I have that field in my table:
2020-01-16T10:55:16..296518000
How to convert this Varchar into a date in format 'YYYY-MM-DD' ?
I tried:
select TRUNC(to_date(DATE_UPDATED ,'YYYY-MM-DD hh24:mi:ss')) from JOB_SCHEDULE_TBL
but I'm getting an error:
ORA-01830: date format picture ends before converting entire input string
Just use substr():
select to_date(SUBSTR(DATE_UPDATED, 1, 10) ,'YYYY-MM-DD')
The trunc() is unnecessary.
You are confusing the format of DATE with what you are seeing on the screen. A DATE data type has no "format". It's Oracle's internal, binary format. Even when you SELECT TO_DATE ..., the result is going to get displayed by the client, and to do so the client will have to peform (under the covers) a TO_CHAR on the resulting DATE. And that implied to_char will use the current system/session/ settings for TNS_DATE_FORMAT.
Related
My current query in oracle sql for getting a timestamp format is TO_CHAR(c2.start_on,'DD-MM-YY HH:MI:SS.FF PM'), it outputs the timestamp like this 25-11-20 07:00:13.36 PM
However I want it to display the date in this way 25-11-20 07:00:13.360000000 PM
What should I add in the timestamp format for this to be possible ?
I have tried doing it like this HH:MI:SS.FM00000 as suggested here
but it gives me the error. ORA-01821: date format not recognized
what is the correct way to get the date in the desired format ?
If you want fractional seconds, you don't want a DATE, you want a TIMESTAMP. So here's a timestamp formatted with 6 digits of precision
select to_char(systimestamp, 'HH:MI:SS.FF6') from dual;
If you have a date, you could convert it to a TIMESTAMP (using CAST AS TIMESTAMP), but better to look at updating your data model to use the proper type for the source column as starters.
nvl(cast(effective_DAte as varchar(100)),' ')
The above is the function i try to apply
When i do this the timestamp in the date is getting removed.Please help
Dates do have a time component in Oracle (confusingly and unlike other databases). By default, I guess Oracle wants people to forget that and only considers the date when converting to a string.
In general, the recommendation is to use to_char() so you can control the format:
select to_char(effective_date, 'YYYY-MM-DD HH24:MI:SS')
If you want the default format along with the time, you can cast the date as a timestamp and then convert to a string:
select to_char(cast(effective_date as timestamp))
I have a requirement to convert MM/DD/YYYY to YYYYMMDD in amazon redshift database.
My result of this query gives me some weird result. Can some one please help me.
select to_date ('07/17/2017','YYYYMMDD');
0007-07-20
If you just wish to convert the hard-coded string into a DATE:
select to_date('07/17/2017', 'MM/DD/YYYY')
If you have a column already formatted as DATE, then use:
to_char(fieldname, 'YYYYMMDD')
Combining the two concepts:
select to_char(to_date('07/17/2017', 'MM/DD/YYYY'), 'YYYYMMDD')
TO_DATE - converts a date represented in a character string to a DATE data type.
TO_CHAR - converts a time stamp or numeric expression to a character-string data format.
select to_char(sysdate,'YYYYMMDD');
If I’ve made a bad assumption please comment and I’ll refocus my answer.
select
to_timestamp(SCHEDULED_TIME,'YYYY-MM-DD HH24:MI:SS.FF') as SCHEDULED_TIME,
TRUNC(to_date(to_timestamp(SCHEDULED_TIME,'YYYY-MM-DD HH24:MI:SS.FF'),'YYYY-MM-DD HH24:MI:SS'))
from S_TIDAL_STATUS
The error was:
ORA-01830: date format picture ends before converting entire input string
01830. 00000 - "date format picture ends before converting entire input string"
The goal is to return something like
2017-07-91 23:14:00
(without the content after the dot).
Here's what the SCHEDULED_TIME (timestamp) looked like:
The problem in your attempt is the function TO_DATE() applied to a timestamp. TO_DATE() takes a VARCHAR2 (string) input, not a timestamp. So Oracle converts the timestamp to a string first, implicitly, using your NLS_TIMESTAMP_FORMAT parameter, and then attempts to convert this string to a date. Depending on your NLS_TIMESTAMP_FORMAT, you may get different errors.
The way to convert a timestamp to a date (datetime) - while truncating off the fractions of a second - is with the CAST function. Example:
select systimestamp,
cast (systimestamp as date) as ts_cast_to_date
from dual
;
Alternatively, if all your strings are EXACTLY in that format, you can truncate the strings first and apply TO_DATE directly:
to_date(substr(scheduled_time, 1, 19), 'yyyy-mm-dd hh24:mi:ss')
This should do the trick:
select
to_char(SCHEDULED_TIME,'YYYY-MM-DD HH24:MI:SS.FF') as time_to_csecs,
to_char(SCHEDULED_TIME,'YYYY-MM-DD HH24:MI:SS') as time_to_secs,
TRUNC(to_date(to_char(SCHEDULED_TIME,'YYYY-MM-DD HH24:MI:SS'),'YYYY-MM-DD HH24:MI:SS')) as time_to_day
from S_TIDAL_STATUS
Please review the docs to see the difference between to_timestamp and to_char.
I am getting invalid number error message while executing the below select statement.Can any one have an idea about the issue..Please let me know.
select TO_DATE(TO_CHAR('2015/01/22 00:00:00','YYYY/MM/DD'),'YYYY/MM/DD')
actually i want oracle standard date format without time stamp for this date '2015/01/22 00:00:00'
select to_date('2015/01/22 00:00:00','YYYY/MM/DD HH24:MI:SS') as dt
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/1/0
As an FYI, the Oracle DATE data type does include the time component (just not down to fractional seconds, as is the case with the TIMESTAMP data type).
If you are converting values and want to bring all the time values to zero you can use the trunc function like this (which changes 12:07:00 to 00:00:00):
select trunc(to_date('2015/01/22 12:07:00','YYYY/MM/DD HH24:MI:SS'),'DD') as dt_with_time_zerod
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/2/0
If the source is itself a date and you want to convert the date to a string in the Oracle default date format ('DD-MON-RR') you can achieve that by running:
select to_char(trunc(to_date('2015/01/22 12:07:00','YYYY/MM/DD HH24:MI:SS'),'DD'),'DD-MON-RR') as dt_with_time_zerod
from dual
Fiddle - http://sqlfiddle.com/#!4/6a3a6/3/0
If it's a date field, to_char without a mask will give you what you say you want.
actually i want oracle standard date format without time stamp for this date '2015/01/22 00:00:00'
I'm not sure what you mean by "Oracle standard date format." The format in which a date would appear would be based on your NLS settings (in particular, NLS_DATE_FORMAT). If you are just trying to format this string representing a date, then you might want something like the following:
SELECT TO_CHAR(TO_DATE('2015/01/22 00:00:00','YYYY/MM/DD HH:MI:SS'), 'YYYY/MM/DD')
FROM dual;
That is, you have the TO_CHAR() and TO_DATE() functions in the wrong order, and an incomplete date mask for the call to TO_DATE().
Try using date literals with the standard ISO 8601 format.
date '2015-01-22'
I suggest you not to give hour-minute-second if you do not want to show the time.
This is my simplest answer :
SELECT TO_DATE('2015/01/22','YYYY/MM/DD') FROM dual