Postgres - how to build array in select with all rows ids - sql

Question

I would like to make something like this. Build array that I will have ids of all selected rows.
SELECT p.*,
array_agg(p.id) as places_ids,
(CASE
WHEN EXISTS(
SELECT id
FROM user_favorites uf
WHERE uf.place_id = p.id
AND uf.user_id = :userId
AND uf.deleted_at IS NULL
)
THEN true
ELSE false
END ) AS favorite
FROM (SELECT
DISTINCT ON (urv.object_id)
urv.id as recent_id,
p.id,
p.name,
p.address,
p.pictures
FROM user_recent_visits urv
JOIN places p on urv.object_id = p.id
WHERE urv.user_id = :userId
AND urv.object_type = :type
AND p.deleted_at IS NULL
AND p.status = 2
AND p.active = true
) AS p
GROUP BY p.recent_id, p.id, p.name, p.address
ORDER BY p.recent_id LIMIT 5
EDIT:
Full Error:
SQLSTATE[42883]: Undefined function: 7 ERROR: unknown compare operator for typ json LINE 30: ... GROUP BY
p.recent_id, p.id, p.name, p.address,... ^ (SQL: SELECT p.*,
array_agg(json_build_array(p.id)) as places_ids, (CASE WHEN EXISTS(
SELECT id FROM user_favorites uf WHERE uf.place_id = p.id AND
uf.user_id = :userId AND uf.deleted_at IS NULL ) THEN true ELSE false
END ) AS favorite FROM (SELECT DISTINCT ON (urv.object_id) urv.id as
recent_id, p.id, p.name, p.address, p.pictures FROM user_recent_visits
urv JOIN places p on urv.object_id = p.id WHERE urv.user_id = :userId
AND urv.object_type = :type AND p.deleted_at IS NULL AND p.status = 2
AND p.active = true ) AS p GROUP BY p.recent_id, p.id, p.name,
p.address, p.pictures ORDER BY p.recent_id LIMIT 5 )
But in this case I have error "unknown compare operator". So how to write this query to get that all ids as array.
Other question. Is it possible to do it without GROUP BY?
Thank you