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Given below is the table of Car sales (of all models from different manufacturers) . ( only few rows are shown)
Date Name Model Units_sold
Dec-2020 Audi A4 300
Dec-2020 BMW 3Series 164
Jan-2020 Maruti Alto 33118
Jan-2020 Toyota Fortuner 1103
Feb-2020 skoda Superb 391
On SQL Server we can try:
SELECT TOP 1 WITH TIES Date, Name, Model, Units_sold
FROM yourTable
ORDER BY
ROW_NUMBER() OVER (PARTITION BY YEAR(Date), Name ORDER BY Units_sold DESC);
Related
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I have a sample table
ID
Invoice_ID
docType
1
100
email
2
100
sms
3
200
email
4
200
email
5
300
sms
and I have to get results with only rows that have invoices with email and sms docType. For this example its only invoice_id 100
One approach is to query those type and count the distinct number of different types that appear:
SELECT invoice_id
FROM invoices
WHERE doctype IN ('sms', 'email')
GROUP BY invoice_id
HAVING COUNT(DISTINCT doctype) = 2
One method uses aggregation:
select invoice_id
from t
where docType in ('email', 'sms')
group by invoice_id
having count(distinct doctype) = 2;
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I have a table which has the below data:
PLAYER RUN
-----------------
Kohli 100
Kohli 200
Sachin 200
Yuvi 300
Yuvi 300
Yuvi 300
I need to return the Player's name who scored the maximum number of runs.
How can I achieve this by a SQL query ? In this case the query should return "Yuvi" .
Could you please use the query given below
SELECT TOP 1 PLAYER, MAX(RUN) AS MAXRUN FROM <TABLE> GROUP BY PLAYER ORDER BY MAXRUN DESC;
select player from (select player , sum(runs) from test group by player,runs order by sum(sal) desc) where rownum=1;
You should use Max function in the column RUN. The query will be,
Select PLAYER, MAX(RUN) from TABLE;
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I have a table with data like:
cust_id, acct_no, ind
123111, 1233, Y
123111, 2311, N
222111, 1112, N
222111, 2111, N
I have to get output as cust_id, 1 (a binary indicator if any of the acct under that customer is Y)
so from the above table I have to get below output.
123111 1
222111 0
A simple way to achieve this is something like:
select cust_id, max(case when ind = 'Y' then 1 else 0 end) as flag from customers group by cust_id;
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I have got table like below after sorting in SQL:
M_ID
-----
2013/01
2013/02
2013/03
2013/04
2013/05
2013/06
Now I want to assign each entries a particular value like below
M_ID Days
--------------
2013/01 20
2013/02 30
2013/03 40
2013/04 50
2013/05 60
2013/06 70
So, can you please let me know how to do that in SQL Query?
Do you mean something like this (presuming sql-server)?
SELECT M_ID,
Days = (ROW_NUMBER()OVER(ORDER BY M_ID) + 1) * 10
FROM dbo.TableName
Demo
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I have this table on sql sever
cstomer |No_Nota
CUS000 | 98342
CUS000 | 98343
CUS000 | 98343
CUS001 | 98355
CUS001 | 98355
I would like to count the frequency of each customer. For similar number of no_nota the value is 1.
I'd like a result like this:
cstomer |Frequent
CUS000 | 2
CUS001 | 1
You want the distinct count of the column no_nota, so that's what you should select...
select customer, count(distinct no_nota) as frequent
from my_table
group by customer
You want to count the result of your select query:
SELECT COUNT(expression)
FROM tables
WHERE predicates;
Example:
SELECT COUNT(No_Nota) FROM your_table WHERE No_Nota > 0;
Sounds like you just want a group by statement to get a count of all individual customers. Something like:
SELECT cstomer, SUM(1) as Frequent FROM table GROUP BY cstomer, No_Nota