Add numbers within a string in an SQL statement - sql

Question

I have below query of which i would like to modify.
I want to sum all the numbers that occur within a string with the condition that it is joined with the text GB or MB .
If it is in GB it first has to be converted to MB. (This i have done simply by multiplying by 1024)
SELECT /*+ PARALLEL */
'SOME TEXT 20GB+2GB+SOMETEXT' SOMETEXT,
CASE
WHEN REGEXP_SUBSTR('SOME TEXT 20GB+2GB+SOMETEXT','GB',1,1) = 'GB'
THEN 1024*to_number(regexp_replace(REGEXP_SUBSTR('SOME TEXT 20GB+2GB+SOMETEXT','(\d+)GB',1,1), '[^0-9]', ''))
ELSE to_number(regexp_replace(REGEXP_SUBSTR('SOME TEXT 20GB+2GB+SOMETEXT','(\d+)MB',1,1), '[^0-9]', ''))
END TOTAL_MBs
FROM DUAL;
TEST STRINGS
TEXT TEXT_35MB+ MORETEXT
OTHERTEXT 480MB + 3MB AND_TEXT
SOMETEXT 7MB + 7NUMBER
TEXT 1GB AND SOME_TEXT
SOME TEXT 20GB+2GB+SOMETEXT
Here is where i am stuck: To add the numbers that occur more than once in one text
For example:-
For this text OTHERTEXT 480MB + 3MB AND_TEXT I want my result to have 483 as TOTAL_MBS and not 480

Answer 1

Think you are searching for something like:
with da as (
select 1 id, 'TEXT TEXT_35MB+ MORETEXT' tcase from dual
union all select 2 id,'OTHERTEXT 480MB + 3MB AND_TEXT' tcase from dual
union all select 3 id,'SOMETEXT 7MB + 7NUMBER' tcase from dual
union all select 4 id,'TEXT 1GB AND SOME_TEXT' tcase from dual
union all select 5 id,'SOME TEXT 20GB+2GB+SOMETEXT' tcase from dual
union all select 6 id,'SOME TEXT 20MB+2GB+SOMETEXT' tcase from dual
),
split as(
select id
, tcase
, REGEXP_SUBSTR(tcase,'(\d+)(M|G)B',1,level) ot
from da
connect by REGEXP_SUBSTR(tcase,'(\d+)(M|G)B',1,level)is not null
and prior id = id
and PRIOR DBMS_RANDOM.VALUE IS NOT NULL)
select id
, tcase
, sum( case when ot like '%GB%' then 1024 else 1 end * regexp_substr(ot,'\d+')) v
from split
group by id
,tcase
order by id;
Result:
1 TEXT TEXT_35MB+ MORETEXT 35
2 OTHERTEXT 480MB + 3MB AND_TEXT 483
3 SOMETEXT 7MB + 7NUMBER 7
4 TEXT 1GB AND SOME_TEXT 1024
5 SOME TEXT 20GB+2GB+SOMETEXT 22528
6 SOME TEXT 20MB+2GB+SOMETEXT 2068

Answer 2

You can use a recursive sub-query factoring clause:
SELECT sometext,
COALESCE(
REGEXP_SUBSTR( sometext, '(\d+)([MG])B', 1, 1, NULL, 1 )
* CASE REGEXP_SUBSTR( sometext, '(\d+)([MG])B', 1, 1, NULL, 2 )
WHEN 'M' THEN 1
WHEN 'G' THEN 1024
END,
0
),
1,
REGEXP_COUNT( sometext, '(\d+)([MG])B' )
FROM test_data
UNION ALL
SELECT sometext,
total_mb
+ REGEXP_SUBSTR( sometext, '(\d+)([MG])B', 1, i + 1, NULL, 1 )
* CASE REGEXP_SUBSTR( sometext, '(\d+)([MG])B', 1, i + 1, NULL, 2 )
WHEN 'M' THEN 1
WHEN 'G' THEN 1024
END,
i + 1,
num_terms
FROM terms
WHERE i < num_terms
)
SELECT sometext,
total_mb
FROM terms
WHERE i >= num_terms;
which for the test data:
CREATE TABLE test_data ( sometext ) AS
SELECT 'SOME TEXT 20GB+2GB+SOMETEXT' FROM DUAL UNION ALL
SELECT '1MB+1GB+10MB+10GB' FROM DUAL;
outputs:
SOMETEXT | TOTAL_MB
:-------------------------- | -------:
SOME TEXT 20GB+2GB+SOMETEXT | 22528
1MB+1GB+10MB+10GB | 11275
db<>fiddle here

Answer 3

below I used a view/memory table to assign regex function to the specific string and it worked for me
with tbl1 as (
select 1 pd, ' 20GB+2GB sometext +7500 + 45sometext' string from dual
),
tbl2 as(
select pd
, string
, REGEXP_SUBSTR(string,'(\d+)(M|G)B',1,level) string2
from tbl1
connect by REGEXP_SUBSTR(string,'(\d+)(M|G)B',1,level)is not NULL
and prior pd = pd
and PRIOR DBMS_RANDOM.VALUE IS NOT NULL)
select pd
, string
, sum( case when string2 like '%GB%' then 1024 end * regexp_substr(string2,'\d+')) string3
from tbl2
group by pd
,string
order by pd;