I have table 1 with data and table 2 as a lookup table with metadata. I need a query that returns all records from table 1 where either column in table 1 not exists in table two.
The following query works fine for one column, but if I use more than one column in my join it´s not.
working query:
select
T1.SCENARIO,
T1.year,
T1.period,
T1.ENTITY,
T1.account,
T1.ICP,
T1.MVMTS,
T1.C1,
T1.C2,
T1.C3,
T1.MULTI_GAAP,
T1.VLAUE
from
"fccs".MV_FACT_FCCS T1
left outer join "fccs".V_META_NOT_FOUND V2 on trim(T1.account) = trim(V2.account)
where
V2.account is null
not working correctly:
select
T1.SCENARIO,
T1.year,
T1.period,
T1.ENTITY,
T1.account,
T1.ICP,
T1.MVMTS,
T1.C1,
T1.C2,
T1.C3,
T1.MULTI_GAAP,
T1.VLAUE
from
"fccs".MV_FACT_FCCS T1
left outer join "fccs".V_META_NOT_FOUND V2 on trim(T1.account) = trim(V2.account)
and trim(T1.entity) = trim(v2.entity)
where
V2.account is null or v2.entity is null
The second query continues to bring the records from table 1 where exist in table 2.
Any help appreciated!
I need a query that returns all records from table 1 where either column in table 1 not exists in table two.
Use not exists:
select ff.*
from "fccs".MV_FACT_FCCS ff
where not exists (select 1
from "fccs".V_META_NOT_FOUND mnf
where trim(ff.account) = trim(mnf.account)
) or
not exists (select 1
from "fccs".V_META_NOT_FOUND mnf
where trim(ff.entity) = mnf.trimc
) ;
Note: This answers the question as written. You might mean that both conditions are not met. In that case, use and instead of or.
Related
I'm trying to join two tables but not getting the desired results. Im new to SQL and will need help to joining these two tables.
The data in Table 2 is transposed and the table will only be populated only when the "value" field is populated with random values.
Details of Table 1 and Table 2 and expected output
You could use CTEs to split up the impact from outcome. Also, your screenshot had an error for task_id 6.
with t_impact as (
select task_id, value
from table2
where name = 'task_impact'
),
t_outcome as (
select task_id, value
from table2
where name = 'task_outcome'
)
select distinct t1.id,
t1.title,
i.value as task_impact,
o.value as task_outcome
from table1 t1
left join t_impact i
on t1.id = i.task_id
left join t_outcome o
on t1.id = o.task_id
order by t1.id
DB-fiddle found here.
I have 2 tables that showing data Item master and BOM. I would like to join the tables between Item master as T1 and BOM as T2 and the additional table for table BOM as T3. Item master table containing ITM_CD, ITM_TYP (1,2,3,4) where each ITM_TYP represents a code for the first digit on ITM_CD. The thing that I want is like the picture below
CHILD_CD2 value replace to CHILD_CD1 value. So the data should be like this. What query should I fix ? I am very new using oracle query.
Here is mycode;
SELECT DISTINCT
T1.ITM_CD,
T2.C_ITM_CD AS CHILD_CD1,
T3.C_ITM_CD AS CHILD_CD2
FROM CM_HINMO_ALL T1
INNER JOIN (SELECT P_ITM_CD, C_ITM_CD, BOM_PTN FROM SM_BOM_ALL) T2
ON T1.ITM_CD = T2.P_ITM_CD
LEFT JOIN (SELECT P_ITM_CD, C_ITM_CD, BOM_PTN FROM SM_BOM_ALL) T3
ON T2.C_ITM_CD = t3.P_ITM_CD
WHERE 0=0
AND T2.BOM_PTN IN (1)
AND T1.ITM_TYP IN (1,2)
AND T1.ITM_CD = '110100370'
ORDER BY 2
Just use Case expression to replace the values.
SELECT ITM_CD, CASE WHEN CHILD_CD2 IS NULL THEN CHILD_CD2 ELSE CHILD_CD1 END AS CHILD_CD1
FROM TABLE1
If I understood, you want child_cd2 value should taken precedence over child_cd1 if available. If this assumption is right then we can use coalesce which returns the fist non null expression to achieve the same.
