Im trying to do following in simplest way.
I'd need to map list of objects into hashMap so that value1 is the key and value2 is entry object.
val map = mutableMapOf<String, Account>()
accountInfo.map {
map.put( it.value1 to it.value2 )
}
or
val map2 = accountInfo.map {
it.value1 to it.value2
}
but both are somehow wrong
first one says it only wants string as input.
Second one tells me its going to return List<Pair<String, Account>>
Why ?! thank you!
use put(x, y)
Not put( x to y)
Related
#file:Suppress("UNCHECKED_CAST")
data class Element<T>(
val key: String,
val valueOne: T,
val valueTwo: T,
val comparator: Comparator<T>,
val comparatorValue: CompareResult
)
enum class CompareResult(
val value: Int
) {
LESS(-1),
EQUAL(0),
GREATER_THAN(1)
}
fun <T> matchesComparison(list:Collection<Element<T>>): Pair<Boolean, List<String>> {
val failedComparisons = mutableListOf<String>()
for (element in list) {
val compareValue = element.comparator.compare(element.valueOne, element.valueTwo)
if (element.comparatorValue.value != compareValue) {
failedComparisons.add(element.key)
}
}
return Pair(failedComparisons.isEmpty(), failedComparisons)
}
val stringComparator = Comparator.comparing(String::toString)
val intComparator = Comparator.comparing(Int::toInt)
val elementsToCompare = listOf(
Element("number", 1, 2, intComparator, CompareResult.LESS),
Element("first name", "a", "a", stringComparator, CompareResult.EQUAL),
Element("last name", "a", "b", stringComparator, CompareResult.EQUAL)
)
matchesComparison(elementsToCompare).second.joinToString(", ","Failed elements: \"","\"")
I often get faced with comparing two different object properties with the same values.
As an example object A has props number,firstname,lastname. What i want to do is create a list have and have a function which goes over these Elements and returns which props have failed the comparison. I've managed to use generics for both the object and the matchesComparison function which returns the failed comparisons. The problem begins when i want to pass this list which is of type Collection<Element<out Any>> to this function is i get a type missmatch. instead of using unchecked casts to force the Comparator to be of type Any i would like to do this
val stringComparator = Comparator.comparing(String::toString)
val intComparator = Comparator.comparing(Int::toInt)
The result value that of the script above should be Failed elements: "last name"
I tried changing the signature of the function to out any but then the comparator.compare method has both params as of type Nothing. I really want to avoid unsing unchecked casts.
matchesComparison() doesn't need to be generic in this case. It doesn't really care what is the type of the whole input collection, so we can simply use * here.
Then we have another problem. The compiler isn't smart enough to notice that while we perform operations on a single element, all its properties are of matching types. As a result, it doesn't allow to use element.comparator on element.valueOne and element.valueTwo. To fix this problem, we simply need to create a separate function which works on a single Element, so it understand the type for all properties is the same:
fun matchesComparison(list:Collection<Element<*>>): Pair<Boolean, List<String>> {
fun <T> Element<T>.matches() = comparatorValue.value == comparator.compare(valueOne, valueTwo)
val failedComparisons = mutableListOf<String>()
for (element in list) {
if (!element.matches()) {
failedComparisons.add(element.key)
}
}
return Pair(failedComparisons.isEmpty(), failedComparisons)
}
Also, I believe such matches() function should be actually a member function of Element. It seems strange that while Element is pretty independent and it contains everything that is needed to perform a comparison, it still requires to use external code for this. If it would have a matches() function then we wouldn't need to care about its T. matches() would work with any Element.
So I was solving a problem that required me to put unique characters in a string without using a data structure.
fun main(){
val s1 = "fhfnfnfjuw"
val s2 = "Osayuki"
val s3 = "Raymond"
val s4 = "Aseosa"
uniqueChar(s1)
}
fun uniqueChar(s: String){
val updatedString = ""
s.forEach {c ->
if (!updatedString.contains(c)){
updatedString.plus(c)
}
}
println(updatedString)
}
And getting this error
I'm not sure what's going on and why I'm getting a blank. I'm sure it's an easy fix, but I can't see it. Any help is appreciated.
updatedString.plus(c) does not change updatedString. It creates a new string, including the character c. Since you don't do anything with that, the new string goes...nowhere.
