How do I drop a row from this data frame? - pandas

Question

ID Address City State Country Name Employees
0 1 3666 21st St San Francisco CA 94114 USA Madeira 8
1 2 735 Dolores St San Francisco CA 94119 USA Bready Shop 15
2 3 332 Hill St San Francisco Cal USA Super River 25
3 4 3995 23rd St San Francisco CA 94114 USA Ben's Shop 10
4 5 1056 Sanchez St San Francisco California USA Sanchez 12
5 6 551 Alvarado St San Francisco CA 94114 USA Richvalley 20
df=df.drop(['3666 21st St'], axis=1, inplace=True)
I am using this code and still, it's showing an error stating that :
KeyError: "['3666 21st St'] not found in axis"
Can anyone help me solve this?

Answer 1

The drop method only works on the index or column names. There are 2 ways to do what you want:
Make the Address column the index, then drop the value(s) you want to drop. You should use axis=0 for this, and not axis=1. The default is axis=0. Do not use inplace=True if you are assigning the output.
Use a Boolean filter instead of drop.
The 1st method is preferred if the Address values are all distinct. The index of a data frame is effectively a sequence of row labels, so it doesn't make much sense to have duplicate row labels:
df.set_index('Address', inplace=True)
df.drop(['3666 21st St'], inplace=True)
The 2nd method is therefore preferred if the Address column is not distinct:
is_bad_address = df['Address'] == '3666 21st St'
# Alternative if you have multiple bad addresses:
# is_bad_address = df['Address'].isin(['366 21st St'])
df = df.loc[~is_bad_address]
You need to consult the Pandas documentation for the correct usage of the axis= and inplace= keyword arguments. You are using both of them incorrectly. DO NOT COPY AND PASTE CODE WITHOUT UNDERSTANDING HOW IT WORKS.