I have records for each user which occur multiple times each month. I wish to select just the highest value from the repeated values for each month for each user.
Table schema
custacc
ID | ac_no | DODSTART | od_limit
---+--------+------------+----------
1 | 110011 | 2019-02-10 | 200,000
2 | 110011 | 2019-02-12 | 120,000
3 | 110014 | 2019-02-10 | 70,000
4 | 110014 | 2019-02-12 | 10,000
5 | 110009 | 2019-02-10 | 30,000
customer
ID | cust_no | name | cust_type
---+---------+-------+----------
1 | 110011 | Jame | M
2 | 110014 | Fred | N
3 | 110009 | Ahmed | M
How can I achieve this>
What I tried so far:
SELECT
custacc.ac_no,
custacc.od_limit,
custacc.DODSTART,
customer.name,
custacc.gl_no,
custacc.USERNAME,
customer.cust_type
FROM
custacc
LEFT JOIN
customer ON custacc.ac_no = customer.cust_no
INNER JOIN
(SELECT
MAX(DODSTART) LAST_UPDATE_DATE_TIME,
ac_no
FROM
custacc
GROUP BY
ac_no) s2 ON custacc.ac_no = s2.ac_no
AND custacc.DODSTART = s2.LAST_UPDATE_DATE_TIME
WHERE
custacc.od_limit != 0.00
The query doesn't return the expected result.
Try this(add columns that you need):
This is Oracle solution since you didn't mention it in your question:
SELECT ID,MAX(OD_LIMIT) OVER(PARTITION BY ID,EXTRACT(MONTH FROM DODSTART)) FROM CUSTACC;
Related
I have a matches and a teams tables. Here's a Db Fiddle. I'm using Postgres.
They look like this:
matches table
id_match | id_home | id_away | date_time
----------+---------+---------+---------------------
1 | 1 | 2 | 2018-11-03 16:30:00
2 | 1 | 3 | 2019-11-03 16:30:00
3 | 2 | 3 | 2019-11-03 16:30:00
4 | 3 | 1 | 2020-11-03 16:30:00
teams table
id_team | club | shorthand
---------+----------------+-----------
1 | Vinica | VIN
2 | Kolpa | KOL
3 | Crnomelj | CRN
4 | Klub Študentov | KBŠ
5 | Zilje | ZLJ
6 | Preloka | PRK
I'm trying to query and join the two to get:
team name | total number of matches
----------+--------------------------
Vinica | 3
Kolpa | 2
Crnomelj | 3
The hard bit that I find is the fact that the team id can appear in two columns of the matches table.
You can unpivot the data using a lateral join. Then join and aggregate:
select t.club, count(*)
from matches m cross join lateral
(values (m.id_home), (m.id_away)
) v(id_team) join
teams t
on t.id_team = v.id_team
group by t.club;
Here is the fiddle.
could help me solve this duplication problem where it returns more than 1 result for the same record I want to bring only 1 result for each id, and only the last history of each record.