SELECT DISTINCT
T1.ITM_CD,
COALESCE(T3.C_ITM_CD,T2.C_ITM_CD) AS CHILD_CD1
FROM CM_HINMO_ALL T1
INNER JOIN SM_BOM_ALL T2
ON T1.ITM_CD = T2.P_ITM_CD
LEFT JOIN SM_BOM_ALL T3
ON T2.C_ITM_CD = t3.P_ITM_CD
WHERE T2.BOM_PTN IN (1)
AND T1.ITM_TYP IN (1,2)
AND T1.ITM_CD = '110100370'
ORDER BY 2
Assume there is a table name "test" below:
name value
n1 1
n2 2
n3 3
Now, I want to get the name which has the max value, I have some solution below:
Solution 1:
SELECT TOP 1 name
FROM test
ORDER BY value DESC
solution 2:
SELECT name
FROM test
WHERE value = (SELECT MAX(value) FROM test);
Now, I hope use join operation to find the result, like
SELECT name
FROM test
INNER JOIN test ON...
Could someone please help and explain how it works?
If you are looking for JOIN then
SELECT T.name, T.value
FROM test T
INNER JOIN
( SELECT T1.name, T1.value ,
RANK() OVER (PARTITION BY T1.name ORDER BY T1.value) N
FROM test T1
WHERE T1.value IN (SELECT MAX(t2.value) FROM test T2)
)T3 ON T3.N = 1 AND T.name = T3.name
FIDDLE DEMO
or
select name, value
from
(
select name, value,
row_number() over(order by value desc) rn
from test
) src
where rn = 1
FIDDLE DEMO
First, note that solutions 1 and 2 could give different results when value is not unique. If in your test data there would be an additional record ('n4', 3), then solution 1 would return either 'n3' or 'n4', but solution 2 would return both.
A solution with JOIN will need aliases for the table, because as you started of, the engine would say Ambiguous column name 'name'.: it would not know whether to take name from the first or second occurrence of the test table.
Here is a way to complete the JOIN version:
SELECT t1.name
FROM test t1
LEFT JOIN test t2
ON t2.value > t1.value
WHERE t2.value IS NULL;
This query takes each of the records, and checks if any records exist that have a higher value. If not, the first record will be in the result. Note the use of LEFT: this denotes an outer join, so that records from t1 that have no match with t2 -- based on the ON condition -- are not immediately rejected (as would be the case with INNER): in fact, we want to reject all the other records, which is done with the WHERE clause.
A way to understand this mechanism, is to look at a variant of the query above, which lacks the WHERE clause and returns the values of both tables:
SELECT t1.value, t2.value
FROM test t1
LEFT JOIN test t2
ON t2.value > t1.value
On your test data this will return:
t1.value t2.value
1 2
1 3
2 3
3 (null)
Note that the last entry would not be there if the join where an INNER JOIN. But with the outer join, one can now look for the NULL values and actually get those records in the result that would be excluded from an INNER JOIN.
Note that this query will give the same result as solution 2 when there are duplicate values. If you want to have also only one result like with solution 1, it suffices to add TOP 1 after SELECT.
Here is a fiddle.
Alternative with pure INNER JOIN
If you really want an INNER join, then this will do it. Again the TOP 1 is only needed if you have non-unique values:
SELECT TOP 1 t1.name
FROM test t1
INNER JOIN (SELECT Max(value) AS value FROM test) t2
ON t2.value = t1.value;
But this one really is very similar to what you did in solution 2. Here is fiddle for it.
Hi I have 2 tables. I want to list
all records in table1 which are present in
table2
all records in table2 which are not present in table1 with a where condition
Null rows will be returned by table1 in second condition but I am unable to get the query working correctly. It is only returning null rows
SELECT
A.CLMSRNO,A.CLMPLANO,A.GENCURRCODE,A.CLMNETLOSSAMT,
A.CLMLOSSAMT,A.CLMCLAIMPRCLLOSSSHARE
FROM
PAKRE.CLMCLMENTRY A
RIGHT OUTER JOIN (
SELECT
B.CLMSRNO,B.UWADVICETYPE,B.UWADVICENO,B.UWADVPREMCURRCODE,
B.GENSUBBUSICLASS,B.UWADVICENET,B.UWADVICEKIND,B.UWADVYEAR,
B.UWADVQTR,B.ISMANUAL,B.UWCLMNOREFNO
FROM
PAKRE.UWADVICE B
WHERE
B.ISMANUAL=1
) r
ON a.CLMSRNO=r.CLMSRNO
ORDER BY
A.CLMSRNO DESC;
Which OS are you using ?
