How to transform rows into column in SQL Server? - sql

Question

Using MS SQL Server and I have below table:
+-----------+------------------+------------------+---------------------+-------------------------+
| SrNo | ApprCode | ApprName | ApprStatus | ApprDate |
+-----------+------------------+------------------+---------------------+-------------------------+
| SR_176 | X001 | James | APR | 2019-10-03 |
| SR_176 | X002 | Sam | APR | 2019-10-03 |
+-----------+------------------+------------------+---------------------+-------------------------+
Tried with PIVOT but its showing james and X001 as a column heading:
Expected Result:
+-----------+-------------- +---------------+---------------------+-------------------------+------------------+
SrNo | ApprCode_1 | ApprName_1 | ApprDate_2 ApprCode_2 ApprName_2 ApprDate_2
+-----------+---------------+---------------+---------------------+-------------------------+------------------+
SR_176 X001 James 2019-10-03 X002 Sam 2019-10-03
+-----------+---------------+---------------+---------------------+---- ---------------------+------------------+
Query to generate data:
CREATE TABLE #Temp
(
SrNo NVARCHAR(200),
ApprCode NVARCHAR(200),
ApprName NVARCHAR(200),
ApprDate Date
)
INSERT INTO #Temp VALUES ('SR_176','X001','James', '2019-10-03')
INSERT INTO #Temp VALUES ('SR_176','X002','Sam', '2019-10-03')
Query that I tried:
declare #sql nvarchar(max)
declare #name_concat nvarchar(max)
declare #name1_concat nvarchar(max)
declare #select_aggs nvarchar(max)
select #name_concat = STUFF((select distinct ',' + quotename(ApprCode) from #Temp order by 1 for xml path('')), 1, 1, '')
select #name1_concat = STUFF((select distinct ',' + quotename(ApprName) from #Temp order by 1 for xml path('')), 1, 1, '')
select #sql = '
;with cte2 as
(
SELECT SrNo,' + #name_concat + ',' + #name1_concat + '
FROM #Temp
PIVOT(MAX(ApprCode)
FOR ApprCode IN (' + #name_concat + ')) AS PVTTable PIVOT
(
MAX(ApprName)
FOR ApprName IN (' + #name1_concat + ')) AS PVTTable1
)
select * from cte2
'
exec sp_executesql #sql

Answer 1

In fact, This is not a SQL Pivot situation and the sample data for question is not enough to test it completely but you can find the main idea :
Select
SrNo,
MAX(IIF(ApprCode = 'X001', ApprCode, null)) as ApprCode_1,
MAX(IIF(ApprCode = 'X001', ApprName, null)) as ApprName_1,
MAX(IIF(ApprCode = 'X001', ApprDate, null)) as ApprDate_1,
MAX(IIF(ApprCode = 'X002', ApprCode, null)) as ApprCode_2,
MAX(IIF(ApprCode = 'X002', ApprName, null)) as ApprName_2,
MAX(IIF(ApprCode = 'X002', ApprDate, null)) as ApprDate_2
From #Temp
Group by SrNo
This code works if ApprCode was the key to make two separate columns & SrNo is for the group by between rows.

Answer 2

I solved it by using ROW_NUMBER() and Case Expression:
Here is the query:
SELECT *,
Row_number()
OVER(
partition BY srno
ORDER BY apprdate) AS RN
INTO #temptable
FROM #temp
SELECT srno,
CASE rn
WHEN 1 THEN Max(apprname)
END AS [1 Approver],
CASE rn
WHEN 2 THEN Max(apprname)
END AS [2 Approver],
CASE rn
WHEN 1 THEN Max(apprcode)
END AS [1 ApproverCode],
CASE rn
WHEN 2 THEN Max(apprcode)
END AS [2 ApproverCode],
CASE rn
WHEN 1 THEN Max(apprdate)
END AS [1 Date],
CASE rn
WHEN 2 THEN Max(apprdate)
END AS [2 Date]
INTO #james
FROM #temptable
GROUP BY srno,
rn
SELECT srno,
Max([1 approver]) AS ApproverName_1,
Max([1 approvercode]) AS ApproverCode_1,
Max([1 date]) AS ApproverDate_1,
Max([2 approver]) AS ApproverName_2,
Max([2 approvercode]) AS ApproverCode_2,
Max([2 date]) AS ApproverDate_2
FROM #james
GROUP BY srno