I am new to BigQuery and am trying to convert numeric values (from Salesforce) to currency (preferably dollar value).
Very basically, what I have currently is:
SELECT salesforce.Name,
ROUND(salesforce.Amount,2) as Amount
FROM table.salesforce
Which obviously only rounds the value to two decimal places.
Regarding your question about how to convert a numeric value to currency value in BigQuery, I would advise you to use the FORMAT() and CONCAT() built-in functions.
I see that in your question you mentioned you want to round the numeric values to the second decimal place, you can do that using FORMAT(), you can read more about it here. In addition, to use the "$" sign, you can use CONCAT(). Below is an example where I used some dummy data to exemplify what I explained:
WITH
data AS (
SELECT
20.21 AS num
UNION ALL
SELECT
99999999.12 AS num
UNION ALL
SELECT
12345 AS num )
SELECT
CONCAT('$ ',FORMAT("%'.2f", num)) AS new_num
FROM
data
And the output:
Notice that in the FORMAT() function I used "%'.2f", which rounds the number to the second decimal place. You can find more information about the meaning of each letter/number in the expression using the following guide.
As a bonus information, the currency values are formatted in a way that the dot "." is a decimal separator and the comma "," is a grouping separator. You can switch that using regex expressions with REGEX_REPLACE() and REPLACE() functions. If that is the case, just let me know so I can help.
This is the method that I use:
CAST(YourNumber AS STRING FORMAT '$999,999')
With decimal points:
CAST(YourNumber AS STRING FORMAT '$999,999.00')
Related
I have a column that is in INT type. I want to remove all the trailing zeroes and only have the number. The example below, should follow be: 3,10,20,20. I cannot have the 4 zeroes at the end.
Is there a way to do this?
You could try casting your numeric data to integer, e.g.
SELECT AS_INTEGER(col) AS col
FROM yourTable;
the 3dp is how floating point numbers print, thus you can cast to number SELECT column_name::number FROM table
If your data is a string/varient type, and not all values stored in your column always casts cleanly, in Snowflake you can hit error, with the TO_NUMBER or ::number forms, thus [TRY_TO_NUMBER][2] form should be used.
I have a decimal field (19,4) in teradata and I need it in a specific format:
group separator as the point
decimal character as the comma
only two decimal digits
integer part of the number must be grouped 3 by 3
I have already tried FORMAT, TO_CHAR and CAST functions. I have also tried NLS_NUMERIC_CHARACTERS parameter in those functions. I think I am missing some rationale in TERADATA SQL, I'll appreciate some help.
The idea is very simple:
SELECT some_decimal_field_in_proper_format_described_above
FROM some_table
For CAST/FORMAT the group separator and decimal separator are determined by the SDF "locale" for your system. But if you want something different you can use TO_CHAR with D for the decimal and G for the group separator in the format string and custom values for NUMERIC_CHARACTERS:
TO_CHAR(x,'S999G999G999G999G990D99','NLS_NUMERIC_CHARACTERS = '',.''')
I'm trying to convert a number to a decimal with two decimals places.
SELECT CONVERT(DECIMAL(10,2),12345)
The above would return 12345.00 but I'm trying to achieve 123.45
You need something like that:
SELECT CONVERT(DECIMAL(15,2),12345/100.0)
SELECT CONVERT(DECIMAL(10,2),CAST(12345 as float)/CAST(100 as float))
Correction: The premise is somewhat flawed, as the data type of a literal number without a decimal point is int, not numeric as implied by the question. In that case, you do need to convert the initial value to either numeric or decimal before dividing:
SELECT CONVERT(DECIMAL,12345)/100
or
SELECT CAST(12345 AS DECIMAL)/100
(cast is the SQL standard, so if you ever want to apply this to other databases, it would be the preferred method.)
Alternately, you can just add a decimal point to the divisor, as SQL server will return the more precise data type when doing arithmetic on heterogeneous types:
SELECT 12345/100.0
According to the documentation, the numeric data type is functionally equivalent to the decimal datatype, so there's really no reason to convert between the two. It seems that all you really want to do is divide the value you have by 100:
SELECT 12345/100
I am using Sybase and I am doing a select which returns me a column called "iftype", but its type is int and I need to convert into varchar. When I try to do the select without the convert function I get this error:
Error code 257, SQL state 37000: Implicit conversion from datatype 'VARCHAR' to 'INT' is not allowed. Use the CONVERT function to run this query.
I dont know how to implement the function CONVERT. Can anyone help me, please ?
Use the convert function.
SELECT CONVERT(varchar(10), field_name) FROM table_name
Use the STR function:
SELECT STR(field_name) FROM table_name
Arguments
float_expression
Is an expression of approximate numeric (float) data type with a decimal point.
length
Is the total length. This includes decimal point, sign, digits, and spaces. The default is 10.
decimal
Is the number of places to the right of the decimal point. decimal must be less than or equal to 16. If decimal is more than 16 then the result is truncated to sixteen places to the right of the decimal point.
source: https://msdn.microsoft.com/en-us/library/ms189527.aspx
You can use CAST function:
SELECT CAST(your_column_name AS varchar(10)) FROM your_table_name
Actually you don't need to use STR Or Convert. Just select 'xxx'+LTRIM(ColumnName) does the job.
Possibly, LTRIM uses Convert or STR under the hood.
LTRIM also removes need for providing length. It seems to be working for integer or float without worry of truncation.
SELECT LTRIM(ColumnName) FROM TableName
also, LTRIM is better than STR as
SELECT STR(1234567890.123)
gives 1234567890
whereas
SELECT LTRIM(1234567890.123)
gives 1234567890.123
SELECT Cast(Cast([field_name] AS BIGINT) AS NVARCHAR(255))
FROM table_name
CONVERT(DATA_TYPE , Your_Column) is the syntax for CONVERT method in SQL. From this convert function we can convert the data of the Column which is on the right side of the comma (,) to the data type in the left side of the comma (,) Please see below example.
SELECT CONVERT (VARCHAR(10), ColumnName) FROM TableName
I have a column in my table which showing an amount. The amount is varying from one column to another and they are more than 15 digits.
What is the best way to format the number to show commas and decimal points?
My query is
select amount from ccamounts
How can I format the number
205511892078
to show as
205,511,892,078
and if there is a radix point it will also appear.
I believe you can use TO_CHAR to do this, the issue is that this is just a formatting function within SQL. It requires that your number is always going to be in the same format.
taking the example above you could do
TO_CHAR('205511892078', '999,999,999,999')
and this would format the number as you have specified, with a decimal place this can be done aswell but the decimal needs to be specified:
TO_CHAR('20551189207842', '999,999,999,999.99')
which would give you 205,511,892,078.42
I think if the field length is going to vary sql will just ignore anything that doesn't fit into the format string (It's a mask). Perhaps you want to consider formatting the number in this case on whichever front end you may be using?
I would format the number in the UI / Reporting tool / Presentation layer not Oracle
but if you MUST format it in oracle try:
SELECT
CASE WHEN INSTR( TO_CHAR(205511892078),'.')>0 THEN
TO_CHAR(205511892078 ,'999,999,999,999.99')
ELSE
TO_CHAR(205511892078 ,'999,999,999,999')
END
FROM DUAL
this will return the number as a string.
declare #d3 decimal (10, 2)
set #d3 = 12309809.5494
SELECT convert(varchar(15),cast(CAST(ROUND(#d3,2,1) AS DECIMAL (30,2)) as money),1) as Value
SELECT CAST(ROUND(convert(varchar(30), cast(#d3 as money),2),2,1) AS DECIMAL (30,2)) as Value
Output:
12,309,809.55
12309809.55