table_2
group by custno;
But just in case there is other information that you need that wasn't included in the question:
select table_1.custno, ifnull(min(qty),0) as min_qty
from table_1
left outer join table_2
on table_1.custno = table_2.custno
group by table_1.custno;
"Generic" SQL way:
SELECT table_1.custno,table_2.qty,table_2.descr
FROM table_1, table_2
WHERE table_2.id = (SELECT TOP 1 id
FROM table_2
WHERE custno = table_1.custno
ORDER BY qty )
SQL 2008 way (probably faster):
SELECT custno, qty, descr
FROM
(SELECT
custno,
qty,
descr,
ROW_NUMBER() OVER (PARTITION BY custno ORDER BY qty) RowNum
FROM table_2
) A
WHERE RowNum = 1
If you use SQL-Server you could use ROW_NUMBER and a CTE:
WITH CTE AS
(
SELECT table_1.custno,table_2.qty,table_2.descr,
RN = ROW_NUMBER() OVER ( PARTITION BY table_1.custno
Order By table_2.qty ASC)
FROM table_1
LEFT OUTER JOIN table_2
ON table_1.custno = table_2.custno
)
SELECT custno, qty,descr
FROM CTE
WHERE RN = 1
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