Instead, you probably wanted updatedString = updatedString.plus(c) -- or something better with StringBuilder, but that's the closest version to your code.
I have a listOf Strings
val help = listOf("a","b","c")
And want to remove b from the list but not using index because I will get Strings randomly like this
val help = listOf("c","a","b")
How to do this?
You can filter the List using the condition item does not equal "b", like…
fun main(args: Array<String>) {
// example list
val help = listOf("a","b","c")
// item to be dropped / removed
val r = "b"
// print state before
println(help)
// create a new list filtering the source
val helped = help.filter { it != r }.toList()
// print the result
println(helped)
}
Output:
[a, b, c]
[a, c]
Lists by default aren't mutable. You should use mutable lists instead if you want that. Then you can simply do
val help = mutableListOf("a","b","c")
help.remove("b")
or you can do it like this if help really needs to be a non-mutable list
val help = listOf("a","b","c")
val newHelp = help.toMutableList().remove("b")
using a filter like in deHaar's answer is also possible
I am looking to find a way to combine some LiveData functions from my Dao and transform them into a single entity. I want to create something like this:
private val combinedValues(ld1, ld2, ld3, ld4){
first, second, third, fourth -> CombinedLiveDataValues(first, second, third, fourth)
}
val combinedEntity: LiveData<Any> = Transformations.map(combinedValues){ it->
val something = it.first.map (etc...)
}
How to create a way of not duplicating code and generalising and adding dozens of liveDatas together?
You can use something like this
fun<T> combine(context: AppCompatActivity, vararg input: LiveData<T>): LiveData<T> {
val output = MutableLiveData<T>()
input.forEach {
it.observe(context, androidx.lifecycle.Observer { value ->
output.value = value
})
}
return output
}
In Kotlin, how can I take the first n elements of this array:
val allColours = arrayOf(
Pair(Color.RED, Color.WHITE),
Pair(Color.RED, Color.BLACK),
Pair(Color.YELLOW, Color.BLACK),
Pair(Color.GREEN, Color.WHITE),
Pair(Color.BLUE, Color.WHITE),
Pair(Color.BLUE, Color.WHITE),
Pair(Color.CYAN, Color.BLACK),
Pair(Color.WHITE, Color.BLACK))
So how can I fill pegColours with the first say 3 Pairs?
var pegColours: Array<Pair<Color,Color>> = //???
I tried allColours.take but it gave an error:
Expecting an element
You need to specify the number of items you want to take.
allColours.take(3)
For a random number of random indices, you can use the following:
val indexes = arrayOf(2, 4, 6)
allColours.filterIndexed { index, s -> indexes.contains(index) }
Note that you can write an extension method for this:
fun <T> Array<T>.filterByIndices(vararg indices: Int) = filterIndexed { index, _ -> indices.contains(index) }
Alternatively, if the indices are consecutive, you can use slice:
allColours.slice(1..3)
The problem with your code that you create pairs with color constants which are Ints (allColours has type Array<Pair<Int, Int>>), but you expect Array<Pair<Color, Color>>. What you have to do is change type pegColours type and use take:
var pegColours: Array<Pair<Int, Int>> = allColours.take(3).toTypedArray()
Also you have to call toTypedArray() cause Array.take returns List rather than Array. Or you can change pegColours type as following:
var pegColours: List<Pair<Int, Int>> = allColours.take(3)
I know you already proposed the usage of take, but alternatively ranges and a simple map also help to write idiomatic code as shown next:
var pegColours = (0 until 3)
.map { allColours[it] }
.toTypedArray()
You are very close :)
val allColours = arrayOf("red", "blue", "green")
kotlin.io.println(allColours.take(2))
Will give you first two elements ["red", "blue"]
You have to specify the number of elements you want to take from the array