My Query:
SELECT DISTINCT ON(tickets.ticket_id,ticket_histories.created_at)
ticket.id AS ticket_id,
tickets.priority,
tickets.title,
tickets.company,
tickets.ticket_statuse,
tickets.created_at AS created_ticket,
group_user.id AS group_id,
group_user.name AS user_group,
ch_history.description AS ch_description,
ch_history.created_at AS ch_history
FROM
tickets
INNER JOIN company ON (company.id = tickets.company_id)
INNER JOIN (SELECT id,
tickets_id,
description,
user_id,
MAX(tickets.created_at) AS created_ticket
FROM
ch_history
GROUP BY id,
created_at,
ticket_id,
user_id,
description
ORDER BY created_at DESC LIMIT 1) AS ch_history ON (ch_history.ticket_id = ticket.id)
INNER JOIN users ON (users.id = ch_history.user_id)
INNER JOIN group_users ON (group_users.id = users.group_user_id)
WHERE company = 15
GROUP BY
tickets.id,
ch_history.created_at DESC;
Result of my query, but returns 3 or 5 identical ids with different histories
I want to return only 1 id of each ticket, and only the last recorded history of each tick
ticket_id | priority | title | company_id | ticket_statuse | created_ticket | company | user_group | group_id | ch_description | ch_history
-----------+------------+--------------------------------------+------------+-----------------+----------------------------+------------------------------------------------------+-----------------+----------+------------------------+----------------------------
49713 | 2 | REMOVE DATA | 1 | t | 2019-12-09 17:50:35.724485 | SAME COMPANY | people | 5 | TEST 1 | 2019-12-10 09:31:45.780667
49706 | 2 | INCLUDE DATA | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 2 | 2019-12-10 09:38:52.769515
49706 | 2 | ANY TITLE | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 3 | 2019-12-10 09:39:22.779473
49706 | 2 | NOTING ELSE MAT | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TESTE 4 | 2019-12-10 09:42:59.50332
49706 | 2 | WHITESTRIPES | 1 | f | 2019-12-09 09:16:35.320708 | SAME COMPANY | people | 5 | TEST 5 | 2019-12-10 09:44:30.675434
wanted to return as below
ticket_id | priority | title | company_id | ticket_statuse | created_ticket | company | user_group | group_id | ch_description | ch_history
-----------+------------+--------------------------------------+------------+-----------------+----------------------------+------------------------------------------------------+-----------------+----------+------------------------+----------------------------
49713 | 2 | REMOVE DATA | 1 | t | 2019-12-09 17:50:10.724485 | SAME COMPANY | people | 5 | TEST 1 | 2020-01-01 18:31:45.780667
49707 | 2 | INCLUDE DATA | 1 | f | 2019-12-11 19:22:21.320701 | SAME COMPANY | people | 5 | TEST 2 | 2020-02-05 16:38:52.769515
49708 | 2 | ANY TITLE | 1 | f | 2019-12-15 07:15:57.320950 | SAME COMPANY | people | 5 | TEST 3 | 2020-02-06 07:39:22.779473
49709 | 2 | NOTING ELSE MAT | 1 | f | 2019-12-16 08:30:28.320881 | SAME COMPANY | people | 5 | TESTE 4 | 2020-01-07 11:42:59.50332
49701 | 2 | WHITESTRIPES | 1 | f | 2019-12-21 11:04:00.320450 | SAME COMPANY | people | 5 | TEST 5 | 2020-01-04 10:44:30.675434
I wanted to return as shown below, see that the field ch_description, and ch_history bring only the most recent records and only the last of each ticket listed, without duplication I wanted to bring this way could help me.
Two things jump out at me:
You have listed "created at" as part of your "distinct on," which is going to inherently give you multiple rows per ticket id (unless there happens to be only one)
The distinct on should make the subquery on the ticket history unnecessary... and even if you chose to do it this way, you again are going on the "created at" column, which will give you multiple results. The ideal subquery, should you choose this approach, would have been to group by ticket_id and only ticket_id.
Slightly related:
An alternative approach to the subquery would be an analytic function (windowing function), but I'll save that for another day.
I think the query you want, which will give you one row per ticket_id, based on the history table's created_at field would be something like this:
select distinct on (t.id)
<your fields here>
from
tickets t
join company c on t.company_id = c.id
join ch_history ch on ch.ticket_id = t.id
join users u on ch.user_id = u.ud
join group_users g on u.group_user_id = g.id
where
company = 15
order by
t.id, ch.created_at -- this is what tells distinct on which record to choose
I have one table with fake individual tax records like so (one row per filer):
T1:
+-------+---------+---------+
| Person| Spouse | Income |
+-------+---------+---------+
| 1 | 2 | 34000 |
| 2 | 1 | 10000 |
| 3 | NULL | 97000 |
| 4 | 6 | 11000 |
| 5 | NULL | 25000 |
| 6 | 4 | 100000 |
+-------+---------+---------+
I have a second table which has tax 'families', a single individual or married couple (one line per tax 'family').
