Sort a dictionary in a column in pandas - pandas

Question

I have a dataframe as shown below.
user_id Recommended_modules Remaining_modules
1 {A:[5,11], B:[4]} {A:2, B:1}
2 {A:[8,4,2], B:[5], C:[6,8]} {A:7, B:1, C:2}
3 {A:[2,3,9], B:[8]} {A:5, B:1}
4 {A:[8,4,2], B:[5,1,2], C:[6]} {A:3, B:4, C:1}
Brief about the dataframe:
In the column Recommended_modules A, B and C are courses and the numbers inside the list are modules.
Key(Remaining_modules) = Course name
value(Remaining_modules) = Number of modules remaining in that course
From the above I would like to reorder the recommended_modules column based on the values in the Remaining_modules as shown below.
Expected Output:
user_id Ordered_Recommended_modules Ordered_Remaining_modules
1 {B:[4], A:[5,11]} {B:1, A:2}
2 {B:[5], C:[6,8], A:[8,4,2]} {B:1, C:2, A:7}
3 {B:[8], A:[2,3,9]} {B:1, A:5}
4 {C:[6], A:[8,4,2], B:[5,1,2]} {C:1, A:3, B:4}
Explanation:
For user_id = 2, Remaining_modules = {A:7, B:1, C:2}, sort like this {B:1, C:2, A:7}
similarly arrange Recommended_modules also in the same order as shown below
{B:[5], C:[6,8], A:[8,4,2]}.

Answer 1

It is possible, only need python 3.6+:
def f(x):
#https://stackoverflow.com/a/613218/2901002
d1 = {k: v for k, v in sorted(x['Remaining_modules'].items(), key=lambda item: item[1])}
L = d1.keys()
#https://stackoverflow.com/a/21773891/2901002
d2 = {key:x['Recommended_modules'][key] for key in L if key in x['Recommended_modules']}
x['Remaining_modules'] = d1
x['Recommended_modules'] = d2
return x
df = df.apply(f, axis=1)
print (df)
user_id Recommended_modules \
0 1 {'B': [4], 'A': [5, 11]}
1 2 {'B': [5], 'C': [6, 8], 'A': [8, 4, 2]}
2 3 {'B': [8], 'A': [2, 3, 9]}
3 4 {'C': [6], 'A': [8, 4, 2], 'B': [5, 1, 2]}
Remaining_modules
0 {'B': 1, 'A': 2}
1 {'B': 1, 'C': 2, 'A': 7}
2 {'B': 1, 'A': 5}
3 {'C': 1, 'A': 3, 'B': 4}