I have two tables: table1 and table2:
table1 has columns id and integer
table2 has columns id and boolean
table2 can have multiple rows with the same id
I want to update the integer column of table1 by looking at all rows with the same id in table2 and seeing if any of the boolean values are true. If so I want table1.integer to be 1, else I want it to be 0.
I have tried something like this:
UPDATE table1,
(
SELECT table2.id, Sum(table2.boolean) > 0
) AS 'condition'
from table2
WHERE 1
GROUP BY table2.id) table3
SET table1.integer =IF(table3.condition, 1, 0) where table1.id = table3.id
And it seems to work, but I wanted to ask if there is a nicer/cleaner/more succinct way of updating the rows of table1 according to multiple rows of table2.
I would recommend EXISTS:
UPDATE table1 t1
SET t1.integer = (EXISTS (SELECT 1
FROM table2 t2
WHERE t2.id = t.id AND
t2.boolean
)
);
This can take advantage of an index on table2(id, boolean). With such an index, it should be faster than an approach that uses JOIN and AGGREGATION.
The syntax of your query is MySql like, so you can do a join like this:
UPDATE table1 t1 INNER JOIN (
SELECT id, MAX(boolean) maxboolean
FROM table2
GROUP BY id
) t2 ON t2.id = t1.id
SET t1.integer = t2.maxboolean
If there are ids in table1 without a corresponding id in table2 and you want the integer column for them to be updated to 0 then use a LEFT join:
UPDATE table1 t1 LEFT JOIN (
SELECT id, MAX(boolean) maxboolean
FROM table2
GROUP BY id
) t2 ON t2.id = t1.id
SET t1.integer = COALESCE(t2.maxboolean, 0)
Related
there is 2 tables
table1
ID
1
2
4
6
7
TABLE2
2
4
6
i want those number from table1 which is not in table2 how i do this ?
i try this
select id from table1 t1
inner join table2 t2 on t1.id=t2.id
where t1.id not in (select id from table2)
but this is not working
SELECT t1.id
FROM table1 t1
LEFT JOIN table2 t2 ON t2.id = t1.id
WHERE t2.id IS NULL
Conceptually, we select all rows from table1 and for each row we attempt to find a row in table2 with the same value for the id column. If there is no such row, we just leave the table2 portion of our result empty for that row. Then we constrain our selection by picking only those rows in the result where the matching row does not exist. Finally, We ignore all fields from our result except for the id column (the one we are sure that exists, from table1).
try this:
select id from table1 t1 where t1.id not in (select t2.id from table2 t2)
You don't need to join the two tables in this case. You could just do
select id from table1 A where A.id not in (select B.id from table2 B);
You could also just simply use the sql set difference EXCEPT operator to achieve this
(select id from table1) except (select id from table2);
Use NOT IN or NOT EXISTS
select id from table1 t1
where t1.id not in (select id from table2)
select id from table1 t1
where not exists (select id from table2 where id = t1.id)
I have 2 tables with the same structure (field names). Table1 and Table2.
I need to return all records from Table1 and only records from Table2 that do not match/join to a record in Table1.
Table2 has more records than Table1.
I am joining the 2 tables on 3 fields.
So basically I want all records from table1 returned and only records that don't have a match (joining on the 3 fields) to table1 from table2 returned.
Put another way, Table1 records take precedence over table2 records in my final result output when the records exist in both tables (same value for the 3 fields)
I started writing something like the below but I don't think it will work. Should I use a left outer join instead?
Select * from table1 t1
left join table2 t2 on t1.id = t2.id and t1.date = t2.date and t1.custid= t2.custid
where t2.id is null or t2.date is null or t2.custid is null
So, you need every row from table1 plus the rows from table2 that don't match with table1?:
SELECT *
FROM table1
UNION ALL
SELECT *
FROM table2 t2
WHERE NOT EXISTS(SELECT * FROM table1
WHERE id = t2.id
AND date = t2.date
AND custid = t2.custid);
Select * from table1 t1
Union
Select * from table2 t2
Where Not exists
(Select * from table1
Where id = t1.id
and date = t1.date
and custid= t1.custid)
I'm stuck with a query and I'd need some help.
I need to select values from a table which meets two conditions from other table, for example:
Select * from table1
where ID = (select ID from table2)
AND value = (select value from table2)
So, if I'd need only one value from the table, I could query:
Select * from table1 where ID = (id1) AND value = (value1)
The only solution that I know is using IN, but it wouldn't be the requested solution.