T1_Family:
+-------- -+-------+---------+
| Family_id| Person| Spouse |
+-------- -+-------+---------+
| 2 | 2 | 1 |
| 3 | 3 | NULL |
| 5 | 5 | NULL |
| 6 | 6 | 4 |
+------ ---+-------+---------+
Family = max(Person) within a couple
The idea of joining the two is for example, to sum the income of 2 people in one tax family (aggregate to the family level).
So, I've tried the following:
select *
into family_table
from
(
(select * from T1_family)a
join
(select * from T1)b
on a.family = b.person **or a.spouse = b.person**
)
where family_id is not null and person is not null
What I should get (and I do get when I select 1 random couple) is one line per individual where I can then group by family_id and sum income, pension contributions, etc. BUT SQL times out before the tables can be joined. The part in bold is what's slowing down the process but I'm not sure what else to do.
Is there an easier way to group by family?
It is simpler to put the data on one row:
select a.*, p.income as person_income, s.income as spouse_income
into family_table
from t1_family a left join
t1 p
on a.person = p.person lef tjoin
t1 s
on a.spouse = s.person;
Of course, you can add them together as well.
here is my table called "Employee"
eID | name |
==============
1 | Mike |
2 | Josh |
3 | Mike |
And table called "Sells"
sID | eID | | price |
=========================
1 | 1 | | 8 |
2 | 3 | | 9 |
3 | 3 | | 5 |
4 | 1 | | 4 |
5 | 1 | | 3 |
This should be my expected result: returns the total income per employee
name | Income |
==================
Mike | 15 |
Josh | 0 |
Mike | 14 |
Actually, I know use the query "SUM...GROUP BY..." to get the incomes of 15 and 14, but I don't know how to get the income of 0 which is not shown on the "Sells" table.
Could someone give me some help? Thanks a lot.
You just need to use a left outer join, so you can get the sum for missing values too. You could use case expression to deal with null values
SELECT e.name,
COALESCE(SUM(price), 0) as Income
FROM employees e
LEFT OUTER JOIN sells s
ON e.eid = s.eid
GROUP BY e.eid, e.name
Edited: case expression is not needed. I put coalesce on the return of sum fuction, in order to deal with missing values (SUM over an empty set returns NULL)
I have two tables:
1. Master
| ID | Name | Amount |
|-----|--------|--------|
| 1 | a | 5000 |
| 2 | b | 10000 |
| 3 | c | 5000 |
| 4 | d | 8000 |
2. Detail
| ID |MasterID| PID | Qty |
|-----|--------|-------|------|
| 1 | 1 | 1 | 10 |
| 2 | 1 | 2 | 20 |
| 3 | 2 | 2 | 60 |
| 4 | 2 | 3 | 10 |
| 5 | 3 | 4 | 100 |
| 6 | 4 | 1 | 20 |
| 7 | 4 | 3 | 40 |
I want to select sum(Amount) from Master which joins to Deatil where Detail.PID in (1,2,3)
So I execute the following query:
SELECT SUM(Amount) FROM Master M INNER JOIN Detail D ON M.ID = D.MasterID WHERE D.PID IN (1,2,3)
Result should be 20000. But I am getting 40000
See this fiddle. Any suggestion?
You are getting exactly double the amount because the detail table has two occurences for each of the PIDs in the WHERE clause.
See demo
Use
SELECT SUM(Amount)
FROM Master M
WHERE M.ID IN (
SELECT DISTINCT MasterID
FROM DETAIL
WHERE PID IN (1,2,3) )
What is the requirement of joining the master table with details when you have all your columns are in Master table.
Also, isnt there any FK relationhsip defined on these tables. Looking at your data it seems to me that there should be FK on detail table for MasterId. If that is the case then you do not need join the table at all.
Also, in case you want to make sure that you have records in details table for the records for which you need sum and there is no FK relationship. Then you could give a try for exists instead of join.