Table aliases are case sensistive on some platforms, which is why your join condition ON a.CLMSRNO=r.CLMSRNO fails.
Try with A.CLMSRNO=r.CLMSRNO and see if that works
I'm not understanding your first attempt, but here's basically what you need, I think:
SELECT *
FROM TABLE1
INNER JOIN TABLE2
ON joincondition
UNION ALL
SELECT *
FROM TABLE2
LEFT JOIN TABLE1
ON joincondition
AND TABLE1.wherecondition
WHERE TABLE1.somejoincolumn IS NULL
I think you may want to remove the subquery and put its columns into the main query e.g.
SELECT A.CLMSRNO, A.CLMPLANO, A.GENCURRCODE, A.CLMNETLOSSAMT,
A.CLMLOSSAMT, A.CLMCLAIMPRCLLOSSSHARE,
B.CLMSRNO, B.UWADVICETYPE, B.UWADVICENO, B.UWADVPREMCURRCODE,
B.GENSUBBUSICLASS, B.UWADVICENET, B.UWADVICEKIND, B.UWADVYEAR,
B.UWADVQTR, B.ISMANUAL, B.UWCLMNOREFNO
FROM PAKRE.CLMCLMENTRY A
RIGHT OUTER JOIN PAKRE.UWADVICE B
ON A.CLMSRNO = B.CLMSRNO
WHERE B.ISMANUAL = 1
ORDER
BY A.CLMSRNO DESC;
Table1
...
LogEntryID *PrimaryKey*
Value
ThresholdID - - - Link to the appropriate threshold being applied to this log entry.
...
Table2
...
ThresholdID *PrimaryKey*
Threshold
...
All fields are integers.
The "..." thingies are there to show that these tables hold a lot more imformation than just this. They are set up this way for a reason, and I can't change it at this point.
I need write a SQL statement to select every record from Table1 where the Value field in that particular log record is less than the Threshold field in the linked record of Table2.
I'm newish to SQL, so I know this is a basic question.
If anyone can show me how this SQL statement would be structured, it would be greatly appreciated.
SELECT T1.*
FROM Table1 T1
JOIN Table2 T2 ON T2.ThresholdID = T1.ThresholdID
WHERE T2.Threshold > T1.Value
SELECT t1.*
FROM dbo.Table1 t1 INNER JOIN dbo.Table2 t2 ON t1.ThresholdID = t2.ThresholdID
WHERE t2.Threshold > t1.Value
SELECT * from table1 t1 join table2 t2 on (t1.thresholdId = t2.thresholdId)
where t1.value < t2.threshold;
SELECT t1.LogEntryID, t1.Value, t1.ThresholdID
FROM Table1 t1
INNER JOIN Table2 t2 ON t1.ThresholdID = t2.ThresholdID
WHERE t1.Value < t2.threshold
SELECT * FROM Table1
JOIN Table2
ON table1.ThresholdID = table2.ThresholdID --(assuming table 2 holds the same value to link them together)
WHERE
value < thresholdvalue
A 'JOIN' connects 2 tables based on the 'ON' clause (which can be multipart, using 'AND' and 'OR')
If you have 3 entries in table 2 which share table1's primary key (a one-to-many association) you will receive 3 rows in your result set.
for the tables below, for example:
Table 1:
Key Value
1 Hi
2 Bye
Table 2:
Table1Key 2nd_word
1 You
1 fellow
1 friend
2 now
this query:
SELECT * FROM Table1
JOIN Table2
on table1.key = table2.table1key
gets this result set:
Key Value Table1Key 2nd_word
1 Hi 1 You
1 Hi 1 fellow
1 Hi 1 friend
2 Bye 2 now
Note that JOIN will only return results when there is a match in the 2nd table, it will not return a result if there is no match. You can LEFT JOIN for that (all fields from the second table will be NULL).
JOINs can also be strung together, the result from the previous JOIN is used in place of the original table.