How can I make all values of one identifier the same based a on value in a row? - sql

Question

SELECT a.IDENTIFIER,
a.NAME,
a.CATEGORY,
b.IDENTIFIER_TYPE,
b.NAME,
CASE
WHEN b.IDENTIFIER_TYPE = 111 THEN 'PRESENT'
ELSE 'NOT PRESENT'
END AS HAS111
FROM TABLE_A a
LEFT JOIN IDENTIFIER_TYPE_TABLE b ON a.IDENTIFIER = b.IDENTIFIER
WHERE a.IDENTIFIER IN (1, 2, 3, 4)
;
Here is the code I'm using, and the data I'm getting is:
But I want the data to look like this:
Basically, I need this:
td {
text-align: center;
}
<table>
<tbody>
<tr>
<td>IDENTIFIER</td>
<td>NAME</td>
<td>CATEGORY</td>
<td>IDENTIFIER_TYPE</td>
<td>HAS111</td>
</tr>
<tr>
<td>123</td>
<td>item123</td>
<td>1</td>
<td>778</td>
<td>not present</td>
</tr>
<tr>
<td>123</td>
<td>item123</td>
<td>1</td>
<td>127</td>
<td>not present</td>
</tr>
<tr>
<td>123</td>
<td>item123</td>
<td>1</td>
<td>137</td>
<td>not present</td>
</tr>
<tr>
<td>456</td>
<td>item456</td>
<td>1</td>
<td>122</td>
<td>not present</td>
</tr>
<tr>
<td>456</td>
<td>item456</td>
<td>2</td>
<td>87</td>
<td>not present</td>
</tr>
<tr>
<td>456</td>
<td>item456</td>
<td>2</td>
<td>444</td>
<td>not present</td>
</tr>
<tr>
<td>789</td>
<td>item789</td>
<td>2</td>
<td>289</td>
<td>present</td>
</tr>
<tr>
<td>789</td>
<td>item789</td>
<td>2</td>
<td>111</td>
<td>present</td>
</tr>
<tr>
<td>789</td>
<td>item789</td>
<td>2</td>
<td>75</td>
<td>present</td>
</tr>
</tbody>
</table>
You see item789 has 111 in one of the rows, therefore I need all the other rows to say "present" for item789. The others don't have 111, so they have no 111 present. Does this make sense?

Answer 1

You can use EXISTS :
SELECT a.IDENTIFIER, a.NAME, a.CATEGORY, b.IDENTIFIER_TYPE, b.NAME,
(CASE WHEN EXISTS (SELECT 1
FROM IDENTIFIER_TYPE_TABLE b1
WHERE a.IDENTIFIER = b1.IDENTIFIER AND
b1.IDENTIFIER_TYPE = 111
)
THEN 'PRESENT' ELSE 'NOT PRESENT'
END) AS HAS111
FROM TABLE_A a LEFT JOIN
IDENTIFIER_TYPE_TABLE b
ON a.IDENTIFIER = b.IDENTIFIER
WHERE a.IDENTIFIER IN (1, 2, 3, 4);

Answer 2

Use window functions:
SELECT a.IDENTIFIER, a.NAME, a.CATEGORY,
b.IDENTIFIER_TYPE, b.NAME,
(CASE WHEN b.num_111 > 0 THEN 'PRESENT'
ELSE 'NOT PRESENT'
END) AS HAS111
FROM TABLE_A a LEFT JOIN
(SELECT b.*,
SUM(CASE WHEN b.IDENTIFIER_TYPE = 111 THEN 1 ELSE 0 END) OVER (PARTITION BY b.IDENTIFIER) as num_111
FROM IDENTIFIER_TYPE_TABLE b
) b
ON a.IDENTIFIER = b.IDENTIFIER
WHERE a.IDENTIFIER IN (1, 2, 3, 4);
Or don't use a subquery:
SELECT a.IDENTIFIER, a.NAME, a.CATEGORY,
b.IDENTIFIER_TYPE, b.NAME,
(CASE WHEN SUM(CASE WHEN b.IDENTIFIER_TYPE = 111 THEN 1 ELSE 0 END) > 0 THEN 'PRESENT'
ELSE 'NOT PRESENT'
END) AS HAS111
FROM TABLE_A a LEFT JOIN
IDENTIFIER_TYPE_TABLE b
ON a.IDENTIFIER = b.IDENTIFIER
WHERE a.IDENTIFIER IN (1, 2, 3, 4);

Answer 3

You will want to left join to your table again for just presents:
SELECT a.IDENTIFIER,
a.NAME,
a.CATEGORY,
b.IDENTIFIER_TYPE,
b.NAME,
iif( b.identifier is null,'Not Present','Present') as HAS111
FROM TABLE_A a
left join (Select distinct identifier table_A where type = 111) b on a.identifier=b.identifier