I need something similar to this, but counting that the data returned by table2 is not only one row, but multiple.
Could somebody give me some clue on how to find this?
Thanks.
One method uses exists:
Select *
from table1 t1
where exists (select 1
from table2 t2
where t2.id = t1.id and t2.value = t1.value
);
This is ANSI standard syntax, so it should work in any database. Some databases support this syntax:
select t1.*
from table1 t1
where (t1.id, t1.value) in (select t2.id, t2.value from table2 t2);
I would use AND and OR
select *
from table1
where (ID = (id1) AND value = (value1))
OR (ID = (id2) AND value = (value2))
Each check must be added in brackets. This allows all results matching the pairs ID and VALUE to be returned.
Select * from
table1 inner join table2 on
(table1.ID = table2.ID and
table1.value = table2.value) ;
Since as far as I can understand , you just need to select every rows from table1 where ID and value in table1 equals ID and value in table2. So you just need inner join which joins table1 and table2 checking the condition.
Is there a quicker way to get the ids that exist in table1 but not exist in table2 and insert them in table2?
insert into table2 (id)
select id
from table1
where table1.id not in (select id from table2)
In addition to your solution using the in operator try the exists one
select id
from table1 t1
where not exists (
select 1
from table2
where id = t1.id
)
If the subquery returns an empty set not exists evaluates to true
The outer join
select id
from
table1 t1
left join
table2 t2 on t1.id = t2.id
where t2.id is null
Use explain analyze to compare
I have an interesting question for an SQL Join. I have 2 tables, examples below:
Table1: ID (int), Value(string)
Table2: ID (int), ForeignID(int), (Value)
The field ForeignID in Table2 is the foreign key of the ID in Table1. For a given entry in Table1, I have multiple entries in Table2 as follows:
Table1:
ID, Value
0, "Hello World"
1, "Bonjour"
Table2:
ID, ForeignID, Value
0, 0, "First entry"
1, 0, "Second entry"
2, 1, "Third entry"
If I do an inner join such as
SELECT Table1.Value, Table2. Value FROM
Table1 INNER JOIN Table2 ON Table1.ID = Table2.ForeignID
I would get
Hello world, First entry
Hello world, Second entry
Bonjour, Third entry
Is there a way to only get the TOP entry in Table2 such as:
Hello world, First entry
Bonjour, Third entry
This works too:
SELECT Table1.value
, Table2.value
FROM Table1
INNER JOIN Table2 ON Table1.id = Table2.foreignID
INNER JOIN (
SELECT MIN(ID) AS ID, ForeignID
FROM Table2
GROUP BY ForeignID
) MinID ON Table2.foreignid = MinID.foreignid
AND Table2.id = MinID.id
SELECT
t1.Value,
(
SELECT TOP 1 t2.Value FROM Table2 t2
WHERE t2.ForeignID = t1.ID
ORDER BY t2.ID ASC
)
FROM Table1 t1
SELECT Table1.Value,
(SELECT TOP 1 Table2.Value
FROM Table2
WHERE Table2.ForeignID = Table1.ID)
FROM Table1
Since you tagged SQL, here is the ANSI SQL query (which should work on SQL Server 2005+) :
WITH TT (ID, ForeignID, Value, N) AS (
SELECT ID, ForeignID, Value,
ROW_NUMBER() OVER(PARTITION BY ForeignID ORDER BY ID)
FROM Table2
)
SELECT T1.Value, T2.Value
FROM Table1 T1
INNER JOIN TT T2
ON T1.ID = T2.ForeignID
AND T2.N = 1;
It uses a Common Table Expression and a windowing function.
Here is another variation that makes sure that table2 in joined to table1 on the proper key.
SELECT t1.Value,
t2.Value
FROM Table1 t1
INNER JOIN Table2 t2
ON t2.ForeignID = (SELECT MIN(sub.ForeignID)
FROM Table2 sub WHERE sub.ForeignID = t1.ID)
Edit, actually, scratch that. Tamila's answer looks better to me.
If you can add a boolean is_first flag to your table2 then things become a lot easier and this would do the job for you:
SELECT table1."value", table2."value"
FROM table1
INNER JOIN table2 ON table1.id = table2.foreign_id
WHERE table2.is_first = true
I don't know if Daniel's, cgatian's or Leons' answers will work for your database. I'm on Postgres and it doesn't work for me.